9

私は過去3時間、何百ものリンクを探していました。たとえば、webconfigへのscriptfactoryの追加、3つの間違い、コンテンツタイプの設定などです。

私は実際に間違いが何であるかを理解することができません。

環境：.net4.0で実行されているサービス.net4.0で実行されているWebアプリケーション

要件：jsonを文字列として返すasmxWebサービスにjqGridをバインドする必要があります。 Webサービスファイルには次のコードが含まれています。

[WebService(Namespace = "http://tempuri.org/")]
[WebServiceBinding(ConformsTo = WsiProfiles.BasicProfile1_1)]
[System.ComponentModel.ToolboxItem(false)]
[ScriptService]
public class SampleService : System.Web.Services.WebService
{
    [WebMethod]
    [ScriptMethod(ResponseFormat = ResponseFormat.Json)]
    public string GetJsonServerProcess()
    {
        int memory = 1;
        string json = string.Empty;
        var obj = (System.Diagnostics.Process.GetProcesses().Where(r => r.WorkingSet64 > memory).Select(p => new { p.ProcessName, p.WorkingSet64 }).ToArray());
        json = Lib.ToJSON(obj);
        return json;
    }
}

Javascriptは次のとおりです

<script type="text/javascript">
    $(document).ready(function () {
        jQuery("#jqgajax").jqGrid({
            ajaxGridOptions: { type: "POST", contentType: 'application/json; charset=utf-8'  },
            url:'http://localhost:1092/SampleService.asmx/GetJsonServerProcess',
            datatype: "json",
            data: "{}",
            colNames: ['ProcessName', 'WorkingSet64'],
            colModel: [
                        { name: 'ProcessName', index: 'ProcessName', width: 55 },
                        { name: 'WorkingSet64', index: 'WorkingSet64', width: 90 }
                    ],
            rowNum: 10,
            width: 700,
            rowList: [10, 20, 30],
            sortname: 'invdate',
            viewrecords: true,
            sortorder: "desc",
            caption: "New API Example"
        });
    });
</script>

HTMLは次のとおりです

<table id="jqgajax">
</table>
<div id="jqgajax">
</div>

[呼び出し]ボタンをクリックしたときのWebサービスの出力

<string xmlns="http://tempuri.org/">
[{"ProcessName":"Dropbox","WorkingSet64":22736896},
 {"ProcessName":"fdhost","WorkingSet64":1941504},
 {"ProcessName":"IntelliTrace","WorkingSet64":39276544}
]
</string>

私が欠けているものを提案してください。 <string xmlns="http://tempuri.org/">タグは私を苛立たせます。これらのタグによってグリッドをバインドできないと想定しています。

アップデート：

ASMXサービスは次のようになります。

[WebService(Namespace = "http://tempuri.org/")]
[WebServiceBinding(ConformsTo = WsiProfiles.BasicProfile1_1)]
[System.ComponentModel.ToolboxItem(false)]
[ScriptService]
public class SampleService : System.Web.Services.WebService
{
    [WebMethod]
    [ScriptMethod(ResponseFormat = ResponseFormat.Json)]
    public List<demo> GetJsonServerProcess()
    {
        List<demo> test = new List<demo>();

        for(int i=1;i<=10;i++)
            test.Add(new demo { ProcessName = string.Format("Sample {0}",i), WorkingSet64 = i });

        var re = test;
        return re;
    }
}

public class demo
{
    public string ProcessName { get; set; }
    public int WorkingSet64 { get; set; }
}
4

8 に答える 8

7

Clicking on the Invoke button returns XML because the request don't specify the contentType: 'application/json; charset=utf-8'. So the experiment with clicking on Invoke button help not really.

The main problem in your code is that you convert the data to string inside of web method. The line

json = Lib.ToJSON(obj);

are not needed. What one typically do is returning the object. The GetJsonServerProcess should be changed to something like

[ScriptService]
public class SampleService : System.Web.Services.WebService
{
    [WebMethod]
    [ScriptMethod(ResponseFormat = ResponseFormat.Json)]
    public List<Process> GetJsonServerProcess()
    {
        int memory = 1;
        return System.Diagnostics.Process.GetProcesses()
                   .Where(r => r.WorkingSet64 > memory)
                   .Select(p => new { p.ProcessName, p.WorkingSet64 })
                   .ToList();
    }
}

The next problem is that the default input format which wait jqGrid is another (see here). So you cave to specify jsonReader which describe the data format. In your case it will be something like

jsonReader: {
    repeatitems: false,
    id: "ProcessName",
    root: function (obj) { return obj; },
    page: function () { return 1; },
    total: function () { return 1; },
    records: function (obj) { return obj.length; }
}

Additionally you should never use http://localhost:1092/ prefix in Ajax url because you cal only get data from the same site because of security reasons. The data parameter in jqGrid has another meaning as in jQuery so you should remove data: "{}" and move type: "POST" from ajaxGridOptions to mtype: "POST". As the result you will have something like

$(document).ready(function () {
    $("#jqgajax").jqGrid({
        mtype: "POST",
        ajaxGridOptions: { contentType: 'application/json; charset=utf-8' },
        url: '/SampleService.asmx/GetJsonServerProcess',
        postData: "{}", // remove all parameters which jqGrid send typically
        datatype: "json",
        colNames: ['ProcessName', 'WorkingSet64'],
        colModel: [
            { name: 'ProcessName', index: 'ProcessName', width: 155 },
            { name: 'WorkingSet64', index: 'WorkingSet64', width: 190 }
        ],
        jsonReader: {
            repeatitems: false,
            id: "ProcessName",
            root: function (obj) { return obj; },
            page: function () { return 1; },
            total: function () { return 1; },
            records: function (obj) { return obj.length; }
        },
        rowNum: 10,
        loadonce: true,
        gridview: true,
        height: 'auto',
        rowList: [10, 20, 30],
        viewrecords: true,
        sortorder: "desc",
        caption: "New API Example"
    });
});

I don't tested the code, but it should be more close to what you need.

UPDATED: You should fix the code by changing jsonReader. You can download the working demo here. It display the grid

enter image description here

I used on the server side the code

using System.Collections.Generic;
using System.Diagnostics;
using System.Linq;
using System.Web.Services;

namespace jqGridWebASMX
{
    [WebService(Namespace = "http://tempuri.org/")]
    [WebServiceBinding(ConformsTo = WsiProfiles.BasicProfile1_1)]
    [System.ComponentModel.ToolboxItem(false)]
    [System.Web.Script.Services.ScriptService]
    public class SampleService : WebService
    {
        [WebMethod]
        public List<Demo> GetJsonServerProcess()
        {
            const int memory = 1;
            return Process.GetProcesses()
                .Where (r => r.WorkingSet64 > memory)
                .Select(p => new Demo {
                    Id = p.Id,
                    ProcessName = p.ProcessName,
                    WorkingSet64 = p.WorkingSet64
                })
                .ToList();
        }
    }

    public class Demo
    {
        public int Id { get; set; }
        public string ProcessName { get; set; }
        public long WorkingSet64 { get; set; }
    }
}

and on the client side

$("#list").jqGrid({
    mtype: "POST",
    ajaxGridOptions: { contentType: 'application/json; charset=utf-8' },
    url: '/SampleService.asmx/GetJsonServerProcess',
    postData: "{}", // remove all parameters which jqGrid send typically
    datatype: "json",
    colNames: ['ProcessName', 'WorkingSet64'],
    colModel: [
        { name: 'ProcessName', index: 'ProcessName', width: 200 },
        { name: 'WorkingSet64', index: 'WorkingSet64', width: 120,
            formatter: 'integer', sorttype: 'int', align: 'right' }
    ],
    jsonReader: {
        repeatitems: false,
        id: "Id",
        root: function (obj) { return obj.d; },
        page: function () { return 1; },
        total: function () { return 1; },
        records: function (obj) { return obj.d.length; }
    },
    rowNum: 10,
    loadonce: true,
    gridview: true,
    height: 'auto',
    pager: '#pager',
    rowList: [10, 20, 30],
    rownumbers: true,
    viewrecords: true,
    sortorder: "desc",
    caption: "New API Example"
});
$("#pager_left").hide(); // hide unused part of the pager to have more space
于 2012-05-30T22:01:49.737 に答える
1

Okay, I got the same error and after a load of trial and error here's my "quick and dirty" solution;

$.get(url, {var1: parameter1, var2: parameter2}, function(data){
    data = JSON.parse($(data).find("string").text());
    alert("data.source: " + data.source);
});
于 2013-08-13T10:08:02.463 に答える
1

The following code should do the trick:

this.Context.Response.ContentType = "application/json; charset=utf-8";
this.Context.Response.Write(json);
于 2016-07-01T13:58:36.547 に答える
1

This code works perfectly 

SqlDataAdapter sda = new SqlDataAdapter(strsql, ConfigurationManager.ConnectionStrings["BTConString"].ToString());
DataSet das = new DataSet();
sda.Fill(das);
Context.Response.Output.Write(JsonConvert.SerializeObject(das, Newtonsoft.Json.Formatting.Indented));
Context.Response.End();

return string.Empty;
于 2017-06-21T07:16:36.697 に答える
0 
  response = await client.GetAsync(RequestUrl, HttpCompletionOption.ResponseContentRead);
                if (response.IsSuccessStatusCode)
                {
                    _data = await response.Content.ReadAsStringAsync();
                    try
                    {
                        XmlDocument _doc = new XmlDocument();
                        _doc.LoadXml(_data);
                        return Request.CreateResponse(HttpStatusCode.OK, JObject.Parse(_doc.InnerText));
                    }
                    catch (Exception jex)
                    {
                        return Request.CreateResponse(HttpStatusCode.BadRequest, jex.Message);
                    }
                }
                else
                    return Task.FromResult<HttpResponseMessage>(Request.CreateResponse(HttpStatusCode.NotFound)).Result;
于 2015-05-17T10:19:57.470 に答える
0

Before function starts put the below 

[System.Web.Services.WebMethod(EnableSession = true)]
[ScriptMethod(UseHttpGet = true, ResponseFormat = ResponseFormat.Json)]

make function as void

when the function ends put below line

this.Context.Response.ContentType = "application/json; charset=utf-8";
this.Context.Response.Write(json);

Example program 

        [System.Web.Services.WebMethod(EnableSession = true)]
        [ScriptMethod(UseHttpGet = true, ResponseFormat = ResponseFormat.Json)]
        public void testJson()
        {
            string json = "{}";
            this.Context.Response.ContentType = "";
            this.Context.Response.Write(json);
        }
于 2019-05-07T06:42:37.293 に答える
0

You can put your url in postman and use the response

Like this i am using php

<?php

$curl = curl_init();

curl_setopt_array($curl, array( CURLOPT_URL => 'your url', CURLOPT_RETURNTRANSFER => true, CURLOPT_ENCODING => '', CURLOPT_MAXREDIRS => 10, CURLOPT_TIMEOUT => 0, CURLOPT_FOLLOWLOCATION => true, CURLOPT_HTTP_VERSION => CURL_HTTP_VERSION_1_1, CURLOPT_CUSTOMREQUEST => 'GET', ));

$response = curl_exec($curl);

curl_close($curl); echo $response;

?>
于 2020-12-05T07:12:17.280 に答える
-1

For Valid JSON response use this code.. 

[WebService(Namespace = "http://tempuri.org/")]
[WebServiceBinding(ConformsTo = WsiProfiles.BasicProfile1_1)]
[System.ComponentModel.ToolboxItem(false)]
[ScriptService]
public class SampleService : System.Web.Services.WebService
{
    [WebMethod]
    [ScriptMethod(ResponseFormat = ResponseFormat.Json)]
    public void GetJsonServerProcess()
    {
        int memory = 1;
        string json = string.Empty;
        var obj = (System.Diagnostics.Process.GetProcesses().Where(r => r.WorkingSet64 > memory).Select(p => new { p.ProcessName, p.WorkingSet64 }).ToArray());
        json = Lib.ToJSON(obj);
       this.Context.Response.ContentType = "application/json; charset=utf-8";
            this.Context.Response.Write(json);

    }
}
于 2015-07-18T10:55:45.917 に答える