Twitter というボタンがあります。これをクリックすると、通常、ツイート用のビューが表示されTWTweetComposeViewController
ます。メッセージをツイートするには、自動共有と通常の共有の 2 つの方法があります。TWTweetComposeViewController
ビューと完了ボタンをクリックします。
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最後に、ios5 で Twitter に関連する非常に多くの質問を検索し、twitter Developer Document も読んで、この回答を試しました。これは、自動共有を行うための解決策の 1 つだと思います。
ACAccountStore *account = [[ACAccountStore alloc] init];
ACAccountType *accountType = [account accountTypeWithAccountTypeIdentifier:ACAccountTypeIdentifierTwitter];
// Request access from the user to access their Twitter account
[account requestAccessToAccountsWithType:accountType withCompletionHandler:^(BOOL granted, NSError *error) {
// Did user allow us access?
if (granted == YES)
{
// Populate array with all available Twitter accounts
NSArray *arrayOfAccounts = [account accountsWithAccountType:accountType];
// Sanity check
if ([arrayOfAccounts count] > 0)
{
// Keep it simple, use the first account available
ACAccount *acct = [arrayOfAccounts objectAtIndex:0];
NSURL *url =
[NSURL URLWithString:
@"https://upload.twitter.com/1/statuses/update_with_media.json"];
// Create a POST request for the target endpoint
TWRequest *request =
[[TWRequest alloc] initWithURL:url
parameters:nil
requestMethod:TWRequestMethodPOST];
// self.accounts is an array of all available accounts;
// we use the first one for simplicity
[request setAccount:acct];
// The "larry.png" is an image that we have locally
UIImage *image = (UIImage *)[dictionarydata valueForKey:@"image"];
NSLog(@"%@",image);
if (image!=nil) {
// Obtain NSData from the UIImage
NSData *imageData = UIImagePNGRepresentation(image);
// Add the data of the image with the
// correct parameter name, "media[]"
[request addMultiPartData:imageData
withName:@"media[]"
type:@"multipart/form-data"];
// NB: Our status must be passed as part of the multipart form data
NSString *status = [NSString stringWithFormat:@"%@ %@ %@",[dictionaryData valueForKey:@"firstname"],[dictionaryData valueForKey:@"lastname"],[dictionarydata valueForKey:@"title"]];
// Add the data of the status as parameter "status"
[request addMultiPartData:[status dataUsingEncoding:NSUTF8StringEncoding]
withName:@"status"
type:@"multipart/form-data"];
// Perform the request.
// Note that -[performRequestWithHandler] may be called on any thread,
// so you should explicitly dispatch any UI operations to the main thread
[request performRequestWithHandler:
^(NSData *responseData, NSHTTPURLResponse *urlResponse, NSError *error) {
NSDictionary *dict =
(NSDictionary *)[NSJSONSerialization
JSONObjectWithData:responseData options:0 error:nil];
// Log the result
NSLog(@"%@", dict);
dispatch_async(dispatch_get_main_queue(), ^{
// perform an action that updates the UI...
});
}];
}else{
NSURL *url = [NSURL URLWithString:@"https://api.twitter.com/1/statuses/update.json"];
NSDictionary *p = [NSDictionary dictionaryWithObjectsAndKeys:
[NSString stringWithFormat:@"%@ %@ %@",[dictionaryData valueForKey:@"firstname"],[dictionaryData valueForKey:@"lastname"],[dictionarydata valueForKey:@"title"]], @"status",
nil
];
TWRequest *postRequest = [[TWRequest alloc]
initWithURL: url
parameters: p
requestMethod: TWRequestMethodPOST
];
// Post the request
[postRequest setAccount:acct];
// Block handler to manage the response
[postRequest performRequestWithHandler:^(NSData *responseData, NSHTTPURLResponse *urlResponse, NSError *error) {
NSLog(@"Twitter response, HTTP response: %i", [urlResponse statusCode]);
}];
}
}
}
}];
于 2012-08-30T06:13:14.873 に答える