3

NSDate が今週か来週かを確認する方法はありますか?

私は今日が次のことを知っています：

[NSDate date]

そして、どうすればいいですか？

4

7 に答える 7

6

次のようなNSDateComponentsを使用します。

NSCalendar *gregorian = [[NSCalendar alloc]
    initWithCalendarIdentifier:NSGregorianCalendar];
    NSDate *today = [NSDate date];

    NSDateComponents *todaysComponents =
        [gregorian components:NSWeekCalendarUnit fromDate:date];

    NSUInteger todaysWeek = [todaysComponents week];


    NSDate *anotherDate = [NSDate date];

    NSDateComponents *otherComponents =
        [gregorian components:NSWeekCalendarUnit fromDate:anotherDate];

    NSUInteger anotherWeek = [otherComponents week];

    if(todaysWeek==anotherWeek){
         NSLog(@"another date is this week");
    }else if(todaysWeek+1==anotherWeek){
         NSLog(@"another date is next week")
    }

完全に確認するために、月や年などの他のコンポーネントを使用することもできます。

注：timeIntervalsは使用しないでください。NSDateComponentsを使用すると、時、分、秒を無視します。私はあなたがそれを望んでいると思います。

于 2012-04-13T15:45:03.613 に答える
2

2 つの日付をこのメソッドに渡します。

- (BOOL) isSameWeekAsDate: (NSDate *) aDate andDate:(NSDate *) bDate
{
    NSDateComponents *components1 = [[NSCalendar currentCalendar] components:(NSYearCalendarUnit| NSMonthCalendarUnit | NSDayCalendarUnit | NSWeekCalendarUnit |  NSHourCalendarUnit | NSMinuteCalendarUnit | NSSecondCalendarUnit | NSWeekdayCalendarUnit | NSWeekdayOrdinalCalendarUnit) fromDate:aDate];
    NSDateComponents *components2 = [[NSCalendar currentCalendar] components:(NSYearCalendarUnit| NSMonthCalendarUnit | NSDayCalendarUnit | NSWeekCalendarUnit |  NSHourCalendarUnit | NSMinuteCalendarUnit | NSSecondCalendarUnit | NSWeekdayCalendarUnit | NSWeekdayOrdinalCalendarUnit) fromDate:bDate];

    if ([components1 week] != [components2 week]) return NO;

    //return (abs([self timeIntervalSinceDate:aDate]) < 604800); // ops, forgot to change "self" with parameter "bDate":
    return (abs([bDate timeIntervalSinceDate:aDate]) < 604800);
}

編集: 異なる年の2つの日付で呼び出します:

[components setDay:31];
[components setMonth:12];
[components setYear:2010];
NSCalendar *gregorian = [[NSCalendar alloc]  initWithCalendarIdentifier:NSGregorianCalendar];
NSDate *date1 = [gregorian dateFromComponents:components];

// second date (SATURDAY -of the same week, other year...)
[components setDay:1];
[components setMonth:1];
[components setYear:2011];
NSDate *date2 = [gregorian dateFromComponents:components];

if ([self isSameWeekAsDate:date1 andDate:date2]) {
    NSLog(@"Same Week!");
}else{
    NSLog(@"OTHER WEEK!");
}
于 2012-04-13T15:40:44.713 に答える
1

iOS7、iOS8で廃止された週を使用しないソリューション（NSDateカテゴリとして実装）を追加しています

- (NSDate *)firstDateOfWeek {
    NSCalendar *calendar = [NSCalendar currentCalendar];
    NSDate *startOfWeek;
    [calendar rangeOfUnit:NSCalendarUnitWeekOfYear startDate:&startOfWeek interval:NULL forDate:self];
    return startOfWeek;
}

- (BOOL)isSameWeekWithDate:(NSDate *)date {
    if (ABS(self.timeIntervalSince1970 - date.timeIntervalSince1970) > (7 * 24 * 60 * 60)) {
        return NO;
    }    
    return ([[self firstDateOfWeek] timeIntervalSince1970] == [[date firstDateOfWeek] timeIntervalSince1970]);
}

- (BOOL)isThisWeek {
    return [self isSameWeekWithDate:[NSDate new]];
}
于 2014-09-23T12:53:17.677 に答える
0 
NSCalendar *cal = [NSCalendar currentCalendar];
NSDateComponents *components = [cal components:NSWeekCalendarUnit fromDate:yourDate];
NSInteger week = [components week]; // here your have a Integer with the weeknr of yourDate

components = [cal components:NSWeekCalendarUnit fromDate:[NSDate date]];
weekToday = [components week]; // here your have a Integer with the weeknr of today

あなたができるはずの残りの部分。年の最後の週になると、別の頭脳を働かせるかもしれません。

クリア？

于 2012-04-13T15:36:17.877 に答える
0

注: これは、日曜日と土曜日の週の概念を使用して「週」の概念を計算します。

現在の曜日を計算するには、ここから次を使用します。

NSCalendar *gregorian = [[NSCalendar alloc]  initWithCalendarIdentifier:NSGregorianCalendar];

NSDateComponents *weekdayComponents =[gregorian components:NSWeekdayCalendarUnit fromDate:dateOfInterest];

NSInteger weekday = [weekdayComponents weekday];
// weekday 1 = Sunday for Gregorian calendar

[gregorian release];

残りはかなり些細なことです。NSDate から現在の日付と日付を取得します。曜日と日付を使用して開始日と終了日を見つけます (今日が月曜日の場合date - 1 dayは、週の最初の日など)。日付が何週目かを割り出します。

于 2012-04-13T15:36:54.120 に答える
0

iOS 7 以降では、次のものに置き換える必要がありますNSWeekCalendarUnit。NSCalendarUnitWeekOfYear 

- (NSInteger)thisW:(NSDate *)date
{
    NSCalendar *gregorian = [[NSCalendar alloc]
                             initWithCalendarIdentifier:NSGregorianCalendar];
    NSDateComponents *todaysComponents = [gregorian components:NSCalendarUnitWeekOfYear fromDate:[NSDate date]];
    NSUInteger todaysWeek = [todaysComponents weekOfYear];
    NSDateComponents *otherComponents = [gregorian components:NSCalendarUnitWeekOfYear fromDate:date];
    NSUInteger datesWeek = [otherComponents weekOfYear];

    //NSLog(@"Date %@",date);
    if(todaysWeek==datesWeek){
        //NSLog(@"Date is in this week");
        return 1;
    }else if(todaysWeek+1==datesWeek){
        //NSLog(@"Date is in next week");
        return 2;
    } else {
        return 0;
    }

}
于 2016-08-17T02:18:25.473 に答える