python - 無効な構文 ---python

Question

すべての If ステートメントでオプションという単語の構文が無効であると言っている理由がわかりません

Options = raw_input("Would you like to Square, Cube, Multiply, or Divide?    ")

If  Options == "Square" or Options == "square":
Square = int(raw_input("What number would you like to Square?    "))
Answer1 = Square ** 2
print "The answer is :%d" %Answer1

if Options == "Cube":
Cube = int(raw_input("What number would you like to Cube    "))
Answer2 = Cube ** 3
print "The answer is :%d" %Answer2

if Options == "Multiply":
Multiply1 = int(raw_input("What is the first number to multiply?    "))
Multiply2 = int(raw_input("What is the second number to multiply?     "))
Answer3 = Multiply1 * Multiply2
 print "The answer is :d%" %Answer3"

Answer 1

Python では大文字と小文字が区別されます。Ifである必要がありますif。コードも適切にインデントする必要があります。