0

次のようなファイルがあります

Sever Name aad98722RHEL  20120630 075022

CPU
1 sec 10 sec 15 sec 1 min 1 hour
5     8      0      1     19

TX kbits/sec:

 interface  10 sec      1 min       10 min      1 hour      1 day 
 ---------  ------      -----       ------      ------      ----- 
 eth0       32          33          39          40          33 
 eth1       6           186         321         199         18 
 eth2       0           0           0           0           0 
 mgt0       0           0           0           0           0 

RX kbits/sec: 

 interface  10 sec      1 min       10 min      1 hour      1 day 
 ---------  ------      -----       ------      ------      ----- 
 eth0       19          19          25          26          23 
 eth1       9           26          40          28          10 
 eth2       0           0           0           0           0 
 mgt0       0           0           0           0           0 

Total memory usage:  1412916 kB 
Resident set size :  1256360 kB
Heap usage        :  1368212 kB 
Stack usage       :  84 kB 
Library size      :  16316 kB

私がプロデュースしたいのは、

aad98722RHE  20120630 075022  CPU  5     8      0      1     19 
aad98722RHE  20120630 075022  TX kbits/sec:  32          33          39          40          33       6           186         321         199      18        0           0           0           0           0        0           0           0           0           0 
aad98722RHE  20120630 075022  RX kbits/sec:  19          19          25          26          23       9           26          40          28       10        0           0           0           0           0        0           0           0           0           0 
aad98722RHE  20120630 075022 Total memory usage:  1412916 kB   Resident set size :  1256360 kB   Heap usage        :  1368212 kB   Stack usage       :  84 kB    Library size      :  16316 kB

これは Awk/Sed で行うことができますか?

4

2 に答える 2

1

おそらくそれはより良い解決策ではありませんが、うまくいきます。

ファイル: a.awk:

function print_cpu( server_name, cpu )  
{
    while ( $0 !~ cpu )                 
    {
        getline
    }    

    getline
    getline

    printf "%s %s ", server_name, cpu

    for ( i = 1; i < NF + 1; i++ )
    {
        printf "%s ", $i
    }

    printf "\n"
}

function print_rx_or_tx( server_name, rx_or_tx )
{
    while ( $0 !~ rx_or_tx )
    {
        getline    
    }

    getline 
    getline 
    getline 

    printf "%s %s ", server_name, rx_or_tx

    while ( $0 != "" )
    {
        getline

        for ( i = 2; i < NF; i++ )
        {
            printf "%s ", $i
        }    
    }

    printf "\n"
}

function print_stuff( server_name )
{
    while ( $0 == "" )
    {
        getline    
    }

    printf "%s ", server_name

    while ( $0 != "" )
    {
        printf "%s ", $0   

        if ( getline <= 0 )
        {
            break    
        }
    }

    printf "\n"
}

BEGIN { server = "Server Name"; cpu = "CPU"; tx = "TX kbits/sec:"; rx = "RX kbits/sec:" }

server { server_name = $3 " " $4 " " $5 }

! server  
{    
    print_cpu( server_name, cpu )
    print_rx_or_tx( server_name, tx  )
    print_rx_or_tx( server_name, rx  )
    print_stuff( server_name )
}

実行: awk -f a.awk your_input_file

于 2012-06-27T20:41:24.527 に答える
0

を使用した片道perl：

infileにあなたの質問のコンテンツと次のコンテンツがあると仮定しますscript.pl:

use warnings;
use strict;

my ($header, $newlines, $trans, @nums);

## Read input in paragraph mode.
local $/ = qq||;

while ( my $par = <> ) { 
    chomp $par;

    ## Save data of the header.
    if ( $. == 1 ) { 
        my @header = $par =~ m/\ASer?ver\s+Name\s+(\S+)\s+(\S+)\s+(\S+)\s*\Z/s;
        last unless @header;
        $header = join qq| |, @header;
        next;
    }   

    ## Number of '\n' in each paragraph (number of lines minus one).
    $newlines = $par =~ tr/\n/\n/;

    ## Three lines, the CPU info. Extract what I need and print.
    if ( $newlines == 2 ) { 
        printf qq|%s %s %s\n|, $header, $par =~ m/\A([^\n]+).*\n([^\n]+)\Z/s;
        next;
    }   

    ## Transmission string.
    if ( $newlines == 0 ) { 
        $trans = $par;
        next;
    }   

    ## Transmission info. Extract numbers and print.
    if ( $newlines == 5 ) { 
        my @lines = split /\n/, $par;
        for my $i ( 0 .. $#lines ) { 
            my @f = split /\s+/, $lines[ $i ];
            if ( grep { m/\D/ } @f[ 1 .. $#f ] ) { 
                next;
            }   
            else {
                push @nums, @f[ 1 .. $#f ];
            }   
        }   
        printf qq|%s %s\n|, $header, join qq| |, @nums;
        @nums = (); 
    }   

    ## Resume info. Extract and print.
    if ( $newlines == 4 ) { 
        $par =~ s/\n/\t/gs;
        printf qq|%s %s\n|, $header, $par;
    }   
}

次のように実行します。

perl script.pl infile

次の出力で：

aad98722RHEL 20120630 075022 CPU 5 8 0 1 19
aad98722RHEL 20120630 075022 32 33 39 40 33 6 186 321 199 18 0 0 0 0 0 0 0 0 0 0
aad98722RHEL 20120630 075022 19 19 25 26 23 9 26 40 28 10 0 0 0 0 0 0 0 0 0 0
aad98722RHEL 20120630 075022 Total memory usage: 1412916 kB     Resident set size : 1256360 kB  Heap usage : 1368212 kB Stack usage : 84 kB     Library size : 16316 kB
于 2012-06-27T18:05:10.213 に答える