そのような例
<?xml version="1.0" encoding="UTF-8"?>
<root>
<a id='a1' name='a1 is a Chinese pig'/>
<b text='b1'/>
<d test='test0' location='L0' text='c0'/>
<a id='a2' name='a2 is a Japanese pig'/>
<b text='b2'/>
<c test='test1' location='L1' text='c1 is a red pig'/>
<c test='test2' location='L2' text='c2 is a green pig'/>
<a id='a3' name='a3 is a American dog'/>
<b text='b3'/>
<c test='test3' location='L3' text='c3 is a lovely dog'/>
<c test='test4' location='L4' text='c4 is a ugly dog'/>
<c test='test5' location='L5' text='c5 is a smart dog'/>
<a id='a4' name='a4 is a Japanese bird'/>
<b text='b4'/>
<c test='test6' location='L6' text='c6 is a lovely bird'/>
<c test='test7' location='L7' text='c7 is a ugly bird'/>
<c test='test8' location='L8' text='c8 is a smart bird'/>
<a id='a5' name='a5 is a American pig'/>
<b text='b2'/>
<c test='test10' location='L10' text='c10 is a red pig'/>
<c test='test11' location='L11' text='c11 is a green pig'/>
<a id='a6' name='a6 is a Chinese dog'/>
<b text='b3'/>
<c test='test12' location='L12' text='c12 is a lovely dog'/>
<c test='test14' location='L14' text='c14 is a ugly dog'/>
<c test='test15' location='L15' text='c15 is a smart dog'/>
<a id='a7' name='a7 is a Chinese bird'/>
<b text='b4'/>
<c test='test16' location='L16' text='c16 is a lovely bird'/>
<c test='test17' location='L17' text='c17 is a ugly bird'/>
<c test='test18' location='L18' text='c18 is a smart bird'/>
</root>
このように xsl1.0 を適用します
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="text" indent="yes"/>
<xsl:key name="lookup" match="c" use="generate-id(preceding-sibling::a[1])" />
<xsl:template match="/root">
<xsl:apply-templates select="a[key('lookup', generate-id())]" />
</xsl:template>
<xsl:template match="a">dog:<xsl:value-of select="concat(@name[contains(.,'dog')], ': ', ' ')" />
<xsl:apply-templates select="key('lookup', generate-id())" />
</xsl:template>
<xsl:template match="c">
<xsl:apply-templates select="@*" />
<xsl:value-of select="' '" />
</xsl:template>
<xsl:template match="c/@*">
<xsl:value-of select="concat(local-name(), ':', ., ': ')" />
</xsl:template>
</xsl:stylesheet>
このような出力が必要です。ルールは
- 要素と次の a の間に 1 つ以上の後続の c 要素がある場合、これらの c 要素を出力します。
- 次に、@name に従って、値に pig、dog、bird などの文字列が含まれていることを確認します。これらはキーワードであり、ここでのハードコード作業だけではありません。豚、鳥、犬のほうが多いので、これらの情報をグループ化できます。中国人か日本人かは関係なく、以前に知っている犬、鳥、豚のカテゴリに従ってグループ化します。
私が望む出力はこのようなものです
case1:the following are all pigs:
a2 is a Japanese pig
test:test1
location:L1
text:c1 is a red pig
test:test2
location:L2
text:c2 is a green pig
a5 is a American pig
test:test10
location:L10
text:c10 is a red pig
test:test11
location:L11
text:c11 is a green pig
case2:the following are all dogs:
a3 is a American dog
test:test3
location:L3
text:c3 is a lovely dog
test:test4
location:L4
text:c4 is a ugly dog
test:test5
location:L5
text:c5 is a smart dog
a6 is a Chinese dog
test:test12
location:L12
text:c12 is a lovely dog
test:test14
location:L14
text:c14 is a ugly dog
test:test15
location:L15
text:c15 is a smart dog
case3:the following are all birds:
a4 is a Japanese bird
test:test6
location:L6
text:c6 is a lovely bird
test:test7
location:L7
text:c7 is a ugly bird
test:test8
location:L8
text:c8 is a smart bird
a7 is a Chinese bird
test:test16
location:L16
text:c16 is a lovely bird
test:test17
location:L17
text:c17 is a ugly bird
test:test18
location:L18
text:c18 is a smart bird
問題は、私の xsl1.0 を修正する方法ですか? もう1つは、xsl2.0でこれを実現するのがより簡単ですか?