c++ - C++ string to fixed sized char array possible?

Question

Hi i have the following code:

char msg[10000];
string mystr = "hello";

I want to put mystr into msg. Is there a way to do that? I tried all sorts of methods, but keep getting:

incompatible types in assignment of 'const char*' to char [10000]'

I tried:

msg = mystr.c_str();

and

msg = (char[10000])mystr;

to no avail.

score 6 · Accepted Answer

これを試すことができますstd::copy。何かのようなもの：

std::copy(mystr.begin(), mystr.end(), msg);

C++のやのCような文字列関数は避けます。mempcystrcpy

score 3 · Accepted Answer

string::copyを見てください- 文字列を取り、それを配列に入れます。

あなたの場合は次のようになります。

std::size_t length = mystr.copy(msg,10000);
msg[length]='\0';

score 1 · Accepted Answer

std::string のコピーメンバー関数を使用します。

size_t len = mystr.copy(msg, (sizeof msg)-1);
msg[len] = 0;

score 1 · Accepted Answer

1

char msg[10000];
string mystr = "hello";

strcpy(msg, mystr.c_str());
cout<<msg;

于 2012-07-24T07:21:06.323 に答える

score 0 · Accepted Answer

C での文字列の割り当ては異なります。バイトを宛先文字列にコピーする必要があります。

memcpy_s(msg, 1000, mystr.c_str(), mystr.length()) // safe windows version

memcpy(msg, mystr.c_str(), mystr.length()) // unix version

score 0 · Accepted Answer

strcpy 関数を使用: http://www.cplusplus.com/reference/clibrary/cstring/strncpy/

strncpy(msg, mystr.c_str(), sizeof msg / sizeof msg[0]);
msg[sizeof msg / sizeof msg[0] - 1] = 0; // null-terminate in case of truncation

score 0 · Accepted Answer

コンパイラは、配列型に対して不安定なエラーメッセージを生成することがあります。

これは、貼り付けてコンパイルするプログラムへの以前の回答の蓄積です。

#include <string>
#include <iostream>

#if 1

int main(int argc, char **argv)
{
    using std::cout;
    using std::endl;

    char msg[1000] = {0};    // initialize to 0 here since we're printing below
                            // the <type> <array-name>[<size>] = {0} just fills a POD struct or an array with 0s

    std::string mystr = "hello";

    // if, at some point, you have things changing "mystr"
    // you'll need to make sure that it will fit in msg[]

    cout << "Before strcpy: \"" << msg << "\"" << endl;

    // I'll just finish the statement in mystr...
    mystr += " world!";

    if(mystr.length() < sizeof(msg)){
        strcpy(
            msg,            // <- put in here until we find a '\0'
            mystr.c_str()    // <- take from here (which could be a temporary buffer)
            );
    }

    //MSC will complain about strcpy being unsafe
    //
    // you can use the below instead (if you really feel the need to), which is
    // the MS-specific equivalent to the above.
    /*
        strcpy_s(
            msg,            // <- put in here until we find a '\0' or the size limit is reached
            sizeof(msg),    // <- don't put any more than this many chars in msg
            mystr.c_str()    // <- take from here
            );
    */

    cout << "After strcpy: \"" << msg << "\"" << endl;

    return 0;
}

#else

// Similarly, using wchar_t (a usually non-byte-sized character type)
//
// note where the divisions occurr

int main(int argc, char **argv)
{
    using std::wcout;
    using std::endl;

    wchar_t msg[1000] = {0};
    std::wstring mystr = L"hello";

    wcout << "Before strcpy: \"" << msg << "\"" << endl;

    mystr += L" world";

    if(mystr.length() < (sizeof(msg)/sizeof(wchar_t))){
        // mystr wil fit!
        wcscpy(
            msg,            // <- put in here until we find a '\0'
            mystr.c_str()    // <- take from here (which could be a temporary buffer)
            );
    }

    // Similar to the char case in the first preprocessor block
    /*
        wcscpy_s(
            msg,                            // <- put in here until we find a '\0' or the size limit is reached
            sizeof(msg)/sizeof(wchar_t),    // <- don't put any more than this many wchar_ts in msg
            mystr.c_str()                    // <- take from here
            );
    */

    wcout << "After strcpy: \"" << msg << "\"" << endl;

    return 0;
}

#endif

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c++ - C++ string to fixed sized char array possible?

7 に答える 7

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