3

以下の表があります（商品）

id  name      quality  weight
1   Demir-1   ST-1     10
2   Demir-2   ST-2      7
3   Demir-3   ST-1     20
4   Demir-2   ST-3      8
5   Demir-1   ST-3      6
6   Demir-4   ST-2     10
7   Demir-2   ST-2     12
8   Demir-1   ST-1     15
9   Demir-1   ST-3     10
10  Demir-3   ST-3      5
11  Demir-2   ST-2      5

ここで、ユーザーが重量の合計が20〜25で、name ='Result-2'の製品のリストを取得したい場合、結果は次のようになります。すべての組み合わせは、重量の合計が20〜25の場合に表示する必要があります。

 id name      quality  weight    
  4 Demir-2   ST-3      8   
  7 Demir-2   ST-2     12   
 11 Demir-2  ST-2       5
------------------------------
  2 Demir-2   ST-2      7
  4 Demir-2   ST-3      8
 11 Demir-2   ST-2      5
------------------------------ 
------------------------------ 
  1 Demir-1   ST-1     10
  8 Demir-1   ST-1     15

合計（重み）が25であることがわかります。

4

5 に答える 5

4 
DECLARE @tblProducts TABLE(Id INT IDENTITY, ProductName varchar(50),Quality varchar(50), ProductWeight int)
INSERT INTO @tblProducts SELECT 'Demir-1','ST-1',10
INSERT INTO @tblProducts SELECT 'Demir-2','ST-2',7
INSERT INTO @tblProducts SELECT 'Demir-3','ST-1',20
INSERT INTO @tblProducts SELECT 'Demir-2','ST-3',8
INSERT INTO @tblProducts SELECT  'Demir-1','ST-3',6
INSERT INTO @tblProducts SELECT  'Demir-4','ST-2',10
INSERT INTO @tblProducts SELECT 'Demir-2','ST-2' ,12
INSERT INTO @tblProducts SELECT  'Demir-1','ST-1',15
INSERT INTO @tblProducts SELECT  'Demir-1','ST-3',10
INSERT INTO @tblProducts SELECT 'Demir-3','ST-3' ,5
INSERT INTO @tblProducts SELECT 'Demir-2' ,'ST-2 ',5

 ;WITH Cte (Id,ProductQuality,ProductIds,ProductNames,ProductQualities,ProductTotalWeight,ProductWeights,ProductName1,ProductName2) AS
(
    SELECT  Id
            ,Quality            
            , ',' + CAST(Id AS VARCHAR(MAX))  
            ,',' + CAST(ProductName AS VARCHAR(MAX))
            ,',' + CAST(Quality AS VARCHAR(MAX)) 
            ,ProductWeight
            , ',' + CAST(ProductWeight AS VARCHAR(MAX)) 
            ,ProductName
            ,CAST(ProductName AS VARCHAR(MAX))
    FROM @tblProducts
    UNION ALL
    SELECT p.Id
            , p.Quality            
            ,c.ProductIds + ',' +  CAST(p.Id AS VARCHAR(MAX))
            ,c.ProductNames + ',' +  CAST(p.ProductName AS VARCHAR(MAX)) 
             ,c.ProductQualities + ',' + CAST(p.Quality AS VARCHAR(MAX)) 
             ,c.ProductTotalWeight + p.ProductWeight          
            ,c.ProductWeights + ',' + CAST(p.ProductWeight AS VARCHAR(MAX))
            ,p.ProductName
            ,c.ProductName2
    FROM @tblProducts AS p JOIN Cte c ON p.Id < c.Id
    WHERE  p.ProductName = c.ProductName2
    )
SELECT 
        ProductIds = STUFF(ProductIds,1,1,'')
        ,ProductNames = STUFF(ProductNames,1,1,'')
        ,ProductQualities = STUFF(ProductQualities,1,1,'')
        ,ProductTotalWeight
        ,ProductWeights = STUFF(ProductWeights,1,1,'')
FROM CTE 
WHERE ProductTotalWeight BETWEEN 20 AND 25

結果

ProductIds  ProductNames             ProductQualities   ProductTotalWeight  ProductWeights
3           Demir-3                 ST-1                20                  20
11,7,2      Demir-2,Demir-2,Demir-2 ST-2 ,ST-2,ST-2     24                  5,12,7
11,7,4      Demir-2,Demir-2,Demir-2 ST-2 ,ST-2,ST-3     25                  5,12,8
11,4,2      Demir-2,Demir-2,Demir-2 ST-2 ,ST-3,ST-2     20                  5,8,7
10,3        Demir-3,Demir-3         ST-3,ST-1           25                  5,20
9,1         Demir-1,Demir-1         ST-3,ST-1           20                 10,10
9,8         Demir-1,Demir-1         ST-3,ST-1           25                 10,15
8,1         Demir-1,Demir-1         ST-1,ST-1           25                 15,10
8,5         Demir-1,Demir-1         ST-1,ST-3           21                  15,6
7,4         Demir-2,Demir-2         ST-2,ST-3           20                  12,8
于 2012-09-12T09:29:27.070 に答える
2

残念ながら、私が一緒にハッキングしたSQLコードが示すように、SQLは、特定の計算でテーブルからすべての組み合わせを考え出すための正しいコーディングエンジンではありません。

通常、これはその性質上、手続き型言語でコーディングすることをお勧めします。また、入力データセットが大きいここでのソリューションは、SQLの再帰制限をすぐに使い果たしてしまう可能性があることにも注意してください。可能な製品の数も十分に多くなる可能性があるため、実行速度は非常に遅くなります。

drop table products
drop table #MinW
drop table #Products
go
create table products
(
id  int,
name  varchar(20),  
quality varchar(20),
[weight] int
) 
go
insert into products
select
1,   'Demir-1',   'ST-1',     10 
union
select 2,   'Demir-2',   'ST-2',      7 
union
select 3,   'Demir-3',   'ST-1',     20 
union
select 4,   'Demir-2',   'ST-3',      8 
union
select 5,   'Demir-1',   'ST-3',      6 
union
select 6,   'Demir-4',   'ST-2',     10 
union
select 7,   'Demir-2',   'ST-2',     12 
union
select 8,   'Demir-1',   'ST-1',     15 
union
select 9,   'Demir-1',   'ST-3',     10 
union
select 10,  'Demir-3',   'ST-3',      5 
union
select 11,  'Demir-2',   'ST-2',      5 
go
select 
p.id, p.name, p.quality, p.weight
into #MinW
from products p
inner join
(
select name,min(weight) as weight
from products group by name having min(weight) < 25
) as minW
on p.name = minW.name and p.weight = minW.weight

go
with weightProducts (id, name, [weight],history)
as
( 
select id, name,[weight],convert(varchar(1024),'"'+convert(varchar(10),id)+'",') from #minW
union all
select products.id, products.name,products.[weight] + weightProducts.[weight],convert(varchar(1024),weightProducts.history+'"'+convert(varchar(10),products.id)+'",') from products, weightProducts where products.name = weightproducts.name and  charindex('"'+convert(varchar(10),products.id)+'",',weightProducts.history)<=0 and (products.weight + weightProducts.weight) < 25
)
-- Statement using the CTE
select *
into #Products
from weightProducts
where weight between 20 and 25

go

select 
p1.history,
p2.id,
p2.quality,
p2.weight,
p1.weight as totalWeight
from #Products p1
inner join
products p2 on p1.name = p2.name and charindex('"'+convert(varchar(10),p2.id)+'",',p1.history)>0
order by 
p1.history,
p2.id
于 2012-09-12T09:20:17.100 に答える
0 
SELECT * FROM tablename
WHERE name IN (
 SELECT name FROM tablename 
 GROUP BY name
 HAVING SUM(weight) BETWEEN 20 AND 25)
于 2012-09-12T06:23:11.190 に答える
0

このクエリはどうですか？

select id, name, quality, weight from PRODUCTS
group by id, name, quality, weight
having sum(weight) between 20 and 25
于 2012-09-12T06:24:09.187 に答える
0

これを試して：

SELECT * FROM products
WHERE name IN (
              SELECT name FROM products
              GROUP BY name
              HAVING SUM(weight) BETWEEN 20 AND 25)
于 2012-09-12T06:25:42.507 に答える