WHEN
caseステートメントのそれぞれを独自の列に出力することは可能ですか?私はそれを試しましたが、運がありませんでした。私が欲しいものに最も近いのは以下です。
現在、次のようなクエリがあります。
select BH.BATCH as batch_number,
BS.TBS_DESCRIPTION as batch_description,
BH.NUM_VOUCHERS as "NUM_VOUCHERS(BATCH)",
case when VS.TVS_CODE = 1 then count(*) else 0 end as in_stock,
case when VS.TVS_CODE = 3 then count(*) else 0 end as terminate,
case when VS.TVS_CODE = 5 then count(*) else 0 end as in_progress,
case when VS.TVS_CODE = 6 then count(*) else 0 end as used,
case when VS.TVS_CODE = 8 then count(*) else 0 end as deactivate
from BATCH_HIST bh,
BATCH_STATUS bs,
VOUCH_HIST vh,
VOUCH_STATUS vs
where substr(BH.ALLOCAT_DATE, 1, 6) = 201207
and to_char(BH.STATUS) = BS.TBS_CODE
and BH.BATCH = VH.BATCH
and to_char(VH.STATUS) = VS.TVS_CODE
group by BH.BATCH,
BS.TBS_DESCRIPTION,
BH.NUM_VOUCHERS,
VS.TVS_CODE
order by 1,2,3;
STATUS
これにより、それぞれが異なるレコードとして、次の出力が得られます。
BATCH_NUMBER | BATCH_DESCRIPTION | NUM_VOUCHERS(BATCH) | IN_STOCK | TERMINATE | IN_PROGRESS | USED | DEACTIVATE
------------------------------------------------------------------------------------------------------------------------------
4413565 | Allocate | 100 | 67 | 0 | 0 | 0 | 0
4413565 | Allocate | 100 | 0 | 0 | 0 | 33 | 0
4413566 | Allocate | 100 | 63 | 0 | 0 | 0 | 0
4413566 | Allocate | 100 | 0 | 0 | 0 | 37 | 0
これをグループ化して、次のレコードごとに1つのレコードが存在するようにしBATCH_NUMBER
ます。
BATCH_NUMBER | BATCH_DESCRIPTION | NUM_VOUCHERS(BATCH) | IN_STOCK | TERMINATE | IN_PROGRESS | USED | DEACTIVATE
------------------------------------------------------------------------------------------------------------------------------
4413565 | Allocate | 100 | 67 | 0 | 0 | 33 | 0
4413566 | Allocate | 100 | 63 | 0 | 0 | 37 | 0