0

長いクエリがありましたが、代わりに結合を使用して短縮しました。結果のクエリは次のようになりますが、それでもサブクエリがあります。このサブクエリを結合に変換する方法

SELECT 
    pav.post_id as Id, img.path as Path, attr.name as Name, pc.title as Category, pav.value_text as Valuess, post.created_on as createdOn 
FROM 
    postings post inner join post_attributes_values pav on post.post_id = pav.post_id
    left outer join images img on post.post_id = img.post_id and img.sequence='1' 
    inner join attributes attr on pav.attr_id = attr.attr_id 
    inner join categories_parent_categories pc on attr.cat_id = pc.category_id 
where 
    pav.post_id in  (select distinct post_id from post_attributes_values where value_text = 'SFX')
4

2 に答える 2

1

Matei の回答に対する最後のコメントを読んだ後、属性の 1 つに「SFX」の値が含まれるすべての投稿が実際に必要であることに気付きました。私の理解が正しければ、派生テーブルを追加して post_id で結合するしかありません。

SELECT pav.post_id     AS Id,
       img.path        AS Path,
       attr.name       AS Name,
       pc.title        AS Category,
       pav.value_text  AS Valuess,
       post.created_on AS createdOn
FROM   postings post
       INNER JOIN post_attributes_values pav
               ON post.post_id = pav.post_id
       LEFT OUTER JOIN images img
                    ON post.post_id = img.post_id
                       AND img.sequence = '1'
       INNER JOIN attributes attr
               ON pav.attr_id = attr.attr_id
       INNER JOIN categories_parent_categories pc
               ON attr.cat_id = pc.category_id
       INNER JOIN
       (
             SELECT DISTINCT post_id
             FROM   post_attributes_values
             WHERE  value_text = 'SFX'
       ) sfxPosts
               ON pav.post_id = sfxPosts.post_id

(クエリはインスタント SQL フォーマッタのおかげで再フォーマットされました。)

于 2012-08-03T11:31:09.160 に答える
0

もしかしてこれ？テストしてください

SELECT 
    pav.post_id as Id, img.path as Path, attr.name as Name, pc.title as Category, pav.value_text as Valuess, post.created_on as createdOn 
FROM 
    postings post 
  inner join post_attributes_values pav on post.post_id = pav.post_id AND pav.value_text = 'SFX'
  left outer join images img on post.post_id = img.post_id and img.sequence='1' 
  inner join attributes attr on pav.attr_id = attr.attr_id 
  inner join categories_parent_categories pc on attr.cat_id = pc.category_id
于 2012-08-03T10:53:14.803 に答える