だから私は今のところ開発者のために記入しています（注意してください-私は初心者です）が、私は単にプロフィール写真が含まれているプロフィールで検索結果を並べ替えようとしています（つまり、私はしたくない結果の上部に表示される空白のプロフィール写真...すべて結果の最後に表示されるはずです）...いくつかのユーザータイプがあることに注意してください。これが、コードが非常に多い理由です...
私が間違っているのは2行だとかなり確信しています...
ORDER BY $ order u.picture ISNULL DESC ";（プロフィール写真による注文に関連します）。すべての助けに本当に感謝します... thx！
コードは次のとおりです。
if ($user_type == 1) {
$sql = "SELECT a.*, u.*,
(SELECT COUNT(DISTINCT userId) FROM LF_usertype_A WHERE usertype_BId = u.userId AND status = 1) as i_cnt,
(SELECT COUNT(productId) FROM LF_products WHERE userId = u.userId AND status = 1) as product_cnt,
(SELECT COUNT(transactionId)
FROM LF_Transactions
WHERE usertypeBId = u.userId
AND (status = 1 OR status = 2)
AND type = 9
AND userId != usertypeBId
AND userId != usertypeAId) AS cnt
FROM LF_Users u
JOIN LF_products a ON a.userId = u.userId
LEFT JOIN LF_Transactions t ON t.productId = a.productId
WHERE a.status = 1
AND u.status = 1
AND u.userType = :ut $where
GROUP BY u.userID
ORDER BY $order u.name DESC LIMIT 200";
} elseif ($filter != "recent" && $user_type == 2) {
$sql = "SELECT u.*,
(SELECT COUNT(a.productId) FROM LF_usertypeA a INNER JOIN LF_products ON a.productId = m.productId INNER JOIN LF_Users uu ON uu.userId = a.usertypeAId WHERE a.userId = u.userId AND uu.status = 1 AND a.status = 1 AND m.status = 1) as product_cnt,
(SELECT COUNT(transactionId)
FROM LF_Transactions
WHERE usertypeBId = u.userId
AND (status = 1 OR status = 2)
AND type = 9
AND userId != usertypeAId
AND userId != usertypeBId) AS cnt
FROM LF_Users u
LEFT JOIN LF_Transactions t ON t.usertypeBId = u.userId
WHERE u.status = 1
AND u.userId != 1
AND u.userType = :ut $where
GROUP BY u.userID
ORDER BY $order u.name DESC LIMIT 200
ORDER BY $order u.picture ISNULL DESC";
} else {
$sql = "SELECT u.*,
(SELECT COUNT(a.productId) FROM LF_usertype_A a INNER JOIN LF_products m ON a.productId = m.productId INNER JOIN LF_Users uu ON uu.userId = a.usertypeAId WHERE a.userId = u.userId AND uu.status = 1 AND a.status = 1 AND m.status = 1) as product_cnt,
(SELECT COUNT(transactionId)
FROM LF_Transactions
WHERE usertypeBId = u.userId
AND (status = 1 OR status = 2)
AND type = 9
AND userId != usertypeAId
AND userId != usertypeBId) AS cnt
FROM LF_Users u
WHERE u.status = 1
AND u.userId != 1
AND u.userType = :ut $where
GROUP BY u.userID
ORDER BY $order u.name DESC LIMIT 200
ORDER BY $order u.picture ISNULL DESC";
}