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I have a table called items_status which has 3 fields, item_id, user_id, and status, which can be either 'have' or 'want'.

Field   Type                Null    Key 
user_id varchar(10)         NO      PRI     
item_id varchar(10)         NO      PRI     
status  set('have','want')  YES     NULL

I have a page where I want to get a list of all the user ids in the table ordered by the number of records their user id is associated with in the table where status is 'have'. So far, this is the best I can come up with:

SELECT user_id 
FROM items_status AS is  
ORDER BY 
    //Subquery to get number of items had by user
    (SELECT COUNT(i.item_id) 
          FROM items_status AS i 
          WHERE i.user_id = is.user_id AND i.status = 'have') DESC
GROUP BY user_id

However, this pulls up an error on the subquery. How can I get all of the user ids in the table ordered by the number of items they have?

4

2 に答える 2

2

あなたはこのようにそれを行うことができます：

SELECT  user_id
FROM    items_status
WHERE   `status` = 'have'
GROUP BY userID
ORDER BY COUNT(user_id) DESC

SQLFiddleデモ

列名にわずかな違いがありますが、クエリは同じです

于 2012-08-10T15:33:02.763 に答える
0 
SELECT user_id, SUM(CASE WHEN i.status = 'have' THEN 1 ELSE 0) AS s
FROM items_status AS is
GROUP BY user_id
ORDER BY  SUM(CASE WHEN i.status = 'have' THEN 1 ELSE 0) DESC
于 2012-08-10T15:34:07.580 に答える