android - Android remove button dynamically

Question

I have a button and when I press it, i want to remove it (not make it invisible). I read that I can do that using layout.removeView(mybutton) but what is the layout ? and how can I get it in my activity

Button showQuestion;
private void initialize() {
    showQuestion = (Button) findViewById(R.id.bAnswerQuestionShowQuestion);
}
public void onClick(View v) {
    switch (v.getId()) {
        case R.id.bAnswerQuestionShowQuestion:
                showQuestion.setVisibility(View.INVISIBLE);
                //Here i want to delete the button
                question.setVisibility(View.VISIBLE);
                theAnswer.setVisibility(View.VISIBLE);
                answerQuestion.setVisibility(View.VISIBLE);
                showChoices.setVisibility(View.VISIBLE);
                showHint.setVisibility(View.VISIBLE);
            break;
    }
}

score 18 · Accepted Answer

see link

ViewGroup layout = (ViewGroup) button.getParent();
if(null!=layout) //for safety only  as you are doing onClick
  layout.removeView(button);

score 14 · Accepted Answer

i have a button and when i press it , i want to remove it (not make it invisible)

=> You did as below:

 showQuestion.setVisibility(View.INVISIBLE);

Try with:

 showQuestion.setVisibility(View.GONE);

FYI, INVISIBLE just hide the view but physically present there and GONE hide as well remove the presence physically as well.

score 4 · Accepted Answer

4

You can use

      button.setVisibility(View.GONE);

于 2012-06-23T12:10:36.403 に答える

score 1 · Accepted Answer

Layout is the parent Layout of your Button, usually a RelativeLayout or LinearLayout.

You can get it as follows:

ViewParent layout = button.getParent();

android - Android remove button dynamically

4 に答える 4

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