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通常、T_String エラーは、余分な引用符がある場合、または少なくとも私が考えた場合です。今夜、私はこのエラーを受け取りました

Parse error: syntax error, unexpected T_STRING in /var/www/html/registerBackend.php on line 118

これが118 + 119行目のコードです 

$query = "INSERT INTO User (Name,Email,Password,Port) VALUES ('$name', '$email','$password','$port')";
mysql_query($query) or die('Error, insert query failed');

それが役立つ場合は、ここにいくつかのコードがあります

 $conn = mysql_connect($dbhost, $dbuser, $dbpass) or die ('Error connecting to mysql');

 $dbname ='hidden';
mysql_select_db($dbname);

//Check if Username has been used before
$query = "SELECT * FROM User where Name='$name'";
$result=mysql_query($query) or die('Error, insert query failed');
$countName=mysql_num_rows($result);

//Check if email has been used before
$query = "SELECT * FROM User where Email='$email'";
$result=mysql_query($query) or die('Error, insert query failed');
$countEmail=mysql_num_rows($result);

if($countName < 1 && $countEmail < 1){

//Assign their port number
$query  = "SELECT *  FROM login;
$countPort=mysql_num_rows($result);
$port = 20000 + $countPort;


$query = "INSERT INTO User (Name,Email,Password,Port) VALUES ('$name', '$email','$password','$port')";
mysql_query($query) or die('Error, insert query failed');


$query  = "SELECT username, password FROM login WHERE username = '$username' AND password = '$password'";
$result = mysql_query($query);

print "<center><div id=newAREA>You have been signed up!<br>";
while($row = mysql_fetch_array($result, MYSQL_ASSOC)){
  echo "Minecraft Username:{$row['Name']} <br>" .
       "Email:{$row['Email']} <br>" .
       "Password:{$row['Password']} <br>".
       "Port:{$row['Port']} <br>";

}
} elseif ($countName > 1) {
print "Someone has already used this Minecraft IGN! E-mail Stolen@freeminecrafthost.com   to prove it is yours!";
} elseif ($countEmail > 1) {
print "Email has been used before!";
}
4

3 に答える 3

2

試す

$query = "INSERT INTO User (Name,Email,Password,Port) VALUES ('" . mysql_real_escape_string($name) . "', '" . mysql_real_escape_string($email) . "','" . mysql_real_escape_string($password) . "','" . mysql_real_escape_string($port) . "')";
mysql_query($query) or die('Error, insert query failed');


アップデート

この行

$query  = "SELECT *  FROM login;

する必要があります

$query  = "SELECT *  FROM login";
于 2012-04-22T02:57:30.907 に答える
1 
//Assign their port number
$query  = "SELECT *  FROM login;
$countPort=mysql_num_rows($result);
$port = 20000 + $countPort;

の後に引用符がありませんlogin。

$query  = "SELECT *  FROM login";

ほめたたえましょう、シンタックスハイライト！

于 2012-04-22T02:59:34.243 に答える
0

オンライン:

$query  = "SELECT *  FROM login;

あなたが持っている必要があります：

$query  = "SELECT *  FROM login";

しかし、これらのクエリにも愛情を与える必要があることは間違いありません。

于 2012-04-22T02:58:15.723 に答える