辞書の特定のキーとアイテムのペアの後にアイテムを追加する必要があります。add メンバーがコレクションで許可するのと本質的に同じ動作: (Collection.Add (item [,key] [,before] [,after])
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5
これを可能にするDictionaryオブジェクトの組み込みメソッドはありません。これがあなた自身を転がす簡単な方法です。これはあなたが求めていることを具体的に達成しますが、変更するのは簡単です：
Function DictAdd(StartingDict As Dictionary, Key, Item, AfterKey) As Dictionary
Dim DictKey As Variant
Set DictAdd = New Dictionary
For Each DictKey In StartingDict
DictAdd.Add DictKey, StartingDict(DictKey)
If DictKey = AfterKey Then DictAdd.Add Key, Item
Next DictKey
End Function
そしてそれをテストするには、次の手順を実行します。
Sub TestDictAdd()
Dim MyDict As New Dictionary, DictKey As Variant
MyDict.Add "A", "Alpha"
MyDict.Add "C", "Charlie"
Set MyDict = DictAdd(MyDict, "B", "Bravo", "A")
For Each DictKey In MyDict
Debug.Print DictKey, MyDict(DictKey)
Next DictKey
End Sub
これはあなたが始めるためだけのものです。これを自分で行う場合は、関数を使用する代わりに、使用する独自のカスタムクラスを作成し、カスタムAddメソッドを作成する可能性があります。また、次の改善を行います。
- エラー処理を追加
- AfterKeyをオプションのパラメータにする
- オプションのパラメータとしてBeforeKeyを追加します
于 2012-05-28T19:55:53.097 に答える
1
このような？
Option Explicit
Sub Sample()
Dim Dict As Dictionary
Dim itm As Variant
Set Dict = New Dictionary
Dict.Add "MyKey1", "Hello"
Dict.Add "MyKey2", "This"
Dict.Add "MyKey3", "is"
Dict.Add "MyKey4", "Example"
'~~> USAGE: Dictionaty Object, Key, Text, Position
Additem Dict, "MyKey5", "An", 3
For Each itm In Dict
Debug.Print itm & " - " & Dict(itm)
Next
End Sub
Function Additem(ByRef D As Dictionary, ky As Variant, itm As Variant, pos As Long)
Dim kyAr() As Variant, itmAr() As Variant
Dim temp1() As Variant, temp2() As Variant
Dim i As Long
kyAr = D.Keys: itmAr = D.Items
ReDim temp1(UBound(kyAr) + 1)
ReDim temp2(UBound(itmAr) + 1)
For i = 0 To pos - 1
temp1(i) = kyAr(i): temp2(i) = itmAr(i)
Next
temp1(pos) = ky: temp2(pos) = itm
For i = pos + 1 To UBound(temp1)
temp1(i) = kyAr(i - 1): temp2(i) = itmAr(i - 1)
Next
ReDim kyAr(0): ReDim itmAr(0)
kyAr() = temp1(): itmAr() = temp2()
D.RemoveAll
For i = LBound(kyAr) To UBound(kyAr)
D.Add kyAr(i), itmAr(i)
Next i
End Function
出力
前
MyKey1 - Hello
MyKey2 - This
MyKey3 - is
MyKey4 - Example
後
MyKey1 - Hello
MyKey2 - This
MyKey3 - is
MyKey5 - An
MyKey4 - Example
于 2012-05-28T19:57:20.943 に答える
1
ディクショナリにすべての項目が含まれている場合にディクショナリをソートする代わりに、DctAdd という小さなプロシージャを実装しました。これは、項目を追加するときにキーをすぐにソートしたままにします。キーが vAdd であると仮定すると、アイテムは vItem であり、バリアント型と並べ替えられるディクショナリの両方が dct です。代わりに：
dct.Add vAdd, vItem
私が使う：
DctAdd dct, vItem, vAdd, dam_sortasc
パフォーマンスについては、プロジェクトで使用するときに十分であることがわかったので、いくつかの基本的なテストのみを含めました。
DctAdd を使用するには、関連するモジュールの宣言セクションに以下をコピーする必要があります。
' Just for the performance time measurement -----------------------------
Private Declare Function GetTime Lib "winmm.dll" Alias "timeGetTime" () As Long
' For the execution mode of DctAdd --------------------------------------
' (may be extended to also cover insert before and after)
Public Enum enAddInsertMode
dam_sortasc = 1
dam_sortdesc = 2
End Enum
次のコードは、任意の標準モジュールまたはクラス モジュールにコピーできます。insert before/after はまだ実装されていませんが、追加にそれほど時間はかからないことに注意してください。
Public Sub DctAdd(ByRef dct As Scripting.Dictionary, _
ByVal vItem As Variant, _
ByVal vAdd As Variant, _
ByVal lMode As enAddInsertMode)
' ----------------------------------------------------------------------
' Add to the Dictionary dct the item vItem with vAdd as the key,
' sorted in ascending or descending order.
'
' If the vAdd key already exists, adding it will be skipped without
' an error. A not existing dictionary is established with the first add
'
' W. Rauschenberger, warbe@cogip.de, Berlin, Feb 2015
' ----------------------------------------------------------------------
Dim i As Long
Dim dctTemp As Scripting.Dictionary
Dim vTempKey As Variant
Dim bAdd As Boolean
If dct Is Nothing Then Set dct = New Dictionary
With dct
If .count = 0 Then
.Add vAdd, vItem
Exit Sub
Else
' -----------------------------------------------------------
' The can maybee added directly after the last key
' -----------------------------------------------------------
vTempKey = .Keys()(.count - 1) ' Get the very last key
Select Case lMode
Case dam_sortasc
If vAdd > vTempKey Then
.Add vAdd, vItem
Exit Sub ' Done!
End If
Case dam_sortdesc
If vAdd < vTempKey Then
.Add vAdd, vItem
Exit Sub ' Done!
End If
End Select
End If
End With
' -----------------------------------------------------------------
' Since the new key could not simply be added to the dct it must be
' added/inserted somewhere in between or before the very first key
' ------------------------------------------------------------------
Set dctTemp = New Dictionary
bAdd = True
For Each vTempKey In dct
With dctTemp
If bAdd Then ' When the new item has yet not been added
Select Case lMode
Case dam_sortasc
If vTempKey > vAdd Then
If Not dct.Exists(vAdd) Then
.Add vAdd, vItem
End If
bAdd = False ' Add done
End If
Case dam_sortdesc
If vTempKey < vAdd Then
If Not dct.Exists(vAdd) Then
.Add vAdd, vItem
End If
bAdd = False ' Add done
End If
End Select
End If
.Add vTempKey, dct.Item(vTempKey)
End With
Next vTempKey
' ------------------------------------
Set dct = dctTemp ' Return the temporary dictionary with
Set dctTemp = Nothing ' the added new item
Exit Sub ' ------------------------------------
on_error:
Debug.Print "Error in 'DctAdd'!"
End Sub
そして、これをテストに使用しました：
Public Sub Testdct1Add()
Dim dct1 As Scripting.Dictionary
Dim dct2 As Scripting.Dictionary
Dim i As Long
Dim lStart As Long
Dim lAdd As Long
Dim vKey As Variant
' -----------------------------------------------------------------------
Debug.Print vbLf & "DctAdd: Test ascending order"
' Add sorted ascending with the key provided in the reverse order
Set dct1 = Nothing
For i = 10 To 1 Step -1
DctAdd dct1, i, i, dam_sortasc
Next i
' Show the result and wait ----------------
For Each vKey In dct1
Debug.Print vKey & " " & dct1.Item(vKey)
Next vKey
Stop
' ------------------------------------------------------------------
Debug.Print vbLf & "DctAdd: Test descending order"
' Add sorted ascending with the key provided in the reverse order
Set dct1 = Nothing
For i = 1 To 10
DctAdd dct1, i, i, dam_sortdesc
Next i
' Show the result and wait ----------------
For Each vKey In dct1
Debug.Print vKey & " " & dct1.Item(vKey)
Next vKey
Stop
' ------------------------------------------------------------------
lAdd = 500
Debug.Print vbLf & "DctAdd: Test a best case scenario by adding " & _
vbLf & lAdd & " items in the desired sort order"
Set dct1 = Nothing
lStart = GetTime
For i = 1 To lAdd
DctAdd dct1, i, i, dam_sortasc
Next i
Debug.Print "Adding " & dct1.count & " items in the target " & _
vbLf & "sort order = " & GetTime - lStart & " ms"
Stop
' ------------------------------------------------------------------
lAdd = 500
Debug.Print vbLf & "DctAdd: Worst case scenarion test by adding " & _
vbLf & lAdd & " items in the reverse sort order"
Set dct1 = Nothing
lStart = GetTime
For i = lAdd To 1 Step -1
DctAdd dct1, i, i, dam_sortasc
Next i
Debug.Print "Adding " & dct1.count & " items, 4 out of " & vbLf & _
"order = " & GetTime - lStart & " ms"
Stop
' -----------------------------------------------------------------
lAdd = 1000
Debug.Print vbLf & "DctAdd: Worst case scenarion test by adding " & _
vbLf & lAdd & " items in the reverse sort order"
Set dct1 = Nothing
lStart = GetTime
For i = lAdd To 1 Step -1
DctAdd dct1, i, i, dam_sortasc
Next i
Debug.Print "Adding " & dct1.count & " items:" & vbLf & _
GetTime - lStart & " ms"
Stop
' -----------------------------------------------------------------
' Example for using dctAdd to sort any dictionary. The item if dct2
' are temporarily added sorted ascending to the dct1 and finally set
' to dct2
' ------------------------------------------------------------------
Debug.Print vbLf & "DctAdd: Used to sort another Dictionary (dct2)"
Set dct2 = New Dictionary
dct2.Add "F", 1
dct2.Add "A", 2
dct2.Add "C", 3
dct2.Add "H", 4
dct2.Add "D", 5
dct2.Add "E", 6
dct2.Add "G", 7
dct2.Add "B", 8
Set dct1 = Nothing
For Each vKey In dct2
DctAdd dct1, dct2(vKey), vKey, dam_sortasc
Next vKey
Set dct2 = dct1
' Show the result and wait ----------------
For Each vKey In dct2
Debug.Print "Key=" & vKey & ", Item=" & dct2.Item(vKey)
Next vKey
End Sub
于 2015-02-26T16:16:10.930 に答える