1

t-sqlクエリについてサポートが必要です。

この構造のテーブルがあります。

id  |  OverallRank  |  FirstRank  |  SecondRank  |  Nrank..
1   |       10      |    20       |     30       |    5
2   |       15      |    24       |     12       |    80
3   |       10      |    40       |     37       |    12

この種の結果を生成するクエリが必要です。

idの場合：1

id  |  OverallRank  |  BestRankLabel  |  BestRankValue  |  WorstRankLabel  | WorkRankValue
1   |     10        |    SecondRank   |        30       |     Nrank        |       5

idの場合：2

id  |  OverallRank  |  BestRankLabel  |  BestRankValue  |  WorstRankLabel  | WorkRankValue
1   |     15        |    FirstRank    |        24       |     SecondRank   |       12

どうすればいいですか？

前もって感謝します

4

3 に答える 3

0 
CASE 
   WHEN OverallRank > FirstRank and OverallRank > FirstSecondRand and  OverallRank > nRank THEN 'OverallRank' 
   WHEN FirstRank > OverallRank ... THEN 'FirstRank' 
END
于 2012-09-11T12:50:55.897 に答える
0

この種のクエリは、データを正規化する必要がある理由です。

declare @id int, @numranks int
select @id = 1, @numranks = 3 -- number of Rank columns

;with cte as    
(   
    select *
    from
    (
        select *,
            ROW_NUMBER() over (partition by id order by rank desc) rn
        from
        (
        select * from YourBadlyDesignedTable
            unpivot (Rank for RankNo in (FirstRank, SecondRank, ThirdRank))u -- etc
        ) v2
    ) v1
    where id=@id and rn in (1, @numranks)
) 
    select 
        tMin.id, 
        tMin.OverallRank,       
        tMin.RankNo as BestRankLabel,
        tMin.Rank as BestRankValue,
        tMax.RankNo as WorstRankLabel,
        tMax.Rank as WorstRankValue
    from (select * from cte where rn=1) tMin
        inner join (select * from cte where rn>1) tMax
            on tMin.id = tmax.id

id = @idすべての行が必要な場合は、を取り出すことができます。

于 2012-09-11T13:09:01.503 に答える
0 
with cte(id, RankValue,RankName) as (
            SELECT id, RankValue,RankName
            FROM 
                        (SELECT id,  OverallRank,  FirstRank,  SecondRank, Nrank 
                        FROM ##input) p
            UNPIVOT
                        (RankValue FOR RankName IN 
                                    (OverallRank,  FirstRank,  SecondRank, Nrank)
            )AS unpvt)
select t1.id, max(case when RankName = 'OverallRank'  then RankValue else null end) as OverallRank,
        max(case when t1.RankValue = t2.MaxRankValue then RankName else null end) as BestRankName,
        MAX(t2.MaxRankValue) as BestRankValue,
        max(case when t1.RankValue = t3.MinRankValue then RankName else null end) as WorstRankName,
        MAX(t3.MinRankValue) as WorstRankValue
        from cte as t1
        left join (select id, MAX(RankValue) as MaxRankValue from cte group by id) as t2 on t1.id = t2.id
        left join (select id, min(RankValue) as MinRankValue from cte group by id) as t3 on t1.id = t3.id
    group by t1.id

テストデータをうまく処理します。右の列の名前を追加することによってのみ、RankName IN（OverallRank、FirstRank、SecondRank、Nrank）を編集する必要があります。

于 2012-09-11T13:10:23.877 に答える