python - ネストされたリスト内包表記と同等

Question

次のコードをリスト内包表記に置き換えることはできますか?

input = ['1\t2,3\t4,5', '61\t7,8\t9,0']

res = []
li = [i.split() for i in input]
for i in li:
    l = [i[0]]
    l = l + [e.split(',') for e in i[1:]]
    res.append(l)

問題は、すべてのサブリストの最初の要素を残りの要素とは異なる方法で処理する必要があることです。

Answer 1

読みやすさを考えると、これは実際にはPythonicではないと言わざるを得ません。

>>> l = ['1\t2,3\t4,5', '61\t7,8\t9,0']
>>> [[i[0]]+[e.split(',') for e in i[1:]] for i in [x.split() for x in l]]
[['1', ['2', '3'], ['4', '5']], ['61', ['7', '8'], ['9', '0']]]

Answer 2

>>> input = ['1\t2,3\t4,5', '61\t7,8\t9,0']
>>> 
>>> [[a.split()[0]] + [b.split(',') for b in a.split()[1:]] for a in input]
[['1', ['2', '3'], ['4', '5']], ['61', ['7', '8'], ['9', '0']]]

Answer 3

>>> import csv
>>> data = ['1\t2,3\t4,5', '61\t7,8\t9,0']
>>> [x[:1] + list(csv.reader(x[1:], delimiter=','))
     for x in csv.reader(data, delimiter='\t')]
[['1', ['2', '3'], ['4', '5']], ['61', ['7', '8'], ['9', '0']]]