0

I have a login form and when I get to the page, it gives me automatically the alert message. I havn't put the username and password info yet.
Here is the page that does the verification of the login form input, Please see why it is behaving like that?

<?
session_start();
include "config.php";

if(isset($_SESSION["login_user"]) AND isset($_SESSION['pass_user'])){
    $login_user = $_SESSION["login_user"];
    $pass_user = $_SESSION["pass_user"];

$sql = mysql_query("SELECT * FROM adm WHERE login = '$login_user'");
$cont = mysql_num_rows($sql);
while($linha = mysql_fetch_array($sql)){
    $pass_db = $linha['pass'];
}

if($cont == 0){
    unset($_SESSION["login_user"]);
    unset($_SESSION["pass_user"]);

    echo "
    <META HTTP-EQUIV=REFRESH CONTENT='0; URL=login.php'>
    <script type=\"text/javascript\">
    alert(\"Name of user dont match.\");
    </script>";

}

if($pass_db != $pass_user){//check pass

    unset($_SESSION["login_user"]);
    unset($_SESSION["pass_user"]);

    echo "
    <META HTTP-EQUIV=REFRESH CONTENT='0; URL=login.php'>
    <script type=\"text/javascript\">
    alert(\"Password dont match.\");
    </script>";

}

}else{

    echo "
    <META HTTP-EQUIV=REFRESH CONTENT='0; URL=login.php'>
    <script type=\"text/javascript\">
    alert(\"User and password dont match.\");
    </script>";

}

?>
4

3 に答える 3

1

これは、次のifステートメントがfalseを返すためです。

if (isset($_SESSION["login_user"]) AND isset($_SESSION['pass_user']))

その場合、次のコードが実行されます。

} else {
    echo "
    <META HTTP-EQUIV=REFRESH CONTENT='0; URL=login.php'>
    <script type=\"text/javascript\">
    alert(\"User and password dont match.\");
    </script>";
}
于 2012-07-10T10:03:44.817 に答える
0

コードからelseステートメントを削除してください。今すぐ使用してください。

 <?php
session_start();

include "config.php";

if(isset($_SESSION["login_user"]) AND isset($_SESSION['pass_user'])){

$login_user = $_SESSION["login_user"];
$pass_user = $_SESSION["pass_user"];

$sql = mysql_query("SELECT * FROM adm WHERE login = '$login_user'");
$cont = mysql_num_rows($sql);
while($linha = mysql_fetch_array($sql)){
$pass_db = $linha['pass'];
}

if($cont == 0){

unset($_SESSION["login_user"]);
unset($_SESSION["pass_user"]);

echo "
<META HTTP-EQUIV=REFRESH CONTENT='0; URL=login.php'>
<script type=\"text/javascript\">
alert(\"Name of user dont match.\");
</script>";

 }

if($pass_db != $pass_user){//check pass

unset($_SESSION["login_user"]);
unset($_SESSION["pass_user"]);

echo "
<META HTTP-EQUIV=REFRESH CONTENT='0; URL=login.php'>
<script type=\"text/javascript\">
alert(\"Password dont match.\");
</script>";

}

}

?>
于 2012-07-10T10:03:37.400 に答える
0

あなたはelseを置き忘れただけだと思います：

<?
session_start();

include "config.php";

if(isset($_SESSION["login_user"]) AND isset($_SESSION['pass_user'])){

    $login_user = $_SESSION["login_user"];
    $pass_user = $_SESSION["pass_user"];

$sql = mysql_query("SELECT * FROM adm WHERE login = '$login_user'");
$cont = mysql_num_rows($sql);
while($linha = mysql_fetch_array($sql)){
    $pass_db = $linha['pass'];
}

if($cont == 0){

    unset($_SESSION["login_user"]);
    unset($_SESSION["pass_user"]);

    echo "
    <META HTTP-EQUIV=REFRESH CONTENT='0; URL=login.php'>
    <script type=\"text/javascript\">
    alert(\"Name of user dont match.\");
    </script>";

}

if($pass_db != $pass_user){//check pass

    unset($_SESSION["login_user"]);
    unset($_SESSION["pass_user"]);

    echo "
    <META HTTP-EQUIV=REFRESH CONTENT='0; URL=login.php'>
    <script type=\"text/javascript\">
    alert(\"Password dont match.\");
    </script>";

}else{

    echo "
    <META HTTP-EQUIV=REFRESH CONTENT='0; URL=login.php'>
    <script type=\"text/javascript\">
    alert(\"User and password dont match.\");
    </script>";

}
}
?>

ただし、@Davidが述べたように、パスワードだけが間違っていると指定しないでください。

于 2012-07-10T10:07:43.757 に答える