2

私はksoap2を使用してAndroidでJavaWebサービスを呼び出しています。Java Webサービスの方法は、

ImageProcessImpl.java

public UserResponse sample(UserRequest userRequest) {
     return ImageProcessDAO.sample(userRequest);
}

ImageProcessDAO.java

public static String sample(UserRequest userRequest) {
     System.out.println(userRequest.getClientName());
     UserResponse UserResponse = new UserResponse();
     userResponse.setMessage("SUCCESS");
     return userResponse;
}

私はAndroidからこれらのWebサービスを次のように呼んでいます。

try{
        String NAMESPACE = "http://impl.test.com";
        String URL = "http://10.0.2.2:8080/Webservice/services/ImageProcessImpl?wsdl";  
        String SOAP_ACTION = "http://impl.test.com/sample";
        String METHOD_NAME = "sample";

        SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME); 

        UserRequest userRequest = new UserRequest();            
        userRequest.setClientName("Test");

        PropertyInfo pi = new PropertyInfo();
        pi.setName("userRequest");
        pi.setValue(userRequest);
        pi.setType(UserRequest.class);
        request.addProperty(pi);

        SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11); 
        envelope.setOutputSoapObject(request);  
        envelope.implicitTypes = true;
        envelope.addMapping(NAMESPACE, "UserResponse", UserResponse.class);

        AndroidHttpTransport httpTransport = new AndroidHttpTransport(URL);  
        httpTransport.debug = true;
        httpTransport.call(SOAP_ACTION, envelope);

       UserResponse response = (UserResponse) envelope.getResponse(); 
       Log.e(Test.LOG_TAG, response.getMessage());
        }catch (Exception e) {
            Log.e(Test.LOG_TAG, "throws an exception: " + e.getMessage());
        }

しかし、Logcatで「例外をスローします：シリアル化できません：com.test.common.UserRequest」というエラーが発生します。このエラーを修正するにはどうすればよいですか？これは、複雑なタイプのWebサービスを呼び出す正しい方法ですか？

私のwsdlファイルは、

<?xml version="1.0" encoding="UTF-8"?>
<wsdl:definitions targetNamespace="http://impl.test.com" xmlns:apachesoap="http://xml.apache.org/xml-soap" xmlns:impl="http://impl.test.com" xmlns:intf="http://impl.test.com" xmlns:tns1="http://common.test.com" xmlns:wsdl="http://schemas.xmlsoap.org/wsdl/" xmlns:wsdlsoap="http://schemas.xmlsoap.org/wsdl/soap/" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<!--WSDL created by Apache Axis version: 1.4
Built on Apr 22, 2006 (06:55:48 PDT)-->
 <wsdl:types>
  <schema elementFormDefault="qualified" targetNamespace="http://impl.test.com" xmlns="http://www.w3.org/2001/XMLSchema">
   <import namespace="http://common.test.com"/>
   <element name="sample">
    <complexType>
     <sequence>
      <element name="userRequest" type="tns1:UserRequest"/>
     </sequence>
    </complexType>
   </element>
   <element name="sampleResponse">
    <complexType>
     <sequence>
      <element name="sampleReturn" type="tns1:UserResponse"/>
     </sequence>
    </complexType>
   </element>
  </schema>
  <schema elementFormDefault="qualified" targetNamespace="http://common.test.com" xmlns="http://www.w3.org/2001/XMLSchema">
   <complexType name="UserRequest">
    <sequence>
     <element name="clientName" nillable="true" type="xsd:string"/>
    </sequence>
   </complexType>
   <complexType name="UserResponse">
    <sequence>
     <element name="message" nillable="true" type="xsd:string"/>
    </sequence>
   </complexType>
  </schema>
 </wsdl:types>

   <wsdl:message name="sampleRequest">

      <wsdl:part element="impl:sample" name="parameters">

      </wsdl:part>

   </wsdl:message>

   <wsdl:message name="sampleResponse">

      <wsdl:part element="impl:sampleResponse" name="parameters">

      </wsdl:part>

   </wsdl:message>

   <wsdl:portType name="ImageProcessImpl">

      <wsdl:operation name="sample">

         <wsdl:input message="impl:sampleRequest" name="sampleRequest">

       </wsdl:input>

         <wsdl:output message="impl:sampleResponse" name="sampleResponse">

       </wsdl:output>

      </wsdl:operation>

   </wsdl:portType>

   <wsdl:binding name="ImageProcessImplSoapBinding" type="impl:ImageProcessImpl">

      <wsdlsoap:binding style="document" transport="http://schemas.xmlsoap.org/soap/http"/>
      <wsdl:operation name="sample">

         <wsdlsoap:operation soapAction=""/>

         <wsdl:input name="sampleRequest">

            <wsdlsoap:body use="literal"/>

         </wsdl:input>

         <wsdl:output name="sampleResponse">

            <wsdlsoap:body use="literal"/>

         </wsdl:output>

      </wsdl:operation>

   </wsdl:binding>

   <wsdl:service name="ImageProcessImplService">

      <wsdl:port binding="impl:ImageProcessImplSoapBinding" name="ImageProcessImpl">

         <wsdlsoap:address location="http://localhost:8080/Webservice/services/ImageProcessImpl"/>

      </wsdl:port>

   </wsdl:service>

</wsdl:definitions>

KvmSerializableを使用しました。private Client[] clientNameList = null;UserRequest.javaにもう1つの配列Bean変数を追加 しました。

Webサービスに電話すると、リクエストで正常に機能しています。しかし、応答では、すべての値を含む1つの文字列を取得しています。応答文字列を以下に示します。

anyType{clientNameList=anyType{clientNameList=anyType{clientID=1; }; clientNameList=anyType{clientID=2; }; }; message=SUCCESS; }.

この文字列を解析するにはどうすればよいですか？

UserResponse.java

public class UserResponse implements KvmSerializable{

public String message = null;
public Client[] clientNameList = null;

@Override
public Object getProperty(int index) {
    switch (index){
    case 0:
        return message;
    case 1:
        return clientNameList;
     default:
         return null;
    }
}

@Override
public int getPropertyCount() {
    // TODO Auto-generated method stub
    return 2;
}

@Override
public void getPropertyInfo(int index, Hashtable arg1, PropertyInfo info) {
    switch(index)
    {
    case 0:
        info.type = PropertyInfo.STRING_CLASS;
        info.name = "message";
        break;
    case 1:
        info.type = PropertyInfo.OBJECT_TYPE;
        info.name = "clientNameList";
        break;
    default:
        break;
    }

}

@Override
public void setProperty(int index, Object value) {
    switch(index)
    {
    case 0:
        message = value.toString();
        break;
    case 1:
        clientNameList = (Client[]) value;
        break;
    default:
        break;
    }

}   
}

Client.javaには、整数型のclientIdのみが含まれています。

更新されたコードとwsdl

ImageProcessImpl.java

public UserResponse sample(UserRequest userRequest) {
     return ImageProcessDAO.sample(userRequest);
}

ImageProcessDAO.java

public static String sample(UserRequest userRequest) {
    System.out.println(userRequest.getClientName());
    UserResponse userResponse = new UserResponse();
    userResponse.setMessage(SUCCESS);
    Client[] clients = new Client[2];
    Client client = null;
    for(int i=0;i<2;i++)
    {
        client = new Client();
        client.setClientID(i+1);
        clients[i] = client;
    }
    userResponse.setClientNameList(clients);
    return userResponse;
}

私はAndroidからこれらのWebサービスを次のように呼んでいます。

try{
        String NAMESPACE = "http://impl.test.com";
        String URL = "http://10.0.2.2:8080/Webservice/services/ImageProcessImpl?wsdl";  
        String SOAP_ACTION = "http://impl.test.com/sample";
        String METHOD_NAME = "sample";

        SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME); 

        UserRequest userRequest = new UserRequest();            
        userRequest.setClientName("Test");

        PropertyInfo pi = new PropertyInfo();
        pi.setName("userRequest");
        pi.setValue(userRequest);
        pi.setType(UserRequest.class);
        request.addProperty(pi);

        SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11); 
        envelope.setOutputSoapObject(request);  
        envelope.implicitTypes = true;
        envelope.addMapping(NAMESPACE, "userRequest", UserRequest.class);
        envelope.addMapping(NAMESPACE, "UserResponse", UserResponse.class);

        AndroidHttpTransport httpTransport = new AndroidHttpTransport(URL);  
        httpTransport.debug = true;
        httpTransport.call(SOAP_ACTION, envelope);

       SoapObject result = (SoapObject) envelope.getResponse();
       userResponse.message = result.getProperty(0).toString();
       Log.e(Test.LOG_TAG, userResponse.message);
        }catch (Exception e) {
            Log.e(Test.LOG_TAG, "throws an exception: " + e.getMessage());
        }

私の新しいwsdlファイルは、

<?xml version="1.0" encoding="UTF-8"?>
<wsdl:definitions targetNamespace="http://impl.test.com" xmlns:apachesoap="http://xml.apache.org/xml-soap" xmlns:impl="http://impl.test.com" xmlns:intf="http://impl.test.com" xmlns:tns1="http://common.test.com" xmlns:wsdl="http://schemas.xmlsoap.org/wsdl/" xmlns:wsdlsoap="http://schemas.xmlsoap.org/wsdl/soap/" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<!--WSDL created by Apache Axis version: 1.4
Built on Apr 22, 2006 (06:55:48 PDT)-->
 <wsdl:types>
  <schema elementFormDefault="qualified" targetNamespace="http://impl.test.com" xmlns="http://www.w3.org/2001/XMLSchema">
   <import namespace="http://common.test.com"/>
   <element name="sample">
    <complexType>
     <sequence>
      <element name="userRequest" type="tns1:UserRequest"/>
     </sequence>
    </complexType>
   </element>
   <element name="sampleResponse">
    <complexType>
     <sequence>
      <element name="sampleReturn" type="tns1:UserResponse"/>
     </sequence>
    </complexType>
   </element>
   <complexType name="ArrayOf_tns1_Client">
    <sequence>
     <element maxOccurs="unbounded" minOccurs="0" name="item" type="tns1:Client"/>
    </sequence>
   </complexType>
  </schema>
  <schema elementFormDefault="qualified" targetNamespace="http://common.test.com" xmlns="http://www.w3.org/2001/XMLSchema">
   <import namespace="http://impl.test.com"/>
   <complexType name="UserRequest">
    <sequence>
     <element name="clientName" nillable="true" type="xsd:string"/>
    </sequence>
   </complexType>
   <complexType name="Client">
    <sequence>
     <element name="clientID" type="xsd:int"/>
    </sequence>
   </complexType>
   <complexType name="UserResponse">
    <sequence>
     <element name="clientNameList" nillable="true" type="impl:ArrayOf_tns1_Client"/>
     <element name="message" nillable="true" type="xsd:string"/>
    </sequence>
   </complexType>
  </schema>
 </wsdl:types>

   <wsdl:message name="sampleRequest">

      <wsdl:part element="impl:sample" name="parameters">

      </wsdl:part>

   </wsdl:message>

   <wsdl:message name="sampleResponse">

      <wsdl:part element="impl:sampleResponse" name="parameters">

      </wsdl:part>

   </wsdl:message>

   <wsdl:portType name="ImageProcessImpl">

      <wsdl:operation name="sample">

         <wsdl:input message="impl:sampleRequest" name="sampleRequest">

       </wsdl:input>

         <wsdl:output message="impl:sampleResponse" name="sampleResponse">

       </wsdl:output>

      </wsdl:operation>

   </wsdl:portType>

   <wsdl:binding name="ImageProcessImplSoapBinding" type="impl:ImageProcessImpl">

      <wsdlsoap:binding style="document" transport="http://schemas.xmlsoap.org/soap/http"/>

      <wsdl:operation name="sample">

         <wsdlsoap:operation soapAction=""/>

         <wsdl:input name="sampleRequest">

            <wsdlsoap:body use="literal"/>

         </wsdl:input>

         <wsdl:output name="sampleResponse">

            <wsdlsoap:body use="literal"/>

         </wsdl:output>

      </wsdl:operation>

   </wsdl:binding>

   <wsdl:service name="ImageProcessImplService">

      <wsdl:port binding="impl:ImageProcessImplSoapBinding" name="ImageProcessImpl">

         <wsdlsoap:address location="http://localhost:8080/Webservice/services/ImageProcessImpl"/>

      </wsdl:port>

   </wsdl:service>

</wsdl:definitions>
4

2 に答える 2

5

XMLで応答を取得し、XMLパーサーを使用して応答を解析する方が簡単だと主張します。また、使用ksoap2-android-assembly-2.5.4-jar-with-dependencies.jarしているものは廃止されることをお勧めします。

AndroidHttpTransport に置き換えられていますHttpTransportSE

XMLで応答を取得する方法は次のとおりです。

HttpTransportSE androidHttpTransport = new HttpTransportSE(URL, 100);
androidHttpTransport.debug=true; 
androidHttpTransport.call(SOAP_ACTION, envelope);
String response = androidHttpTransport.responseDump;
Log.d("Response in XML", response);

応答はresponse文字列で取得され、SAXまたは他のXMLパーサーを使用して解析できます。

于 2012-08-23T04:32:51.553 に答える
2

UserRequestクラスは、org.ksoap2.serialization.KvmSerializableを実装する必要があります。

于 2012-08-22T12:57:32.450 に答える