25

データベースにこのようなテーブルがあります (SQL Server 2008)

ID      Type            Desc
--------------------------------
C-0 Assets          No damage
C-0 Environment     No impact
C-0 People          No injury or health effect
C-0 Reputation      No impact
C-1 Assets          Slight damage
C-1 Environment     Slight environmental damage
C-1 People          First Aid Case (FAC)
C-1 Reputation      Slight impact; Compaints from local community

Assets、People、Environment、および Reputation を列として表示し、一致する Desc を値として表示する必要があります。しかし、ピボット クエリを実行すると、すべての値が null になります。

誰かが私のクエリを調べて、どこが間違っているのか教えてもらえますか?

Select severity_id,pt.[1] As People, [2] as Assets , [3] as Env, [4] as Rep
FROM 
(
    select * from COMM.Consequence
) As Temp
PIVOT
(
    max([DESCRIPTION]) 
    FOR [TYPE] In([1], [2], [3], [4])
) As pt

これが私の出力です

ID  People  Assets   Env     Rep
-----------------------------------
C-0 NULL    NULL    NULL    NULL
C-1 NULL    NULL    NULL    NULL
C-2 NULL    NULL    NULL    NULL
C-3 NULL    NULL    NULL    NULL
C-4 NULL    NULL    NULL    NULL
C-5 NULL    NULL    NULL    NULL
4

2 に答える 2

35 
Select severity_id, pt.People, Assets, Environment, Reputation
FROM 
(
    select * from COMM.Consequence
) As Temp
PIVOT
(
    max([DESCRIPTION]) 
    FOR [TYPE] In([People], [Assets], [Environment], [Reputation])
) As pt
于 2012-04-05T09:27:41.993 に答える