0

タイプというテーブルがあり、データは次のようになります。

Item_Name 

Hardware \ Hardware Laptop \ Display
Application \ Application Configuration Request
Application \ Application File Request
Application

それらを3つの異なる列に分割しようとしています。そこで、次のクエリで試してみました。

select parsename(replace([Item_Name],'\','.'),3) as First,
 parsename(replace([Item_Name],'\','.'),2) as Second,
 parsename(replace([Item_Name],'\','.'),1) as third
from dbo.Types

しかし、私が望む出力は次のとおりです。

First          Second                                      Third
Hardware       Hardware Laptop                             Display
Application    Application Configuration Request           NULL
Application    Application File Request                    NULL
Application    NULL                                        NULL

しかし、私は次のように出力しています：

First          Second                          Third
Hardware       Hardware Laptop                 Display
NULL           Application                     Application Configuration Request           
NULL           Application                     Application File Request                    
NULL           NULL                            Application
4

3 に答える 3

2

これは役に立つかもしれません

Declare @t table(Item_Name Varchar(100))
Insert Into @t 
Select 'Hardware \ Hardware Laptop \ Display' Union All 
Select 'Application \ Application Configuration Request' Union All
Select 'Application \ Application File Request' Union All
Select 'Application'

;WITH CTE AS(
SELECT 
    Item_Name
    ,NoOfOccurance = (LEN(Item_Name) - LEN(REPLACE(Item_Name, '\', ''))) 
    ,New_Item_Name = CASE (LEN(Item_Name) - LEN(REPLACE(Item_Name, '\', ''))) 
                         WHEN 0 THEN 'Col1 \ Col2 \ ' +Item_Name
                         WHEN 1 THEN 'Col1 \ ' +Item_Name 
                         ELSE Item_Name
                     END
FROM @t)
,cte2 AS(
SELECT 
    [First] = LEFT(New_Item_Name,CHARINDEX('\',New_Item_Name,0)-1)  
    , [Second] = SUBSTRING(
                 New_Item_Name
                 ,CHARINDEX('\',New_Item_Name,0)+1
                 ,CHARINDEX('\',SUBSTRING(New_Item_Name,CHARINDEX('\',New_Item_Name,0)+1,len(New_Item_Name)),0)-1
               )
    ,[Third] = REVERSE(LEFT(REVERSE (New_Item_Name),CHARINDEX('\',REVERSE (New_Item_Name),0)-1))

FROM CTE)
SELECT
    [First] = CASE WHEN LTRIM(RTRIM([First])) = 'Col1' THEN REPLACE([First], 'Col1', NULL) ELSE [First] END
    ,[Second] = CASE WHEN LTRIM(RTRIM([Second])) = 'Col2' THEN REPLACE([Second], 'Col2', NULL) ELSE [Second] END 
    ,[Third]    
FROM Cte2

//結果

First   Second  Third
Hardware     Hardware Laptop     Display
NULL     Application     Application Configuration Request
NULL     Application     Application File Request
NULL    NULL     Application
于 2012-08-31T05:45:26.090 に答える
0

私はこれをブルートフォースと考えていますが、うまくいきます。アイデアは、最後に十分なスラッシュを追加してフルネームを作成することです. これは物事を押しのけます：

with types as (select 'Hardware \ Hardware Laptop \ Display' as item_name union all
               select 'Application \ Application Configuration Request' union all
               select 'Application \ Application File Request' union all
               select 'Application'
              )
select parsename(replace([Item_Name]+suffix, '\', '.'), 3) as First,
       parsename(replace([Item_Name]+suffix, '\', '.'), 2) as Second,
       parsename(replace([Item_Name]+suffix, '\', '.'), 1) as third
from (select item_name, LEN(Item_name) - LEN(replace(item_name, '\', '')) as numslash,
             REPLICATE('. ', 2-(LEN(Item_name) - LEN(replace(item_name, '\', '')))) as suffix
      from Types
     ) t

わずかな違いの 1 つは、空のスロットに対して NULL ではなくスペースが生成されることです。NULL が必要な場合は、追加のロジックが必要になります。

于 2012-08-30T21:23:09.863 に答える
-1 
WITH CTE AS(
 SELECT CASE LEN(Item_Name)-LEN(REPLACE(Item_Name,'\','')) WHEN 2 THEN [Item_Name] WHEN 1 THEN  
         [Item_Name]+'.' Else [Item_Name]+'..' as Item_Name
 FROM dbo.Types 
 )
SELECT parsename(Item_Name,'\','.'),3) as First,
       parsename(Item_Name,'\','.'),2) as Second,
       parsename(Item_Name,'\','.'),1) as third 
FROM CTE
于 2012-08-30T21:23:27.683 に答える