1

これが私の質問です

CREATE view pivmehis WITH ENCRYPTION
as 
SELECT APPROVED, [Not Approved] as REJECT, NULL
FROM 
(SELECT MgtApproval
from LeaveRequest) l
PIVOT 
(
Sum (SchedId) --I DON'T WANT TO SUM THIS COLUMN
FOR MgtApproval IN 
([APPROVED], [REJECT], [NULL])) as pvt

元のテーブルの結果:

MgtApproval      SchedId
Approved           1
Reject             2
Null               3
Approved           4
Reject             5
Null               6

これが私が見たい結果です:

Approved    Reject        Null
1           2           3         
4           5           6         
4

1 に答える 1

5
SELECT  rn, APPROVED, [Not Approved] as REJECT, NULL
FROM    (
        SELECT  MgtApproval, SchedID, ROW_NUMBER() OVER (PARTITION BY mgtapproval ORDER BY SchedID) AS rn
        FROM    LeaveRequest
        ) l
        PIVOT 
        (
        MIN(SchedId)
        FOR     MgtApproval IN 
                ([APPROVED], [Not Approved], [NULL])
        ) as pvt

PIVOTまだ集計関数が必要ですが、これは最大で1つの列に集計されることが保証されています。

必要なものを正確に返すサンプルデータのクエリは次のとおりです。

WITH leaveRequest aS
(
SELECT 'APPROVED' AS mgtapproval, 1 AS SchedID
UNION ALL
SELECT 'Reject' AS mgtapproval, 2 AS SchedID
UNION ALL
SELECT 'NULL' AS mgtapproval, 3 AS SchedID
UNION ALL
SELECT 'APPROVED' AS mgtapproval, 4 AS SchedID
UNION ALL
SELECT 'Reject' AS mgtapproval, 5 AS SchedID
UNION ALL
SELECT 'NULL' AS mgtapproval, 6 AS SchedID
)
SELECT  APPROVED, REJECT, [NULL]
FROM    (
        SELECT  MgtApproval, SchedID, ROW_NUMBER() OVER (PARTITION BY mgtapproval ORDER BY SchedID) AS rn
        FROM    LeaveRequest
        ) l
        PIVOT 
        (
        MIN(SchedId)
        FOR     MgtApproval IN 
                ([APPROVED], [Reject], [Null])
        ) as pvt

アップデート:

列が実際にはであると述べたので、次のbit構文を使用する必要があります。

SELECT  [1] AS approved, [0] AS reject, [-1] AS nil
FROM    (
        SELECT  COALESCE(MgtApproval, -1) AS MgtApproval, SchedID, ROW_NUMBER() OVER (PARTITION BY mgtapproval ORDER BY SchedID) AS rn
        FROM    LeaveRequest
        ) l
        PIVOT 
        (
        MIN(SchedId)
        FOR     MgtApproval IN 
                ([1], [0], [-1])
        ) as pvt
于 2009-07-21T15:46:44.710 に答える