c# - Convert an object to an XML string

Question

I have got a class named WebserviceType I got from the tool xsd.exe from an XSD file.

Now I want to deserialize an instance of an WebServiceType object to a string. How can I do this?

The MethodCheckType object has as params a WebServiceType array.

My first try was like I serialized it: with a XmlSerializer and a StringWriter (while serializing I used a StringReader).

This is the method in which I serialize the WebServiceType object:

XmlSerializer serializer = new XmlSerializer(typeof(MethodCheckType));
        MethodCheckType output = null;
        StringReader reader = null;

        // catch global exception, logg it and throw it
        try
        {
            reader = new StringReader(path);
            output = (MethodCheckType)serializer.Deserialize(reader);
        }
        catch (Exception)
        {
            throw;
        }
        finally
        {
            reader.Dispose();
        }

        return output.WebService;

Edit:

Maybe I could say it in different words: I have got an instance of this MethodCheckType object an on the other hand I have got the XML document from which I serialized this object. Now I want to convert this instance into a XML document in form of a string. After this I have to proof if both strings (of XML documents) are the same. This I have to do, because I make unit tests of the first method in which I read an XML document into a StringReader and serialize it into a MethodCheckType object.

score 214 · Accepted Answer

両方向の変換方法は次のとおりです。this=クラスのインスタンス

public string ToXML()
    {
        using(var stringwriter = new System.IO.StringWriter())
        { 
            var serializer = new XmlSerializer(this.GetType());
            serializer.Serialize(stringwriter, this);
            return stringwriter.ToString();
        }
    }

 public static YourClass LoadFromXMLString(string xmlText)
    {
        using(var stringReader = new System.IO.StringReader(xmlText))
        {
            var serializer = new XmlSerializer(typeof(YourClass ));
            return serializer.Deserialize(stringReader) as YourClass ;
        }
    }

score 81 · Accepted Answer

これは非常に古い投稿であることは承知していますが、LB の回答を見て、受け入れられた回答を改善し、自分のアプリケーション用に一般化する方法を考えました。これが私が思いついたものです：

public static string Serialize<T>(T dataToSerialize)
{
    try
    {
        var stringwriter = new System.IO.StringWriter();
        var serializer = new XmlSerializer(typeof(T));
        serializer.Serialize(stringwriter, dataToSerialize);
        return stringwriter.ToString();
    }
    catch
    {
        throw;
    }
}

public static T Deserialize<T>(string xmlText)
{
    try
    {
        var stringReader = new System.IO.StringReader(xmlText);
        var serializer = new XmlSerializer(typeof(T));
        return (T)serializer.Deserialize(stringReader);
    }
    catch
    {
        throw;
    }
}

これらのメソッドは、静的ヘルパークラスに配置できるようになりました。つまり、シリアル化が必要なすべてのクラスでコードが重複することはありません。

score 21 · Accepted Answer

    public static string Serialize(object dataToSerialize)
    {
        if(dataToSerialize==null) return null;

        using (StringWriter stringwriter = new System.IO.StringWriter())
        {
            var serializer = new XmlSerializer(dataToSerialize.GetType());
            serializer.Serialize(stringwriter, dataToSerialize);
            return stringwriter.ToString();
        }
    }

    public static T Deserialize<T>(string xmlText)
    {
        if(String.IsNullOrWhiteSpace(xmlText)) return default(T);

        using (StringReader stringReader = new System.IO.StringReader(xmlText))
        {
            var serializer = new XmlSerializer(typeof(T));
            return (T)serializer.Deserialize(stringReader);
        }
    }

c# - Convert an object to an XML string

5 に答える 5

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