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一部のデータのカウントを返すクエリがありますが、null 値を含むデータは必要ありません...

例として、コードは統計情報をクリック システムからテーブルにロールします。

SELECT sh.dropid,
COUNT(DISTINCT IF(sh2.`SentDate` IS NOT NULL, sh2.`subid`, NULL)) AS sentCount,
COUNT(DISTINCT IF(sh2.`Open` = 1, sh2.`subid`, NULL)) AS openCount,
COUNT(DISTINCT IF(sh2.`Click` = 1, sh2.`subhistid`, NULL)) AS clickCount,
COUNT(DISTINCT IF(sh2.`Bounced` = 1, sh2.`subid`, NULL)) AS bounceCount,
COUNT(DISTINCT IF(sh2.`Unsubscribed` = 1, sh2.`subid`, NULL)) AS unsubCount,
COUNT(DISTINCT IF(sh2.`Abuse` = 1, sh2.`subid`, NULL)) AS abuseCount
FROM subscriberhistory sh
INNER JOIN subscriberhistory sh2 ON sh.subid = sh2.subid
WHERE sh.SentDate >= '#runDate# #lastRunTime#'
AND sh.dropid IS NOT NULL
AND sh.dropid != ""
OR (sh.SentDate IS NULL AND sh.OpenDate >= '#runDate# #lastRunTime#')
OR (sh.SentDate IS NULL AND sh.ClickDate >= '#runDate# #lastRunTime#')
OR (sh.SentDate IS NULL AND sh.UnsubscribeDate >= '#runDate# #lastRunTime#')
OR (sh.SentDate IS NULL AND sh.BouncedDate >= '#runDate# #lastRunTime#')
OR (sh.SentDate IS NULL AND sh.AbuseDate >= '#runDate# #lastRunTime#')
GROUP BY dropid
ORDER BY sentCount DESC

編集: 修正されたクエリ

SELECT sh.dropid,
COUNT(DISTINCT IF(sh2.`SentDate` IS NOT NULL, sh2.`subid`, NULL)) AS sentCount,
COUNT(DISTINCT IF(sh2.`Open` = 1, sh2.`subid`, NULL)) AS openCount,
COUNT(DISTINCT IF(sh2.`Click` = 1, sh2.`subid`, NULL)) AS clickCount,
COUNT(DISTINCT IF(sh2.`Bounced` = 1, sh2.`subid`, NULL)) AS bounceCount,  
COUNT(DISTINCT IF(sh2.`Unsubscribed` = 1, sh2.`subid`, NULL)) AS unsubCount,
COUNT(DISTINCT IF(sh2.`Abuse` = 1, sh2.`subid`, NULL)) AS abuseCount
FROM subscriberhistory sh
INNER JOIN subscriberhistory sh2 ON sh.subid = sh2.subid
WHERE sh.dropid IS NOT NULL AND sh.dropid != ""
AND ((sh.SentDate >= '2012-04-10 14:15') 
OR (sh.SentDate IS NULL AND sh.OpenDate >= '2012-04-10 14:15')
OR (sh.SentDate IS NULL AND sh.ClickDate >= '2012-04-10 14:15')
OR (sh.SentDate IS NULL AND sh.UnsubscribeDate >= '2012-04-10 14:15')
OR (sh.SentDate IS NULL AND sh.BouncedDate >= '2012-04-10 14:15')
OR (sh.SentDate IS NULL AND sh.AbuseDate >= '2012-04-10 14:15'))
GROUP BY sh.dropid
ORDER BY sentCount DESC

返されるレコード セットの例は次のようになります...

(dropid) sent opens  clicks
400      2    3      4
401      2    3      6
NULL     2    3      4

繰り返しますが、目標は、前のレコード セットから NULL データを除外することです。この動作が発生する理由と、それを解決するために何をすべきかを誰かに説明してもらえますか?

4

1 に答える 1

1

私のコメントで述べたように、ステートメントの条件をNULL介して行が忍び寄っています。ORWHERE

検討：

WHERE sh.dropid IS NOT NULL
AND   sh.dropid != ""
OR    ( some.other.condition )

NULL であるが、sh.dropidそれでも満足できる行があるとします。some.other.conditionWHERETRUEOR

解決策 - ブラケットを追加します。例（あなたが求めているロジックに依存します）：

WHERE sh.dropid IS NOT NULL
  AND sh.dropid != ""
  AND (   one.condition
       OR second.condition
       OR third.condition
       )
于 2012-04-11T00:00:23.417 に答える