0

Im thinking this is correct, but probably WAY off.

I have a string formatted as such name, name1, name2, name3, name4, etc

admins_count = 0
if ["name2", "name3"].include?(player_list)
  admins_count += 1
end

Is this the proper way to count matches in a list?

Essentially, its a list of players, I want to count how many of the names in the second list mtch against player_list.

this is what worked for me a combo of things

player_list = response[3].split(" ", 2)[1].chomp[1..-2]
admin_list = "Howard_Roark, Gerrit8500, fffizzz"
mod_list = "ZionRx, rodtang, fuzzamuzza, DJRedFlames, bingbong2715, ErebusAnima, Twentytenor2, zephyrnug, Tiberione, deadkill02, tTheoRyy, PyneApll, tercept, Hestehaven, Orjis87, Yaltar101"

mod_arr = mod_list.split(", ")
admin_arr = admin_list.split(", ")
player_arr = player_list.split(", ")

mods_count = 0
mod_arr.each do |s|
        mods_count += 1 if player_arr.include? s
end

admins_count = 0
admin_arr.each do |s1|
        admins_count += 1 if player_arr.include? s1
end

puts "players.value #{player_count}"
puts "mods.value #{mods_count}"
puts "admins.value #{admins_count}"
4

2 に答える 2

1

player_listが配列の場合、&演算子を使用できます。2つの配列を受け取り、2つの配列に共通する項目のみの新しい配列を返します（重複はありません）。 

# I'm assuming player_list becomes a string of 'name1, name2, name3...' after 
# the 'chomp' method
player_list = response[3].split(" ", 2)[1].chomp[1..-2].split(",").map(&:strip)
admins_count = (["name2", "name3"] & player_list).size

したがって、player_list「name2」が含まれている場合は、を返し["name2"]ます。次に、それを呼び出し.sizeて、に1割り当てられるものを取得しadmins_countます。

于 2012-06-28T16:15:09.200 に答える
1

私はこれがあなたが望むものの多くだと思います： 

formatted_string = "name,name1,name2,name3,name4";
string_arr = formatted_string.split(",")

string_arr.each do |s|
   admin_count += 1 if player_list.include? s
end
于 2012-06-28T16:15:13.597 に答える