1

私はテーブルを持っています:

CREATE TABLE [dbo].[TargettingReport](
    [MLISNPI] [varchar](50) NULL,
    [CLIENT_ID1] [varchar](50) NULL,
    [Sum of count] [int] NULL
) ON [PRIMARY]

SUM OF COUNTに基づいて2 番目と 3 番目に高いものを選択しようとしていますMLISNPI, CLIENT_ID1

これは、次の一意の出現ごとに最大値を取得する方法ですMLISNPI, CLIENT_ID1:

  select [MLISNPI],[CLIENT_ID1],MAX([Sum of count])
  from [TargettingReport]
  group by 
  [MLISNPI],[CLIENT_ID1]

問題は、2 番目と 3 番目に高い値を取得する方法です。

ここにいくつかのサンプルデータがあります:

+---------+------------+--------------+
| MLISNPI | CLIENT_ID1 | sum of count |
+---------+------------+--------------+
|  567890 |     214060 |           18 |
|  678901 |     214060 |           58 |
|  789012 |     214060 |           27 |
|  891012 |     214060 |            1 |
|  101112 |     214060 |           23 |
|  003001 |     101596 |            0 |
|  003001 |     101522 |          436 |
|  003001 |     101597 |            0 |
|  003002 |     102165 |           66 |
|  003002 |     100062 |            1 |
|  003002 |     211074 |         1229 |
|  003006 |     102235 |           21 |
|  003014 |     213926 |            5 |
|  003016 |     213143 |            3 |
|  003023 |     213801 |           55 |
|  003023 |     212876 |           44 |
|  003023 |     100218 |            0 |
|  003028 |     211144 |          133 |
|  003041 |     100236 |          346 |
|  003041 |     103164 |           65 |
|  003051 |     213402 |          157 |
|  003058 |     100572 |           28 |
|  003065 |     101632 |           29 |
|  003071 |     213632 |            6 |
|  003072 |     101506 |            4 |
|  003081 |     100087 |          398 |
|  003083 |     214311 |            7 |
|  003117 |     210178 |          203 |
|  003121 |     214008 |            9 |
|  003139 |     102179 |         1635 |
|  003147 |     216022 |           21 |
|  003149 |     211425 |            1 |
|  003186 |     215748 |            1 |
+---------+------------+--------------+
4

3 に答える 3

4 
; with numbered as
(
  select *,
      -- Assign number to each record
      -- Numbering is separate for each pair of MLISNPI and CLIENT_ID1
      -- Highest [Sum of desc] will get number 1 and so forth
         row_number() over (partition by [MLISNPI], [CLIENT_ID1]
                            order by [Sum of count] desc) rn
    from [TargettingReport]
)
select [MLISNPI],
       [CLIENT_ID1], 
       [Sum of count]
  from numbered
-- Now one can filter ranks
 where rn between 2 and 3

UPDATE : mlisnpi を中心に [Sum of count] をピボットする

; with numbered as
(
  select mlisnpi,
         [sum of count],
      -- Assign number to each record
      -- Numbering is separate for each MLISNPI
      -- Highest [Sum of desc] will get number 1 and so forth
         row_number() over (partition by [MLISNPI]
                            order by [Sum of count] desc) rn
    from [TargettingReport]
)
select mlisnpi,
       [1] Rank1,
       [2] Rank2,
       [3] Rank3
  from numbered
 pivot (max([Sum of count]) for rn in ([1], [2], [3])) p

Sql Fiddle はこちらです。

[Sum of count] の代わりに Cliend_ID1 が実際に必要な場合は、[Sum of count] のすべての出現箇所を Client_ID1 に置き換えます。Client_ID1 を cte に追加しないでください。これは、ピボットによって結果に含まれ、mlisnpi と Client_ID1 の各組み合わせが独自の行に表示されるためです。

UPDATE2 : タイトルを含むピボット。すべてのタイトル (client_id1) を結合し、行番号を操作してタイトルと合計の正しい組み合わせを取得する必要があるため、もう少し冗長です。また、使用できるようにするには、すべてを同じデータ型 (ここでは varchar) に変換する必要がありますunion all。

; with numbered as
(
  select *,
         row_number() over (partition by [MLISNPI]
                            order by [Sum of count] desc) rn
    from [TargettingReport]
),
unioned as
(
  select mlisnpi,
         convert(varchar(20), [Sum of count]) value,
         rn * 2 rn
    from numbered
   union all
   select mlisnpi,
       convert(varchar(20), [Client_ID1]),
       rn * 2 - 1
    from numbered
)
select mlisnpi,
       [1] Client1,
       [2] Rank1,
       [3] Client2,
       [4] Rank2,
       [5] Client3,
       [6] Rank3
  from unioned
 pivot (max(value) for rn in ([1], [2], [3], [4], [5], [6])) p

このための Sql Fiddle は hereです。

于 2012-09-12T19:52:51.967 に答える
1

上位3つの値のビューを作成します

CREATE VIEW TESTVIEW

AS

SELECT ABB4.[MLISNPI], ABB4.[CLIENT_ID1], MAX(ABB4.[SUM OF COUNT]) AS NEW3
FROM TARGETTINGREPORT AS ABB4
    LEFT JOIN (SELECT ABB2.[MLISNPI], ABB2.[CLIENT_ID1], MAX([SUM OF COUNT]) AS NEW2
                FROM TARGETTINGREPORT AS ABB2
                LEFT JOIN (SELECT [MLISNPI], [CLIENT_ID1], MAX([SUM OF COUNT]) AS NEW1
                            FROM TARGETTINGREPORT GROUP BY MLISNPI, [CLIENT_ID1]) 
                AS ABB1 ON ABB1.MLISNPI = ABB2.MLISNPI AND ABB1.NEW1 = ABB2.[SUM OF COUNT] and ABB1.CLIENT_ID1 = ABB2.CLIENT_ID1
                WHERE ABB1.MLISNPI IS NULL
                GROUP BY ABB2.MLISNPI, ABB2.[CLIENT_ID1])
     AS ABB3 ON ABB3.MLISNPI = ABB4.MLISNPI AND ABB3.NEW2 = ABB4.[SUM OF COUNT] AND ABB3.CLIENT_ID1 = ABB4.CLIENT_ID1
     LEFT JOIN (SELECT ABB5.[MLISNPI], ABB5.[CLIENT_ID1], MAX([SUM OF COUNT]) AS NEW4
                FROM TARGETTINGREPORT AS ABB5
                GROUP BY ABB5.MLISNPI, ABB5.[CLIENT_ID1]) 
                AS ABB6 ON ABB6.MLISNPI = ABB4.MLISNPI AND ABB6.NEW4 = ABB4.[SUM OF COUNT] AND ABB6.CLIENT_ID1 = ABB4.CLIENT_ID1
WHERE ABB3.MLISNPI IS NULL AND ABB6.MLISNPI IS NULL             
GROUP BY ABB4.MLISNPI, ABB4.[CLIENT_ID1]

UNION ALL

SELECT ABB2.[MLISNPI], ABB2.[CLIENT_ID1], MAX([SUM OF COUNT]) AS NEW2
FROM TARGETTINGREPORT AS ABB2
    LEFT JOIN (SELECT [MLISNPI], [CLIENT_ID1], MAX([SUM OF COUNT]) AS NEW1
                FROM TARGETTINGREPORT GROUP BY MLISNPI, [CLIENT_ID1]) 
                AS ABB1 ON ABB1.MLISNPI = ABB2.MLISNPI AND ABB1.NEW1 = ABB2.[SUM OF COUNT] AND ABB1.CLIENT_ID1 = ABB2.CLIENT_ID1
WHERE ABB1.MLISNPI IS NULL
GROUP BY ABB2.MLISNPI, ABB2.[CLIENT_ID1]

UNION ALL

SELECT [MLISNPI], [CLIENT_ID1], MAX([SUM OF COUNT]) AS NEW1
FROM TARGETTINGREPORT 
GROUP BY MLISNPI, [CLIENT_ID1]

次に、別のビューを作成します

CREATE VIEW TESTVIEW2

AS

SELECT ABB1.MLISNPI, ABB1.CLIENT_ID1, ABB1.NEW3
FROM TESTVIEW AS ABB1
    LEFT JOIN (SELECT MLISNPI, CLIENT_ID1, MIN(NEW3) AS VAR1
                FROM TESTVIEW
                GROUP BY MLISNPI, CLIENT_ID1) AS ABB2
    ON ABB2.MLISNPI = ABB1.MLISNPI AND ABB2.CLIENT_ID1 = ABB1.CLIENT_ID1 AND ABB2.VAR1 = ABB1.NEW3
    LEFT JOIN (SELECT MLISNPI, CLIENT_ID1, MAX(NEW3) AS VAR2
                FROM TESTVIEW
                GROUP BY MLISNPI, CLIENT_ID1) AS ABB3
    ON ABB3.MLISNPI = ABB1.MLISNPI AND ABB3.CLIENT_ID1 = ABB1.CLIENT_ID1 AND ABB3.VAR2 = ABB1.NEW3          
WHERE ABB2.MLISNPI IS NULL AND ABB3.MLISNPI IS NULL

そして最後に、ピボット形式で上位3つの値を呼び出します

SELECT TESTVIEW.MLISNPI, TESTVIEW.CLIENT_ID1, MAX(TESTVIEW.NEW3) AS '1', TESTVIEW2.NEW3 AS '2', MIN(TESTVIEW.NEW3) AS '3'
FROM TESTVIEW
    LEFT JOIN TESTVIEW2 ON TESTVIEW2.MLISNPI = TESTVIEW.MLISNPI AND TESTVIEW2.CLIENT_ID1 = TESTVIEW.CLIENT_ID1
GROUP BY TESTVIEW.MLISNPI, TESTVIEW.CLIENT_ID1, TESTVIEW2.NEW3
于 2012-09-12T21:26:47.073 に答える
0

where rownum < 3 を実行して、選択から最大値を削除できますか?

select top 3 [MLISNPI],[CLIENT_ID1], Max([Sum of count]) COUNTS
from [TargettingReport]
group by 
[MLISNPI],[CLIENT_ID1]
ORDER by [Sum of count] desc
于 2012-09-12T19:20:20.670 に答える