2 
LowKeys = dict(La = 'z', Lb = 'x', Lc = 'c', Ld = 'v', Le = 'b', Lf = 'n', Lg = 'm')
MidKeys = dict(Ma = 'q', Mb = 'w', Mc = 'e', Md = 'r', Me = 't', Mf = 'y', Mg = 'u')
HighKeys = dict(Ha = 'i', Hb = 'o', Hc = 'p', Hd = '[', He = ']')
SharpLowKeys = dict(SLa = 's', SLc = 'f', SLd = 'g', SLf = 'j', SLg = 'k') 
FlatLowKeys = dict(FLa = 'a', FLb = 's', FLd = 'f', FLe = 'g', FLg = 'j') 
SharpMidKeys = dict(SMa = '2', SMc = '4', SMd = '5', SMf = '7', SMg = '8')
FlatMidKeys = dict(FMa = '1', FMb = '2', FMd = '4', FMe = '5', FMg = '7')
SharpHighKeys = dict(SHa = '9', SHc = '-', SHd = '=')
FlatHighKeys = dict(FHa = '8', FHb = '9', FHd = '-', FHe = '=')

notes = raw_input('Notes: ')
notes = notes.split()

メモとの両方に表示されるすべての項目を値に置き換えたいと思いdictsますdict。

元：

notes = La, Ha, Lb
notes = z, i, x

これを行う方法はありますか？または私が試しているものよりも良い方法ですか？

4

2 に答える 2

3 
allKeys = {}
for subdict in (LowKeys, MidKeys, ..., FlatHighKeys):
    allKeys.update(subdict)

notes = [allKeys[note] for note in notes]
于 2012-04-23T01:33:26.493 に答える
1

dictのすべての内容を1つの大きなdictに入れ、リスト内包表記を使用してdictから適切な値を引き出します。

于 2012-04-23T01:18:40.153 に答える