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文字列内の文字列を拡張文字列に置き換える必要があります。

私の質問は、info内の文字列の位置を置き換えるたびに、元の文字列が変更されることです。Pythonの方法で文字列を更新するにはどうすればよいですか？

str = 'If you do not know where you are going, any road will get you there.'

info = {'you': [(3, 3), (25, 3)], 'get you': [(54, 7)], 'know': [(14, 4)]}

# replace 'you' from info with '<b>you</b>' and 'know' with '<i>know</i>'
# results in

str = 'If <b>you</b> do not <i>know</i> where <b>you</b> are going, any road will get you there.'

info = {'<b>you</b>': [(3, 10), (25, 10)], 'get you': [(54, 7)], '<i>know</i>': [(21, 11)]}

これまでの私の解決策：

str = 'If you do not know where you are going, any road will get you there.'
info = {'you': [(3, 3), (25, 3)], 'get you': [(54, 7)], 'know': [(14, 4)]}

replacer = [('you', '<b>you</b>'), ('know', '<i>know</i>')]

for s, s2 in replacer:
    print "replacing %s to %s and update position info dict" % (s, s2)

    old_s_pos = info[s]
    diff = len(s2) - len(s)

    new_key_pos = [(old_s_pos[0][0], old_s_pos[0][1] + diff)]

    old_s_pos = old_s_pos[1:]
    if old_s_pos:
        next_old_s_pos_start = old_s_pos[0][0]
    else:
        next_old_s_pos_start = None

    del info[s]

    for key, positions in info.iteritems():

        new_positions = []                    
        for i, (x,y) in enumerate(positions):

            if x < next_old_key_pos_start:
                new_positions.append((x + diff, y))
            else:
                new_positions.append((x, y))

                if next_old_s_pos_start is not None:
                    # update old_s_pos at first pair
                    new_key_pos.append((old_key_pos[0][0], old_s_pos[0][1] + diff))
                    old_s_pos = old_s_pos[1:]
                    if old_s_pos:
                        next_old_s_pos_start = old_s_pos[0][0]

        info[key] = new_positions
    info[s2] = new_key_pos

    print info

よろしく、マティアス

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1 に答える 1

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これは、文字列を逆方向に移動するだけで置き換える必要があるという考えに基づいています。まず、情報と置換の構造を少し変更する必要がありました。

str = 'If you do not know where you are going, any road will get you there.'
info = {'you': [(3, 3), (25, 3)], 'get you': [(54, 7)], 'know': [(14, 4)]}
replacer = [('you', '<b>you</b>'), ('know', '<i>know</i>')]

info2 = {}
replacer2 = {}

for original, replacement in replacer:
    replacer2[original] = replacement

for k, v in info.items():
    for start, length in v:
        replacement = None
        if k in replacer2:
            replacement = replacer2[k]
        info2[start] = (k, length, replacement)

for position in sorted(info2.iterkeys(), reverse=True):
    original, length, replacement = info2[position]
    if replacement is not None:
        str[:position] + replacement + str[position + length]

print str
于 2012-06-29T13:14:48.040 に答える