このURLから xml データを解析したい
私はこのようなコードを書いていました:-
NSString *escapedURL = @"http://www.google.com/ig/api?weather=%22Dr%20Vikram%20Sarabhai%20Marg%20Panchavati%20Society%20Gulabai%20Tekra%20Ahmedabad%20Gujarat%20India%22&hl=hr";
xmlParser = [[NSXMLParser alloc] initWithContentsOfURL:[NSURL URLWithString:escapedURL]];;
[xmlParser setDelegate:self];
[xmlParser setShouldProcessNamespaces:NO];
[xmlParser setShouldReportNamespacePrefixes:NO];
[xmlParser setShouldResolveExternalEntities:NO];
[xmlParser parse];
- (void)parserDidStartDocument:(NSXMLParser *)parser
{
NSLog(@"Document started", nil);
currentElement = nil;
}
- (void)parser:(NSXMLParser *)parser parseErrorOccurred:(NSError *)parseError
{
NSLog(@"Error: %@", [parseError localizedDescription]);
}
- (void)parser:(NSXMLParser *)parser didStartElement:(NSString *)elementName
namespaceURI:(NSString *)namespaceURI
qualifiedName:(NSString *)qName
attributes:(NSDictionary *)attributeDict
{
[currentElement release];
currentElement = [elementName copy];
currentName = [[NSMutableString alloc] init];
//For temeprature
if ([currentElement isEqualToString:@"forecast_information"])
{
}
else if ([currentElement isEqualToString:@"current_conditions"])
{
}
else if ([currentElement isEqualToString:@"temp_c"])
{
//NSLog(@"attributeDict==>%@",[attributeDict objectForKey:@"data"]);
LblTemperature.text=[NSString stringWithFormat:@"Ahmedabad %@°",[attributeDict objectForKey:@"data"]];
}
}
- (void)parser:(NSXMLParser *)parser didEndElement:(NSString *)elementName
namespaceURI:(NSString *)namespaceURI
qualifiedName:(NSString *)qName
{
if ([elementName isEqualToString:@"temp_c"])
{
//NSLog(@"temp_c: %@", currentName);
}
}
- (void)parser:(NSXMLParser *)parser foundCharacters:(NSString *)string
{
if ([currentElement isEqualToString:@"temp_c"])
{
[currentName appendString:string];
//NSLog(@"==>%@",string);
}
}
- (void)parserDidEndDocument:(NSXMLParser *)parser
{
NSLog(@"Document finished");
}
しかし、この解析では temp_c のデータを取得できません。私が取得している要素名は次のとおりです。
私を助けてください..