3

最初の親が null であるクエリが必要です。前の親の子は、次の親になります。 

WITH RESULT (PARENT,CHILD,TNAME,LEVEL)
AS
(
--anchor
 SELECT E.PARENT_GENERAL_KEY,E.M_GENERAL_KEY,E.NAME ,0 AS LEVEL
  FROM RPT_SYN_M_GENERAL AS E 
 WHERE E.PARENT_GENERAL_KEY IS NULL
 UNION ALL
 --outer
 SELECT e.PARENT_GENERAL_KEY,E.M_GENERAL_KEY,e.NAME ,LEVEL +1
 FROM RPT_SYN_M_GENERAL AS E
 INNER JOIN RESULT AS D  
 ON E.PARENT_GENERAL_KEY=D.CHILD 
)
SELECT PARENT,CHILD,TNAME,LEVEL FROM RESULT as d
order by PARENT,CHILD

上記は私の質問です。最後の子を繰り返すのを手伝ってください。

私が持っている出力は次のとおりです。

 PARENT CHILD   TNAME               LEVEL
  NULL  0       ACCOUNT_MASTER        0
   0    1       LIABILITIES           1
   0    2       ASSETS                1
   0    3       INCOME                1
   0    4       EXPENSE               1
   0    15003   POLISHED DIAMOND      1
   0    15004   DEMO                  1
   0    15005   DEMO ( FACTORY        1
   1    238     CAPITAL A/C.          2
   1    1067    PROVISION             2
   1    1284    SECURED LOANS         2 
   1    2968    UNSECURED LOANS       2
   1    3535    SHARE HOLDERS         2
   2    484     FIXED ASSETS A/C      2
   2    3301    INVESTMENTS           2
   2    4858    CURRENT ASSETS        2
   2    4859    LOANS ADVANCES        2
   3    867     OTHER INCOME          2
   3    1246    SALES                 2

私が望む出力は次のとおりです。

 PARENT      CHILD  TNAME             LEVEL
   null      0                          0
    0        1                          1 
    1        238                        2
   238       982                        3
   982       26                         4
   982       894                        4        
   982       1321                       4
   238       7757                       3
   7757      7521                       4
4

2 に答える 2

0

指定する出力では、CTEの行をランク付けする必要があります。次に、各反復でランク付けされた行をフィルタリングするだけです。

WITH RESULT (ROW_RANK, PARENT,CHILD,TNAME,[LEVEL])
AS
(
--anchor
 SELECT RANK() OVER (ORDER BY E.M_GENERAL_KEY), E.PARENT_GENERAL_KEY,E.M_GENERAL_KEY,E.NAME ,0 AS [LEVEL]
  FROM RPT_SYN_M_GENERAL AS E 
 WHERE E.PARENT_GENERAL_KEY IS NULL
 UNION ALL
 --outer
 SELECT RANK() OVER (ORDER BY E.M_GENERAL_KEY), E.PARENT_GENERAL_KEY,E.M_GENERAL_KEY,E.NAME, D.[LEVEL] +1 
 FROM RPT_SYN_M_GENERAL AS E
 INNER JOIN RESULT AS D  
 ON E.PARENT_GENERAL_KEY=D.CHILD AND ROW_RANK = 1
)
SELECT PARENT,CHILD,TNAME,LEVEL FROM RESULT as d
WHERE ROW_RANK = 1
order by PARENT,CHILD
于 2012-12-12T05:47:56.717 に答える
0

基になるテーブルが表示されないと、提案をテストできません。ただし、外側のクエリで親と子を切り替えるとどうなるかを確認してください。

WITH RESULT (PARENT,CHILD,TNAME,LEVEL)
AS
(
--anchor
 SELECT E.PARENT_GENERAL_KEY,E.M_GENERAL_KEY,E.NAME ,0 AS LEVEL
  FROM RPT_SYN_M_GENERAL AS E 
 WHERE E.PARENT_GENERAL_KEY IS NULL
 UNION ALL
 --outer
 SELECT D.CHILD,D.PARENT,e.NAME ,LEVEL +1 --switched parent/child
 FROM RPT_SYN_M_GENERAL AS E
 INNER JOIN RESULT AS D  
 ON E.PARENT_GENERAL_KEY=D.CHILD 
WHERE LEVEL<100
)
SELECT PARENT,CHILD,TNAME,LEVEL FROM RESULT as d
order by PARENT,CHILD
于 2012-04-24T05:08:31.670 に答える