3

だから私は動的にmysqlクエリであるPDOを使用してビルドして準備しようとしています。これが私のコードとデバッグ情報です。

$allowed_filters = array('hotels.star_rating', 'countries.id');

$where = 'WHERE 1 ';
if (!empty($data['filters'])){
    $where = 'WHERE';
    foreach ($data['filters'] as $field => $value){
        if (in_array($field, $allowed_filters)){
            $where .= " $field = :$field &&";
        }
        else unset($data['filters'][$field]);
    }

    $where = rtrim($where, '&&');
    $where = ($where == 'WHERE')? 'WHERE 1 ' : $where;
}

$st = $this->db->prepare("
    SELECT 
        hotels.code,
        hotels.name as name,
        hotels.star_rating,
        hotels.description,
        hotels.cover_image,
        countries.name as country,
        cities.name as city 
    FROM  
        hotels JOIN cities ON cities.id = hotels.city_id
        join countries on countries.id = cities.country_id
    $where
");

$st->execute($data['filters']);
var_dump($st->fetch());

$ st-> execute（$ data ['filters']）という行の直前に$stと$data['filters']をダンプしました。値は次のとおりです。

$stの値

PDOStatement Object
(
    [queryString] => 
        SELECT 
            hotels.code,
            hotels.name as name,
            hotels.star_rating,
            hotels.description,
            hotels.cover_image,
            countries.name as country,
            cities.name as city 
        FROM  
            hotels JOIN cities ON cities.id = hotels.city_id
            join countries on countries.id = cities.country_id
        WHERE 
            hotels.star_rating = :hotels.star_rating && 
            countries.id = :countries.id 
)

$data['filters']の値

Array
(
    [hotels.star_rating] => 4 stars
    [countries.id] => 5
)

PDOは例外をスローし、次のエラーで失敗します。

SQLSTATE [HY093]：無効なパラメーター番号：パラメーターが定義されていません'

ヘルプ？

4

1 に答える 1

1

:のキーのコロンを忘れました$data['filters']。そのはず：

Array
(
    [:hotels.star_rating] => 4 stars
    [:countries.id] => 5
)
于 2012-06-24T18:47:21.670 に答える