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Java、jpa(および休止状態)を使用してデスクトップアプリケーションを作成しました。

ユーザーが Bean フィールドを編集してデータベースに保存できるページがあります。豆の畑codiceは独特です。データベースには 2 つの行があり、1 つはcodice=0で、2 つ目はcodice=00です。

使用は、最初の Bean を編集し、フィールドをに0変更し、それを永続化しようとします。entityManager.commit() は例外を発生させます:codice00

ERROR: Duplicate entry '00' for key 'codice'.

例外がキャッチされてユーザーに表示され、codiceフィールドが11(まだ存在しない) に変更され、永続化が試行されます。

entityManager.commit()同じ例外を再び発生させる

(ERROR: Duplicate entry '00' for key )

古いアイテムを永続化しようとしていたようです。

ここにケース例:

EntityManager em = Persistence.createEntityManagerFactory(
            "testNewDataModel").createEntityManager();
Articolo a = em.find(Articolo.class, 1L);
EntityTransaction tx = em.getTransaction();
a.setNome("albi8");
// ---- 1 ---- just a normal commit, no errors
tx.begin();     
a = em.merge(a);        
tx.commit();        
System.out.println("---- 1 ----");
// ---- 2 ---- will cause Duplicate entry error
tx.begin();     
a.setCodice("00");  //  already exist an item with codice = 00 -> Duplicate entry '00' for key 'codice'
a = em.merge(a);        
try {
    System.out.println("---- 2 ---- pre commit");
    tx.commit();
    System.out.println("---- 2 ---- after commit");
} catch (Exception e) {
    System.out.println("Duplicate entry '00' for key 'codice'");
}

// ---- 3 ---- trying to correct the previous error 

tx.begin();

a.setCodice("11"); //this code don't exist yet
a.setNome("alby9");

a = em.merge(a);

try {
    System.out.println("---- 3 ---- pre commit");
tx.commit();
    System.out.println("---- 3 ---- after commit");
} catch (Exception e) {
    e.printStackTrace(); //Duplicate entry '00' for key 'codice'
}

彼女の出力は次のとおりです。

org.hibernate.engine.transaction.internal.jdbc.JdbcTransactionFactory
22-ago-2012 18.41.02 org.hibernate.hql.internal.ast.ASTQueryTranslatorFactory <init>
INFO: HHH000397: Using ASTQueryTranslatorFactory
Hibernate: select articolo0_._id as column1_12_0_, articolo0_.id_categoria as id10_12_0_, articolo0_.codice as codice12_0_, articolo0_.coefficiente_prezzo as coeffici3_12_0_, articolo0_.descrizione as descrizi4_12_0_, articolo0_.id_foto as id5_12_0_, articolo0_.nome as nome12_0_, articolo0_.posizione as posizione12_0_, articolo0_.prezzo_imponibile as prezzo8_12_0_, articolo0_.prezzo_vendita as prezzo9_12_0_, articolo0_1_.quantita as quantita13_0_ from inventario4.articolo articolo0_ left outer join inventario4.magazzino articolo0_1_ on articolo0_._id=articolo0_1_._id_articolo where articolo0_._id=?
---- 1 ----
---- 2 ---- pre commit
Hibernate: update inventario4.articolo set id_categoria=?, codice=?, coefficiente_prezzo=?, descrizione=?, id_foto=?, nome=?, posizione=?, prezzo_imponibile=?, prezzo_vendita=? where _id=?
22-ago-2012 18.41.02 org.hibernate.engine.jdbc.spi.SqlExceptionHelper logExceptions
WARN: SQL Error: 1062, SQLState: 23000
22-ago-2012 18.41.02 org.hibernate.engine.jdbc.spi.SqlExceptionHelper logExceptions
ERROR: Duplicate entry '00' for key 'codice'
Duplicate entry '00' for key 'codice'
---- 3 ---- pre commit
Hibernate: update inventario4.articolo set id_categoria=?, codice=?, coefficiente_prezzo=?, descrizione=?, id_foto=?, nome=?, posizione=?, prezzo_imponibile=?, prezzo_vendita=? where _id=?
22-ago-2012 18.41.02 org.hibernate.engine.jdbc.spi.SqlExceptionHelper logExceptions
WARN: SQL Error: 1062, SQLState: 23000
22-ago-2012 18.41.02 org.hibernate.engine.jdbc.spi.SqlExceptionHelper logExceptions
ERROR: Duplicate entry '00' for key 'codice'
javax.persistence.RollbackException: Error while committing the transaction
    at org.hibernate.ejb.TransactionImpl.commit(TransactionImpl.java:90)
    at org.lelmarir.test.Main.main(Main.java:79)
Caused by: javax.persistence.PersistenceException: org.hibernate.exception.ConstraintViolationException: Duplicate entry '00' for key 'codice'
    at org.hibernate.ejb.AbstractEntityManagerImpl.convert(AbstractEntityManagerImpl.java:1361)
    at org.hibernate.ejb.AbstractEntityManagerImpl.convert(AbstractEntityManagerImpl.java:1289)
    at org.hibernate.ejb.TransactionImpl.commit(TransactionImpl.java:78)
    ... 1 more
Caused by: org.hibernate.exception.ConstraintViolationException: Duplicate entry '00' for key 'codice'
    at org.hibernate.exception.internal.SQLExceptionTypeDelegate.convert(SQLExceptionTypeDelegate.java:74)
    at org.hibernate.exception.internal.StandardSQLExceptionConverter.convert(StandardSQLExceptionConverter.java:47)
    at org.hibernate.engine.jdbc.spi.SqlExceptionHelper.convert(SqlExceptionHelper.java:125)
    at org.hibernate.engine.jdbc.spi.SqlExceptionHelper.convert(SqlExceptionHelper.java:110)
    at org.hibernate.engine.jdbc.internal.proxy.AbstractStatementProxyHandler.continueInvocation(AbstractStatementProxyHandler.java:129)
    at org.hibernate.engine.jdbc.internal.proxy.AbstractProxyHandler.invoke(AbstractProxyHandler.java:81)
    at $Proxy21.executeUpdate(Unknown Source)
    at org.hibernate.engine.jdbc.batch.internal.NonBatchingBatch.addToBatch(NonBatchingBatch.java:56)
    at org.hibernate.persister.entity.AbstractEntityPersister.update(AbstractEntityPersister.java:3006)
    at org.hibernate.persister.entity.AbstractEntityPersister.updateOrInsert(AbstractEntityPersister.java:2908)
    at org.hibernate.persister.entity.AbstractEntityPersister.update(AbstractEntityPersister.java:3237)
    at org.hibernate.action.internal.EntityUpdateAction.execute(EntityUpdateAction.java:113)
    at org.hibernate.engine.spi.ActionQueue.execute(ActionQueue.java:272)
    at org.hibernate.engine.spi.ActionQueue.executeActions(ActionQueue.java:264)
    at org.hibernate.engine.spi.ActionQueue.executeActions(ActionQueue.java:187)
    at org.hibernate.event.internal.AbstractFlushingEventListener.performExecutions(AbstractFlushingEventListener.java:326)
    at org.hibernate.event.internal.DefaultFlushEventListener.onFlush(DefaultFlushEventListener.java:52)
    at org.hibernate.internal.SessionImpl.flush(SessionImpl.java:1081)
    at org.hibernate.internal.SessionImpl.managedFlush(SessionImpl.java:315)
    at org.hibernate.engine.transaction.internal.jdbc.JdbcTransaction.beforeTransactionCommit(JdbcTransaction.java:101)
    at org.hibernate.engine.transaction.spi.AbstractTransactionImpl.commit(AbstractTransactionImpl.java:175)
    at org.hibernate.ejb.TransactionImpl.commit(TransactionImpl.java:73)
    ... 1 more
Caused by: com.mysql.jdbc.exceptions.jdbc4.MySQLIntegrityConstraintViolationException: Duplicate entry '00' for key 'codice'
    at sun.reflect.NativeConstructorAccessorImpl.newInstance0(Native Method)
    at sun.reflect.NativeConstructorAccessorImpl.newInstance(Unknown Source)
    at sun.reflect.DelegatingConstructorAccessorImpl.newInstance(Unknown Source)
    at java.lang.reflect.Constructor.newInstance(Unknown Source)
    at com.mysql.jdbc.Util.handleNewInstance(Util.java:406)
    at com.mysql.jdbc.Util.getInstance(Util.java:381)
    at com.mysql.jdbc.SQLError.createSQLException(SQLError.java:1015)
    at com.mysql.jdbc.SQLError.createSQLException(SQLError.java:956)
    at com.mysql.jdbc.MysqlIO.checkErrorPacket(MysqlIO.java:3558)
    at com.mysql.jdbc.MysqlIO.checkErrorPacket(MysqlIO.java:3490)
    at com.mysql.jdbc.MysqlIO.sendCommand(MysqlIO.java:1959)
    at com.mysql.jdbc.MysqlIO.sqlQueryDirect(MysqlIO.java:2109)
    at com.mysql.jdbc.ConnectionImpl.execSQL(ConnectionImpl.java:2648)
    at com.mysql.jdbc.PreparedStatement.executeInternal(PreparedStatement.java:2077)
    at com.mysql.jdbc.PreparedStatement.executeUpdate(PreparedStatement.java:2362)
    at com.mysql.jdbc.PreparedStatement.executeUpdate(PreparedStatement.java:2280)
    at com.mysql.jdbc.PreparedStatement.executeUpdate(PreparedStatement.java:2265)
    at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
    at sun.reflect.NativeMethodAccessorImpl.invoke(Unknown Source)
    at sun.reflect.DelegatingMethodAccessorImpl.invoke(Unknown Source)
    at java.lang.reflect.Method.invoke(Unknown Source)
    at org.hibernate.engine.jdbc.internal.proxy.AbstractStatementProxyHandler.continueInvocation(AbstractStatementProxyHandler.java:122)
    ... 18 more

そして最後に質問:トランザクションがまだcodice=で行を永続化しようとするのはなぜ00ですか?

4

2 に答える 2

0

コミットに失敗した後、明示的にトランザクションをロールバックしてみてください

try {
System.out.println("---- 2 ---- pre commit");
tx.commit();
System.out.println("---- 2 ---- after commit");
} catch (Exception e) {
    System.out.println("Duplicate entry '00' for key 'codice'");

    tx.rollback(); // HERE

}
于 2013-04-16T09:05:00.193 に答える