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以下に示す配列があります。キー要素[tv], [tu],[cost]の[km]値が の同じ値を持つすべての行に対して合計される結果の配列が必要です[tick_id]。この例では、配列要素 0、1、2、… の値 、 、 を合計する必要があり[tv]ます[tu]。[cost][km]

Array (
    [0] => stdClass Object (
        [id] => 15
        [user_id] => 44
        [name] => inspector1
        [tv] => 0.00
        [tc] => 0.00
        [tu] => 0.00
        [cost] => 0.00
        [kms] => 0
        [date_s] => 2012-03-30
        [notes] =>
        [tick_id] => 11
        [tot_fee] => 5500
    )
    [1] => stdClass Object (
        [id] => 39
        [user_id] => 46
        [name] => Assistant
        [tv] => 10.00
        [tc] => 0.00
        [tu] => 4.50
        [cost] => 0.00
        [kms] => 120
        [date_s] => 2012-03-31
        [notes] =>
        [tick_id] => 15
        [tot_fee] => 0
     )
    [2] => stdClass Object (
        [id] => 35
        [user_id] => 46
        [name] =>
        [tv] => 0.00
        [tc] => 0.00
        [tu] => 0.00
        [cost] => 0.00
        [kms] => 0
        [date_s] => 2012-03-30
        [notes] =>
        [tick_id] => 13
        [tot_fee] => 3200
    )
    …
)
4

1 に答える 1

1

コードがどのように表示されているかを伝えるのは難しいですが、これは必要なものです。

// Create the cost total array
$cost = array();

// Iterate over each object in the given array
foreach ($array as $object)
{

  // If the tick_id has not yet been assigned as a key then do so with a default cost of 0
  if (!isset($cost[$object->tick_id]))
  {
    $cost[$object->tick_id] = 0;
  }

  // Increment the total cost for the given tick_id
  $cost[$object->tick_id] += $object->tv + $object->km + $object->tu + $object->cost;

}

$costが で、keyが総コストの配列になります。tick_idvalue

于 2012-04-04T07:45:44.167 に答える