-2

私は以下のクエリを持っています、クエリは正しい結果を返しますが、テーブルcslogcurve_datanodeに10000行以上ある場合、私のクエリは長い時間の労力を要し、クエリを最適化する方法または最適なシンタックスを尋ねたいので、同じ結果を返さなければなりません以下の私のクエリ

 SELECT DISTINCT
    (SELECT dataNode FROM cslogcurve_datanode s1 WHERE logCurveInfoUID = 'W-12B-01f34a-lci-1' AND s1.baseNodeDouble = t.baseNodeDouble) AS R1,
    (SELECT dataNode FROM cslogcurve_datanode s1 WHERE logCurveInfoUID = 'W-12B-01f34a-lci-10' AND s1.baseNodeDouble = t.baseNodeDouble) AS R2
     (SELECT dataNode FROM cslogcurve_datanode s1 WHERE logCurveInfoUID = 'W-12B-01f34a-lci-11' AND s1.baseNodeDouble = t.baseNodeDouble) AS R3,
     (SELECT dataNode FROM cslogcurve_datanode s1 WHERE logCurveInfoUID = 'W-12B-01f34a-lci-12' AND s1.baseNodeDouble = t.baseNodeDouble) AS R4,
     (SELECT dataNode FROM cslogcurve_datanode s1 WHERE logCurveInfoUID = 'W-12B-01f34a-lci-13' AND s1.baseNodeDouble = t.baseNodeDouble) AS R5,
     (SELECT dataNode FROM cslogcurve_datanode s1 WHERE logCurveInfoUID = 'W-12B-01f34a-lci-14' AND s1.baseNodeDouble = t.baseNodeDouble) AS R6,
     (SELECT dataNode FROM cslogcurve_datanode s1 WHERE logCurveInfoUID = 'W-12B-01f34a-lci-15' AND s1.baseNodeDouble = t.baseNodeDouble) AS R7,
     (SELECT dataNode FROM cslogcurve_datanode s1 WHERE logCurveInfoUID = 'W-12B-01f34a-lci-16' AND s1.baseNodeDouble = t.baseNodeDouble) AS R8,
     (SELECT dataNode FROM cslogcurve_datanode s1 WHERE logCurveInfoUID = 'W-12B-01f34a-lci-17' AND s1.baseNodeDouble = t.baseNodeDouble) AS R9,
     (SELECT dataNode FROM cslogcurve_datanode s1 WHERE logCurveInfoUID = 'W-12B-01f34a-lci-18' AND s1.baseNodeDouble = t.baseNodeDouble) AS R10
     (SELECT dataNode FROM cslogcurve_datanode s1 WHERE logCurveInfoUID = 'W-12B-01f34a-lci-19' AND s1.baseNodeDouble = t.baseNodeDouble) AS R11,
     (SELECT dataNode FROM cslogcurve_datanode s1 WHERE logCurveInfoUID = 'W-12B-01f34a-lci-2' AND s1.baseNodeDouble = t.baseNodeDouble) AS R12,
     (SELECT dataNode FROM cslogcurve_datanode s1 WHERE logCurveInfoUID = 'W-12B-01f34a-lci-20' AND s1.baseNodeDouble = t.baseNodeDouble) AS R13,
     (SELECT dataNode FROM cslogcurve_datanode s1 WHERE logCurveInfoUID = 'W-12B-01f34a-lci-21' AND s1.baseNodeDouble = t.baseNodeDouble) AS R14,
     (SELECT dataNode FROM cslogcurve_datanode s1 WHERE logCurveInfoUID = 'W-12B-01f34a-lci-3' AND s1.baseNodeDouble = t.baseNodeDouble) AS R15,
     (SELECT dataNode FROM cslogcurve_datanode s1 WHERE logCurveInfoUID = 'W-12B-01f34a-lci-4' AND s1.baseNodeDouble = t.baseNodeDouble) AS R16,
     (SELECT dataNode FROM cslogcurve_datanode s1 WHERE logCurveInfoUID = 'W-12B-01f34a-lci-5' AND s1.baseNodeDouble = t.baseNodeDouble) AS R17,
     (SELECT dataNode FROM cslogcurve_datanode s1 WHERE logCurveInfoUID = 'W-12B-01f34a-lci-6' AND s1.baseNodeDouble = t.baseNodeDouble) AS R18,
     (SELECT dataNode FROM cslogcurve_datanode s1 WHERE logCurveInfoUID = 'W-12B-01f34a-lci-7' AND s1.baseNodeDouble = t.baseNodeDouble) AS R19,
     (SELECT dataNode FROM cslogcurve_datanode s1 WHERE logCurveInfoUID = 'W-12B-01f34a-lci-8' AND s1.baseNodeDouble = t.baseNodeDouble) AS R20,
     (SELECT dataNode FROM cslogcurve_datanode s1 WHERE logCurveInfoUID = 'W-12B-01f34a-lci-9' AND s1.baseNodeDouble = t.baseNodeDouble) AS R21 
  FROM cslogcurve_datanode t ORDER BY R1 ASC
4

1 に答える 1

5

IN代わりに節を使用してください。
構文：

SELECT DISTINCT <COLUMN> 
FROM <TABLE> 
WHERE <COLUMN> IN (<VALUE1>,<VALUE2>,...) 
ORDER BY <COLUMN>;

したがって、クエリは次のようになります。

SELECT DISTINCT dataNode 
FROM cslogcurve_datanode 
WHERE logCurveInfoUID IN ('W-12B-01f34a-lci-1', 'W-12B-01f34a-lci-10'
                         ,'W-12B-01f34a-lci-11','W-12B-01f34a-lci-12'
                         ,'W-12B-01f34a-lci-13',....)
ORDER BY dataNode ASC;
于 2012-09-16T04:40:30.173 に答える