java - Double -> 整数を抽出

Question

int a = 4;
int b = 3;
int c = 10;
int d1 =(int) (double)(a*b)/c;
double d2 =(double)(a*b)/c;
System.out.println("d1: " + d1);
System.out.println("d2: " + d2);

Result: d1: 1 and d2: 1.2

1.2 の 1.0 を抽出/削除する方法。だから私は d2 = 0.2 と d1 = 1 を取得し、a = 9 -> (9*3)/10 の場合。d2 = 0.7 および d1 = 2 そして、a = 6 -> (6*3)/10 の場合。d2 = 0.8 および d1 = 1

どうもありがとう。

Answer 1

int a = 4;
int b = 3;
int c = 10;
// Store the original value.
double original = (double)(a*b)/c;
int d1 = (int)(original);
// Get the difference between the original value and the floored one.
double d2 = original - d1;
System.out.println("d1: " + d1);
System.out.println("d2: " + d2);

Answer 2

浮動小数点値から整数部分を差し引くだけです。

double d = (double) (a*b)/c;
int intPart = (int) d;
double fracPart = d - intPart;

Answer 3

これを試して

int a = 9;
int b = 3;
int c = 10;

int d1 =(int) (double)(a*b)/c;
double d2 =(double)((a*b)%c)/c;
System.out.println("d1: " + d1);
System.out.println("d2: " + d2);