(ここで私自身の質問に答えます)
私の知る限り、これは不可能です。数日見ても何も見えません。必要な処理を実行する簡単なスクリプトを作成しました。カバレッジ出力を取得して解析し、特定のパッケージのカバレッジが特定のしきい値を満たしていない場合はビルドに失敗します。汚れていて、クリーンアップ/拡張できますが、基本的な考え方はここにあります。コメントは大歓迎です。
#!/usr/bin/env python
'''
Jenkins' Cobertura plugin doesn't allow marking a build as successful or
failed based on coverage of individual packages -- only the project as a
whole. This script will parse the coverage.xml file and fail if the coverage of
specified packages doesn't meet the thresholds given
'''
import sys
from lxml import etree
PACKAGES_XPATH = etree.XPath('/coverage/packages/package')
def main(argv):
filename = argv[0]
package_args = argv[1:] if len(argv) > 1 else []
# format is package_name:coverage_threshold
package_coverage = {package: int(coverage) for
package, coverage in [x.split(':') for x in package_args]}
xml = open(filename, 'r').read()
root = etree.fromstring(xml)
packages = PACKAGES_XPATH(root)
failed = False
for package in packages:
name = package.get('name')
if name in package_coverage:
# We care about this one
print 'Checking package {} -- need {}% coverage'.format(
name, package_coverage[name])
coverage = float(package.get('line-rate', '0.0')) * 100
if coverage < package_coverage[name]:
print ('FAILED - Coverage for package {} is {}% -- '
'minimum is {}%'.format(
name, coverage, package_coverage[name]))
failed = True
else:
print "PASS"
if failed:
sys.exit(1)
if __name__ == '__main__':
main(sys.argv[1:])