http - Tomcat が http 応答コード 400 を返す

Question

私は長い間グーグルで調べていましたが、まだ私のケースの解決策を見つけることができません.

私のTomcatは時々例外を返します:

Error in postRequest(): Server returned HTTP response code: 400 for URL: http://localhost:80/CITIUS2/webresources/entities.personainterna/

うまくいくこともあれば、この例外を返すこともあるので、何が原因なのか本当にわかりません...

接続機能:

public static String excutePost(String targetURL, String urlParameters) throws UnsupportedEncodingException {

    URL url;
    HttpURLConnection connection = null;
    String responseXML = null;

    try {
        //Create connection
        url = new URL(targetURL);
        connection = (HttpURLConnection) url.openConnection();
        byte[] requestXML = urlParameters.getBytes();

        connection.setRequestProperty("Content-Length", String.valueOf(requestXML.length));
        connection.setRequestProperty("Content-Type", "application/xml; charset=utf-8");


        connection.setRequestMethod("POST");

        connection.setDoOutput(true);
        connection.setDoInput(true);

        // Send the String that was read into postByte.
        OutputStream out = connection.getOutputStream();
        out.write(requestXML);
        out.close();

        // Read the response and write it to standard out.
        InputStreamReader isr = new InputStreamReader(connection.getInputStream());
        BufferedReader br = new BufferedReader(isr);
        String temp;
        String tempResponse = "";

        //Create a string using response from web services
        while ((temp = br.readLine()) != null) {
            tempResponse = tempResponse + temp;
        }
        responseXML = tempResponse;
        br.close();
        isr.close();
    } catch (java.net.MalformedURLException e) {
        System.out.println("Error in postRequest(): Secure Service Required");
    } catch (Exception e) {
        System.out.println("Error in postRequest(): " + e.getMessage());
    }
    return responseXML;
}

@ 編集：

通常、ビルドは成功し、エラーはありません。Apache Tomcat の出力ウィンドウには、これだけが表示されます。

残りの方法:

@POST
@Consumes({"application/xml", "application/json"})
public Response create(Personainterna entity) {
    try {
        getJpaController().create(entity);
        return Response.created(URI.create(entity.getPersonaId().toString())).build();
    } catch (Exception ex) {
        return Response.notModified(ex.getMessage()).build();
    }
}