これは役に立ちますか
DECLARE @t TABLE(ID INT IDENTITY,String VARCHAR(100))
INSERT INTO @t
SELECT 'Honorificabcdwert' UNION ALL
SELECT 'AbCdEfxy' UNION ALL
SELECT 'abc1234defg' UNION ALL
SELECT 'XYZABCPPCKLMIDBABC' UNION ALL
SELECT 'MNOP$%^&~()MNOPQRS;:'
SELECT ID, OriginalString,Sequence
FROM (SELECT ID, REPLACE(string,'%','') AS Sequence,OriginalString,
ROW_NUMBER() OVER(PARTITION BY ID ORDER BY LEN(string) DESC, string) AS rn
FROM (SELECT OriginalString = b.String, CASE WHEN b.String LIKE a.strings THEN a.strings ELSE NULL END AS string,
b.ID, ROW_NUMBER() OVER(PARTITION BY ID ORDER BY LEN(strings) DESC, strings) AS rn
FROM (SELECT COALESCE('%' + b.strings+a.strings + '%','%' + a.strings + '%') AS strings
FROM (SELECT SUBSTRING('ABCDEFGHIJKLMNOPQRSTUVWXYZ',t1.N,t2.N-t1.N+1) AS strings, t1.N
FROM (VALUES(1),(2),(3),(4),(5),(6),(7),(8),
(9),(10),(11),(12),(13),(14),(15),
(16),(17),(18),(19),(20),(21),(22),
(23),(24),(25),(26)) t1(N)
CROSS JOIN (VALUES(1),(2),(3),(4),(5),(6),(7),(8),
(9),(10),(11),(12),(13),(14),(15),
(16),(17),(18),(19),(20),(21),(22),
(23),(24),(25),(26)) t2(N)
WHERE t1.N <= t2.N) a
LEFT OUTER JOIN (SELECT REVERSE(SUBSTRING('ZYXWVUTSRQPONMLKJIHGFEDCBA',1,N)) AS strings, 1 AS ID
FROM (VALUES(1),(2),(3),(4),(5),(6),(7),(8),
(9),(10),(11),(12),(13),(14),(15),
(16),(17),(18),(19),(20),(21),(22),
(23),(24),(25),(26)) t1(N)
UNION ALL SELECT '', 1) b ON a.N = b.ID) a
CROSS JOIN @t b) a ) a
WHERE a.rn = 1
ORDER BY a.ID
結果
ID OriginalString Sequence
1 Honorificabcdwert ABCD
2 AbCdEfxy ABCDEF
3 abc1234defg DEFG
4 XYZABCPPCKLMIDBABC XYZABC
5 MNOP$%^&~()MNOPQRS;: MNOPQRS
@Martin Smithとの話し合いの過程で提供された入力に基づいて、プログラムが開発されています。それをテストして、それがあなたの要件を満たしているかどうか私に知らせてください。