11

Postgres ストアド関数が識別された列を含むテーブルを返す方法を知りたいです。私はreturnTypeのreturnsセットを使用しました:

-- create employeeSearchResult returnType
create type employeeAllReturnType as
(
  id bigserial,
  "positionId" integer,
  "subjectId" bigint,
  "dateEngaged" date,
  "nextKin" text,
  "nrcNo" text,
  dob date,
  father text,
  mother text,
  wife text,
  "userId" integer,
  "statusId" integer,
  "mainCode" text,
  "subCode" text
);


-- Search for emmployee by name
CREATE OR REPLACE FUNCTION "employee_search_by_name"(employeeNameIN text)
returns setof employeeAllReturnType as 
$$
declare
    results record;
    resultsRow employee%rowtype;
    nameIn text;
begin
    nameIn = employeeNameIN || '%';
    for results in select 
        employee.id,-- bigserial NOT NULL,
  employee."positionId",-- integer,
  employee."subjectId",-- bigint NOT NULL,
  employee."dateEngaged",-- date,
  employee."nextKin",-- text,
  employee."nrcNo",-- text,
  employee.dob,-- date,
  employee.father,-- text,
  employee.mother,-- text,
  employee.wife,-- text,
  employee."userId",-- integer NOT NULL,
  employee."statusId",-- integer,
  employee."mainCode",-- character(5) NOT NULL,
  employee."subCode"-- character(10),
     from employee, subject where employee."subjectId" = subject.id and (subject.name1 ILIKE nameIn OR subject.name2 ILIKE nameIn OR subject.name3 ILIKE nameIn OR subject.name4 ILIKE nameIn) loop
      return next results;
    end loop;
end;
$$ language 'plpgsql';

また、table() を返します。

-- Search for emmployee by name
CREATE OR REPLACE FUNCTION "employee_search_by_name"(employeeNameIN text)
returns table (id bigserial,
  position integer,
  subject bigint,
  date_engaged date,
  next_kin text,
  nrc_no text,
  dob date,
  father text,
  mother text,
  wife text,
  user_id integer,
  status_id integer,
  main_code text,
  sub_code text) as 
$$
declare
    results record;
    resultsRow employee%rowtype;
    nameIn text;
begin
    nameIn = employeeNameIN || '%';
    for results in select 
        employee.id,-- bigserial NOT NULL,
        employee."positionId",-- integer,
        employee."subjectId",-- bigint NOT NULL,
        employee."dateEngaged",-- date,
        employee."nextKin",-- text,
        employee."nrcNo",-- text,
        employee.dob,-- date,
        employee.father,-- text,
        employee.mother,-- text,
        employee.wife,-- text,
        employee."userId",-- integer NOT NULL,
        employee."statusId",-- integer,
        employee."mainCode",-- character(5) NOT NULL,
        employee."subCode"-- character(10),
     from employee, subject where employee."subjectId" = subject.id and (subject.name1 ILIKE nameIn OR subject.name2 ILIKE nameIn OR subject.name3 ILIKE nameIn OR subject.name4 ILIKE nameIn) loop
      return next results;
    end loop;
end;
$$ language 'plpgsql';

ただし、どちらも次の形式で出力されます。

"(1,1,1,2011-12-01,Timea,fg1254,1981-12-27,moses,sarada,timea,1,1,"ADM  ","1         ")"
"(37,3,10,2011-11-11,s,s,2011-11-11,s,s,s,1,1,"OP   ","1         ")"

テーブルからの選択結果などの出力を得ることができる方法はありますか?

"1";1;1;"2011-12-01";"Timea";"fg1254";"1981-12-27";"moses";"sarada";"timea";1;1;"ADM  ";"1         "

フロントエンドからの結果データの処理にパーサーは必要ありません。

4

1 に答える 1

12

次のように関数をクエリする必要があります。

SELECT * FROM employee_search_by_name('Bob');

また、関数を単純化するために、RETURN QUERY EXECUTE ...構文を調べることもできます。plpgsqlまた、キーワードを引用する必要はありません。

于 2012-04-26T09:24:03.743 に答える