Python 用の Amazon 製品 API を使用していますが、次のようなエラーが常に発生します。
File "/usr/local/lib/python2.7/dist-packages/amazonproduct/paginators.py", line 47, in __iter__
yield self.page(self.current + 1)
File "/usr/local/lib/python2.7/dist-packages/amazonproduct/paginators.py", line 54, in page
root = self.fun(*self.args, **self.kwargs)
File "/usr/local/lib/python2.7/dist-packages/amazonproduct/paginators.py", line 75, in <lambda>
method = lambda *a, **b: fnc(api, *a, **b)
File "/usr/local/lib/python2.7/dist-packages/amazonproduct/api.py", line 360, in item_search
SearchIndex=search_index, **params)
File "/usr/local/lib/python2.7/dist-packages/amazonproduct/api.py", line 281, in call
fp = self._fetch(url)
File "/usr/local/lib/python2.7/dist-packages/amazonproduct/contrib/retry.py", line 38, in _fetch
return API._fetch(self, url)
File "/usr/local/lib/python2.7/dist-packages/amazonproduct/api.py", line 208, in _fetch
response = opener.open(request)
File "/usr/lib/python2.7/urllib2.py", line 400, in open
response = self._open(req, data)
File "/usr/lib/python2.7/urllib2.py", line 418, in _open
'_open', req)
File "/usr/lib/python2.7/urllib2.py", line 378, in _call_chain
result = func(*args)
File "/usr/lib/python2.7/urllib2.py", line 1207, in http_open
return self.do_open(httplib.HTTPConnection, req)
File "/usr/lib/python2.7/urllib2.py", line 1180, in do_open
r = h.getresponse(buffering=True)
File "/usr/lib/python2.7/httplib.py", line 1030, in getresponse
response.begin()
File "/usr/lib/python2.7/httplib.py", line 407, in begin
version, status, reason = self._read_status()
File "/usr/lib/python2.7/httplib.py", line 365, in _read_status
line = self.fp.readline()
File "/usr/lib/python2.7/socket.py", line 447, in readline
data = self._sock.recv(self._rbufsize)
socket.timeout: timed out
これは何を意味し、どうすれば修正できますか? Amazonが一時的に私をブロックしているだけですか？(私のスクリプトは一定の API 呼び出しを実行します) スクリプトを再起動すると、少し実行されますが、その後再び停止します。