sql - 異なる WHERE 条件での SELECT

Question

このようなものを選択して実行したいと思います。

SELECT
        COUNT(*) WHERE switch=0 AND detail=1 AS zeroone
    AND
        COUNT(*) WHERE switch=0 AND detail=2 AS zerotwo
    AND
        COUNT(*) WHERE switch=1 AND detail=1 AS oneone
    AND 
        COUNT(*) WHERE swithc=1 AND detail=2 AS onetwo
  FROM tablename

これを行う方法はありますか？

score 4 · Accepted Answer

CASEでステートメントを使用しSELECTて、結果を取得できます。

SELECT SUM(case when switch=0 AND detail=1 then 1 else 0 end) as zeroone
    , SUM(case when switch=0 AND detail=2 then 1 else 0 end) as zerotwo
    , SUM(case when switch=1 AND detail=1 then 1 else 0 end) as oneone
    , SUM(case when switch=1 AND detail=2 then 1 else 0 end) as onetw
FROM tablename

score 4 · Accepted Answer

SELECT
    sum(switch=0 AND detail=1) AS zeroone,
    sum(switch=0 AND detail=2) AS zerotwo,
    sum(switch=1 AND detail=1) AS oneone,
    sum(switch=1 AND detail=2) AS onetwo
FROM tablename

score 1 · Accepted Answer

SELECT SUM(CASE WHEN switch = 0 and detail = 1 THEN 1 ELSE NULL END) AS zeroone
     , ...
FROM TableName

score 0 · Accepted Answer

何が欲しいのかはっきりしていません。

4つの列を持つ1つの行を返すselectが必要だと思います。

SELECT
COUNT(*) WHERE switch=0 AND detail=1 AS zeroone,
COUNT(*) WHERE switch=0 AND detail=2 AS zerotwo,
COUNT(*) WHERE switch=1 AND detail=1 AS oneone,
COUNT(*) WHERE swithc=1 AND detail=2 AS onetwo
FROM tablename

score 0 · Accepted Answer

なぜこれを使わないのですか？

SELECT COUNT(*) 
  FROM tablename
 GROUP BY switch, detail

sql - 異なる WHERE 条件での SELECT

5 に答える 5

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