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各ループの結果が異なる列に出力され、すべてが1つのテーブルに出力されるpl/sqlクエリ関数でループを設定するにはどうすればよいですか。

機能は次のとおりです。

select t1.aaa, coalesce(t2.bbb_count, 0) bbb_count,
    coalesce(t2.ccc_sum, 0) ccc_sum
from (
  select distinct aaa
  from nrb
) t1
left join (
  select t.aaa, count (t.bbb) bbb_count, sum (t.ccc) ccc_sum
  from nrb t
  where t.vvv IN  ('3','4','5','6','D','E','F')
    and t.ddd like '50%'
    and t.eee >= TO_DATE('2012/03/21','YYYY/MM/DD')
    and t.eee <= TO_DATE('2012/07/21','YYYY/MM/DD')
  group by t.aaa
) t2 on t1.aaa = t2.aaa
order by t1.aaa;

この関数は、200 行 3 列のテーブルを提供します。私はループを作る必要があります

" そして t.ddd は '50%' のように"

line 、50から55まで。つまり、結果は200行と15列になります。

Pl/sql 7.0.2 無制限のユーザー ライセンス

oci: 9.2

Oracle データベース: 11.1.0.6.0 エンタープライズ

OS：XPに勝つ

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1 に答える 1

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select t1.aaa, 
       coalesce(t2.bbb_count, 0) bbb_50_count, coalesce(t2.ccc_sum, 0) ccc_50_sum,
       coalesce(t3.bbb_count, 0) bbb_51_count, coalesce(t3.ccc_sum, 0) ccc_51_sum,
       coalesce(t4.bbb_count, 0) bbb_52_count, coalesce(t4.ccc_sum, 0) ccc_52_sum,
       coalesce(t5.bbb_count, 0) bbb_53_count, coalesce(t5.ccc_sum, 0) ccc_53_sum,
       coalesce(t6.bbb_count, 0) bbb_54_count, coalesce(t6.ccc_sum, 0) ccc_54_sum,
       coalesce(t7.bbb_count, 0) bbb_55_count, coalesce(t7.ccc_sum, 0) ccc_55_sum
from (
  select distinct aaa
  from nrb
) t1
left join (
  select t.aaa, count (t.bbb) bbb_count, sum (t.ccc) ccc_sum
  from nrb t
  where t.vvv IN  ('3','4','5','6','D','E','F')
    and t.ddd like '50%'
    and t.eee >= TO_DATE('2012/03/21','YYYY/MM/DD')
    and t.eee <= TO_DATE('2012/07/21','YYYY/MM/DD')
  group by t.aaa
) t2 on t1.aaa = t2.aaa
left join (
  select t.aaa, count (t.bbb) bbb_count, sum (t.ccc) ccc_sum
  from nrb t
  where t.vvv IN  ('3','4','5','6','D','E','F')
    and t.ddd like '51%'
    and t.eee >= TO_DATE('2012/03/21','YYYY/MM/DD')
    and t.eee <= TO_DATE('2012/07/21','YYYY/MM/DD')
  group by t.aaa
) t3 on t1.aaa = t3.aaa
left join (
  select t.aaa, count (t.bbb) bbb_count, sum (t.ccc) ccc_sum
  from nrb t
  where t.vvv IN  ('3','4','5','6','D','E','F')
    and t.ddd like '52%'
    and t.eee >= TO_DATE('2012/03/21','YYYY/MM/DD')
    and t.eee <= TO_DATE('2012/07/21','YYYY/MM/DD')
  group by t.aaa
) t4 on t1.aaa = t4.aaa
left join (
  select t.aaa, count (t.bbb) bbb_count, sum (t.ccc) ccc_sum
  from nrb t
  where t.vvv IN  ('3','4','5','6','D','E','F')
    and t.ddd like '53%'
    and t.eee >= TO_DATE('2012/03/21','YYYY/MM/DD')
    and t.eee <= TO_DATE('2012/07/21','YYYY/MM/DD')
  group by t.aaa
) t5 on t1.aaa = t5.aaa
left join (
  select t.aaa, count (t.bbb) bbb_count, sum (t.ccc) ccc_sum
  from nrb t
  where t.vvv IN  ('3','4','5','6','D','E','F')
    and t.ddd like '54%'
    and t.eee >= TO_DATE('2012/03/21','YYYY/MM/DD')
    and t.eee <= TO_DATE('2012/07/21','YYYY/MM/DD')
  group by t.aaa
) t6 on t1.aaa = t6.aaa
left join (
  select t.aaa, count (t.bbb) bbb_count, sum (t.ccc) ccc_sum
  from nrb t
  where t.vvv IN  ('3','4','5','6','D','E','F')
    and t.ddd like '55%'
    and t.eee >= TO_DATE('2012/03/21','YYYY/MM/DD')
    and t.eee <= TO_DATE('2012/07/21','YYYY/MM/DD')
  group by t.aaa
) t7 on t1.aaa = t7.aaa
order by t1.aaa;
于 2012-07-29T05:49:37.960 に答える