6

交差条件を実行できるかどうか知りたいです。somesクエリがありますが、結果は間違っています（常に空です）。結果を書きます。

DECLARE @CAN_USE_TABLE1 BIT
DECLARE @CAN_USE_TABLE2 BIT
DECLARE @CAN_USE_TABLE3 BIT
DECLARE @CAN_USE_TABLE4 BIT

DECLARE @TABLE1 AS TABLE ( ABC INT ) -- values will be 1,2,3
DECLARE @TABLE2 AS TABLE ( ABC INT ) -- values will be 1,2
DECLARE @TABLE3 AS TABLE ( ABC INT ) --EMPTY TABLE
DECLARE @TABLE4 AS TABLE ( ABC INT ) --EMPTY TABLE
INSERT INTO @TABLE1 VALUES (1)
INSERT INTO @TABLE1 VALUES (2)
INSERT INTO @TABLE1 VALUES (3)
INSERT INTO @TABLE2 VALUES (1)
INSERT INTO @TABLE2 VALUES (2)

SET @CAN_USE_TABLE1 = 1
SET @CAN_USE_TABLE2 = 1
SET @CAN_USE_TABLE3 = 1
SET @CAN_USE_TABLE4 = 0

SELECT ABC FROM @TABLE1 WHERE @CAN_USE_TABLE1 = 1
INTERSECT
SELECT ABC FROM @TABLE2 WHERE @CAN_USE_TABLE2 = 1
INTERSECT 
SELECT ABC FROM @TABLE3 WHERE @CAN_USE_TABLE3 = 1
INTERSECT
SELECT ABC FROM @TABLE4 WHERE @CAN_USE_TABLE4 = 1

--RESULT SHOULD BE :
--  NO RESULT
--
--  BECAUSE, AT THIS STAGE, TABLE1 AND TABLE2 AND TABLE3 SHOULD BE INTERSECTED. AND BECAUSE TABLE3 IS EMPTY, THE RESULT IS EMPTY.

SET @CAN_USE_TABLE1 = 1
SET @CAN_USE_TABLE2 = 1
SET @CAN_USE_TABLE3 = 0
SET @CAN_USE_TABLE4 = 0

SELECT ABC FROM @TABLE1 WHERE @CAN_USE_TABLE1 = 1
INTERSECT
SELECT ABC FROM @TABLE2 WHERE @CAN_USE_TABLE2 = 1
INTERSECT 
SELECT ABC FROM @TABLE3 WHERE @CAN_USE_TABLE3 = 1
INTERSECT
SELECT ABC FROM @TABLE4 WHERE @CAN_USE_TABLE4 = 1

--RESULT SHOULD BE :
--  1
--  2
--
--  BECAUSE, AT THIS STAGE, TABLE1 AND TABLE2 SHOULD BE INTERSECTED

SET @CAN_USE_TABLE1 = 0
SET @CAN_USE_TABLE2 = 1
SET @CAN_USE_TABLE3 = 0
SET @CAN_USE_TABLE4 = 0

SELECT ABC FROM @TABLE1 WHERE @CAN_USE_TABLE1 = 1
INTERSECT
SELECT ABC FROM @TABLE2 WHERE @CAN_USE_TABLE2 = 1
INTERSECT 
SELECT ABC FROM @TABLE3 WHERE @CAN_USE_TABLE3 = 1
INTERSECT
SELECT ABC FROM @TABLE4 WHERE @CAN_USE_TABLE4 = 1

--RESULT SHOULD BE :
--  1
--  2
--
--  BECAUSE, AT THIS STAGE, ONLY TABLE 2 SHOULD BE USED
4

3 に答える 3

2

INTERSECT他のセットと一緒に編集された空のセットは常に空になります。これは、0を掛けるようなものです。常に0を取得します。

条件付きINTERSECTのingには、次のような動的クエリまたはステージングテーブルのいずれかが必要です。

初期化

DECLARE @CAN_USE_TABLE1 BIT
DECLARE @CAN_USE_TABLE2 BIT
DECLARE @CAN_USE_TABLE3 BIT
DECLARE @CAN_USE_TABLE4 BIT

DECLARE @TABLE1 AS TABLE ( ABC INT )
DECLARE @TABLE2 AS TABLE ( ABC INT )
DECLARE @TABLE3 AS TABLE ( ABC INT )
DECLARE @TABLE4 AS TABLE ( ABC INT )
DECLARE @RESULT AS TABLE ( ABC INT ) --Adding this result table
INSERT INTO @TABLE1 VALUES (1)
INSERT INTO @TABLE1 VALUES (2)
INSERT INTO @TABLE1 VALUES (3)
INSERT INTO @TABLE2 VALUES (1)
INSERT INTO @TABLE2 VALUES (2)

SET @CAN_USE_TABLE1 = 1
SET @CAN_USE_TABLE2 = 1
SET @CAN_USE_TABLE3 = 0
SET @CAN_USE_TABLE4 = 0

処理

INSERT INTO @RESULT
SELECT ABC FROM @TABLE1 WHERE @CAN_USE_TABLE1=1 UNION
SELECT ABC FROM @TABLE2 WHERE @CAN_USE_TABLE2=1 UNION
SELECT ABC FROM @TABLE3 WHERE @CAN_USE_TABLE3=1 UNION
SELECT ABC FROM @TABLE4 WHERE @CAN_USE_TABLE4=1

DELETE r FROM @RESULT r
WHERE NOT EXISTS(SELECT 1 FROM @TABLE1 WHERE ABC=r.ABC)
AND @CAN_USE_TABLE1=1;

DELETE r FROM @RESULT r
WHERE NOT EXISTS(SELECT 1 FROM @TABLE2 WHERE ABC=r.ABC)
AND @CAN_USE_TABLE2=1;

DELETE r FROM @RESULT r
WHERE NOT EXISTS(SELECT 1 FROM @TABLE3 WHERE ABC=r.ABC)
AND @CAN_USE_TABLE3=1;

DELETE r FROM @RESULT r
WHERE NOT EXISTS(SELECT 1 FROM @TABLE4 WHERE ABC=r.ABC)
AND @CAN_USE_TABLE4=1;

SELECT * FROM @RESULT;

結果

1
2
于 2012-05-25T20:34:00.697 に答える
0 
declare @sql nvarchar(4000),
    @params nvarchar(4000)

 if @can_use_table1 = 1
    select @sql= 'select abc from @table1'

 if @can_use_table2 = 1
 begin
    if  @can_use_table1 = 1
       select @sql = @sql + ' intersect '
    select @sql = @sql + 'select abc from @table2'
 end

 if @can_use_table3 = 1
 begin
   if  @can_use_table1 = 1 or @can_use_table2 = 1
      select @sql= @sql + ' intersect '        
   select @sql= @sql + 'select abc from @table3'
 end

 if @can_use_table4 = 1
 begin
   if  @can_use_table1 = 1 or @can_use_table2 = 1 or @can_use_table3 = 1
      select @sql= @sql + ' intersect ' 
   select @sql= @sql + 'select abc from @table4'    
 end

select @params ='@can_use_table1 bit, @can_use_table2 bit,
         @can_use_table3 bit, @can_use_table4 bit,
 @table1 table, @table2 table, @table3  table, @table4 table' 

exec sp_executesql @sql,@params, 
       @can_use_table1,@can_use_table2, @can_use_table3, @can_use_table4,
       @table1, @table2, @table3, @table4
于 2012-05-25T20:19:59.853 に答える
0

これは、次のように1つのクエリで実行できます。

select ABC
from (SELECT ABC, @CAN_USE_TABLE1 as CanUse1, 0 as CanUse2, 0 as CanUse3, 0 as CanUse4
      FROM @TABLE1 
      union all
      SELECT ABC, 0, @CAN_USE_TABLE2, 0, 0 FROM @TABLE2
      union all
      SELECT ABC, 0, 0,  @CAN_USE_TABLE3, 0 FROM @TABLE3
      union all
      SELECT ABC, 0, 0, 0, @CAN_USE_TABLE4 FROM @TABLE4
     ) t
group by ABC
having max(Canuse1) = @CAN_USE_TABLE1 AND
       max(CanUse2) = @CAN_USE_TABLE2 AND
       max(CanUse3) = @CAN_USE_TABLE3 And
       max(CanUse4) = @CAN_USE_TABLE4
于 2012-05-26T02:09:40.000 に答える