0

それぞれがまったく同じ計算列を作成する下に 3 つの select ステートメントがあり、その計算列のすべての yes とすべての no を数えます。現時点では、リージョンを 3 回表示し、その隣に 3 つの結果を表示しています。合計を含む3つの新しい列で地域を一度表示したいので、現時点では

私は持っている： 

region1 computedCol1

region1 computedCol2

region1 computedCol3

region2 computedCol1

region2 computedCol2

region2 computedCol3

私が欲しい：

Region1,  computedCol1, computedCol2, computedCol3

Region2,  computedCol1, computedCol2, computedCol3

Region3,  computedCol1, computedCol2, computedCol3

「ユニオンオール」を使用すると、次のようになります。

region1 computedCol1

region2 computedCol1

region3 computedCol1



SELECT a.region, COUNT(*) AS [computedCol1]    
(
SELECT  DISTINCT table1.serial1, table1.serial2, region,
    CASE WHEN table2.serial1 IS NULL THEN 'No' ELSE 'Yes' END AS [computedCol1],
    CASE WHEN table3.serial2 IS NULL THEN 'No' ELSE 'Yes' END AS [computedCol2],
    CASE WHEN table3.serial2 IS NULL AND table2.serial1 IS NULL THEN 'No' ELSE 'Yes' END AS [computedCol3]

FROM    table1
        LEFT JOIN table2
            ON table2.serial1 = table1.serial1
        LEFT JOIN dbo.EPG
            table3.serial2 = table1.serial2
)a
    WHERE region in (
        '37000','38000','39000','41000','42000','43000','44000','46000','45000','51000','52000','53000','54000',
        '55000','56000','57000','58000','59000','61000','62000','63000','64000','65000','66000','67000','68000',
        '69000','30000','33000','36000','34000','35000','31000','32000','N/A'   )
and [CCA Match Org] in  ('no')
    GROUP BY a.region

union

SELECT b.region, COUNT(*) AS [computedCol2], region   
(
SELECT  DISTINCT table1.serial1, table1.serial2,
    CASE WHEN table2.serial1 IS NULL THEN 'No' ELSE 'Yes' END AS [computedCol1],
    CASE WHEN table3.serial2 IS NULL THEN 'No' ELSE 'Yes' END AS [computedCol2],
    CASE WHEN table3.serial2 IS NULL AND table2.serial1 IS NULL THEN 'No' ELSE 'Yes' END AS [computedCol3]

FROM    table1
        LEFT JOIN table2
            ON table2.serial1 = table1.serial1
        LEFT JOIN dbo.EPG
            table3.serial2 = table1.serial2
)b
    WHERE region in     (
        '37000','38000','39000','41000','42000','43000','44000','46000','45000','51000','52000','53000','54000'
        '55000','56000','57000','58000','59000','61000','62000','63000','64000','65000','66000','67000','68000',
        '69000','30000','33000','36000','34000','35000','31000','32000','N/A'   )
and [CCA Match Org] in ('yes')
    group by b.region

union

SELECT c.region, COUNT(*) AS [computedCol3], region   
(
SELECT  DISTINCT table1.serial1, table1.serial2,
    CASE WHEN table2.serial1 IS NULL THEN 'No' ELSE 'Yes' END AS [computedCol1],
    CASE WHEN table3.serial2 IS NULL THEN 'No' ELSE 'Yes' END AS [computedCol2],
    CASE WHEN table3.serial2 IS NULL AND table2.serial1 IS NULL THEN 'No' ELSE 'Yes' END AS [computedCol3]

FROM    table1
        LEFT JOIN table2
            ON table2.serial1 = table1.serial1
        LEFT JOIN dbo.EPG
            table3.serial2 = table1.serial2
)c
    WHERE region in     (
        '37000','38000','39000','41000','42000','43000','44000','46000','45000','51000','52000','53000','54000'
        '55000','56000','57000','58000','59000','61000','62000','63000','64000','65000','66000','67000','68000',
        '69000','30000','33000','36000','34000','35000','31000','32000','N/A'   )
and [CCA Match Org] in ('yes', 'no')
    group by c.region
4

2 に答える 2

0

これが、UNIONがすべてのデータベースで機能する方法です。新しい列を作成するのではなく、すべての行を汚染します。

行から列への変換は、PIVOT演算子を使用して行われます。基本的に、PIVOTは、ピボットされていない列（この場合はRegion）で行をグループ化し、生成された各列に集計を適用します。

于 2012-06-01T14:38:24.787 に答える
0

他の回答が示唆するようにピボットを使用するか、SUM を CASE と組み合わせて使用​​して同じ結果を得ることができます。多数のcomputedcolsがある場合、これは苦痛になります。

例として Oracle を使用していますが、概念は SQLServer に変換する必要があります。

例：

SELECT 'A' region, 1 col_num, 10 computed_value FROM DUAL
UNION
SELECT 'A' region, 2 col_num, 11 computed_value FROM DUAL
UNION
SELECT 'A' region, 3 col_num, 12 computed_value FROM DUAL
UNION
SELECT 'B' region, 1 col_num, 20 computed_value FROM DUAL
UNION
SELECT 'B' region, 2 col_num, 21 computed_value FROM DUAL
UNION
SELECT 'B' region, 3 col_num, 22 computed_value FROM DUAL

これは以下を返します:

REGION  COL_NUM COMPUTED_VALUE
A           1   10
A           2   11
A           3   12
B           1   20
B           2   21
B           3   22

そのクエリを次のようにネストすると:

SELECT     region,
           SUM (CASE col_num WHEN 1 THEN computed_value ELSE NULL END) compulated_1,
           SUM (CASE col_num WHEN 2 THEN computed_value ELSE NULL END) compulated_2,
           SUM (CASE col_num WHEN 3 THEN computed_value ELSE NULL END) compulated_3
    FROM   (SELECT 'A' region, 1 col_num, 10 computed_value FROM DUAL
            UNION
            SELECT 'A' region, 2 col_num, 11 computed_value FROM DUAL
            UNION
            SELECT 'A' region, 3 col_num, 12 computed_value FROM DUAL
            UNION
            SELECT 'B' region, 1 col_num, 20 computed_value FROM DUAL
            UNION
            SELECT 'B' region, 2 col_num, 21 computed_value FROM DUAL
            UNION
            SELECT 'B' region, 3 col_num, 22 computed_value FROM DUAL)
GROUP BY   region

あなたにあげる：

REGION  COMPULATED_1    COMPULATED_2    COMPULATED_3
A           10          11           12
B           20          21           22
于 2012-06-01T17:40:53.343 に答える