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基本的なツールとユーティリティを使用してPythonリストをJSON形式に変換し、特定の「名前」、「グループ」、「ソース」、「ターゲット」キー名などを含める方法は? 基本的に、そのフォーマットを構築するために多くの文字列を連結していますか?

リストのインデックスは接続を表します。たとえば、リストのインデックス 0 はインデックス 1、3、4、5、6、7、8、9 に接続し、1 はインデックス 0、2、3、4、5、6、7、8 に接続します。 、 9

リスト：

[[1, 3, 4, 5, 6, 7, 8, 9], [0, 2, 3, 4, 5, 6, 7, 8, 9], [1, 3, 4, 7, 9], [0, 1, 2, 4, 5, 6, 7, 9], [0, 1, 2, 3, 6, 7, 8], [0, 1, 3, 6, 7, 8, 9], [0, 1, 3, 4, 5, 7, 8, 9], [0, 1, 2, 3, 4, 5, 6, 8, 9], [0, 1, 4, 5, 6, 7, 9], [0, 1, 2, 3, 5, 6, 7, 8]]

この JSON 形式のようなものに?

    {"nodes":
[
{"name":"Zone1","group":0},
{"name":"Zone2","group":1},
{"name":"Zone3","group":2},
{"name":"Zone4","group":3},
{"name":"Zone5","group":4},
{"name":"Zone6","group":5},
{"name":"Zone7","group":6},
{"name":"Zone8","group":7},
{"name":"Zone9","group":8},
{"name":"Zone10","group":9}
],
"links":[
{"source":0,"target":1},
{"source":0,"target":3},
{"source":0,"target":4},
{"source":0,"target":5},
{"source":0,"target":6},
{"source":0,"target":7},
{"source":0,"target":8},
{"source":0,"target":9},
{"source":1,"target":0},
{"source":1,"target":2},
{"source":1,"target":3},
{"source":1,"target":4},
{"source":1,"target":5},
{"source":1,"target":6},
{"source":1,"target":7},
{"source":1,"target":8},
{"source":1,"target":9},
{"source":2,"target":1},
{"source":2,"target":3},
{"source":2,"target":4},
{"source":2,"target":7},
{"source":2,"target":9},
{"source":3,"target":0},
{"source":3,"target":1},
{"source":3,"target":2},
{"source":3,"target":4},
{"source":3,"target":5},
{"source":3,"target":6},
{"source":3,"target":7},
{"source":3,"target":9},
{"source":4,"target":0},
{"source":4,"target":1},
{"source":4,"target":2},
{"source":4,"target":3},
{"source":4,"target":6},
{"source":4,"target":7},
{"source":4,"target":8},
{"source":5,"target":0},
{"source":5,"target":1},
{"source":5,"target":3},
{"source":5,"target":6},
{"source":5,"target":7},
{"source":5,"target":8},
{"source":5,"target":9},
{"source":6,"target":0},
{"source":6,"target":1},
{"source":6,"target":3},
{"source":6,"target":4},
{"source":6,"target":5},
{"source":6,"target":7},
{"source":6,"target":8},
{"source":6,"target":9},
{"source":7,"target":0},
{"source":7,"target":1},
{"source":7,"target":2},
{"source":7,"target":3},
{"source":7,"target":4},
{"source":7,"target":5},
{"source":7,"target":6},
{"source":7,"target":8},
{"source":7,"target":9},
{"source":8,"target":0},
{"source":8,"target":1},
{"source":8,"target":4},
{"source":8,"target":5},
{"source":8,"target":6},
{"source":8,"target":7},
{"source":8,"target":9},
{"source":9,"target":0},
{"source":9,"target":1},
{"source":9,"target":2},
{"source":9,"target":3},
{"source":9,"target":5},
{"source":9,"target":6},
{"source":9,"target":7},
{"source":9,"target":8}
]}
4

3 に答える 3

3

ただ行う：

import json
myjson = json.dumps(mylst)
于 2012-09-14T18:10:03.293 に答える
2

入力と出力から推測すると、これがおそらく必要なものです。

import json
def convert(adj_lst):
    links = []
    for i,adj in enumerate(adj_lst):
        links.extend( [{'source':i,'target':n} for n in adj] )
    nodes = [{"name":"Zone%d" % i, "group":i} for i in xrange(len(adj_lst))]
    return {"nodes":nodes, "links":links}

adj_list = [[1, 3, 4, 5, 6, 7, 8, 9], [0, 2, 3, 4, 5, 6, 7, 8, 9], [1, 3, 4, 7, 9], [0, 1, 2, 4, 5, 6, 7, 9], [0, 1, 2, 3, 6, 7, 8], [0, 1, 3, 6, 7, 8, 9], [0, 1, 3, 4, 5, 7, 8, 9], [0, 1, 2, 3, 4, 5, 6, 8, 9], [0, 1, 4, 5, 6, 7, 9], [0, 1, 2, 3, 5, 6, 7, 8]]
print json.dumps(convert(adj_list), indent=2)
于 2012-09-14T18:24:57.960 に答える
1

モジュールを使用jsonすると、リストを簡単にエンコードできるはずです。

ダビデが提案したように

json.dumpsと

json.loadsjson から python に変わります。Python は優れたドキュメントを提供し、Google に「python json」のような未定義の検索を入力すると、最初の検索結果として適切なリンクが提供されます

于 2012-09-14T18:10:02.407 に答える