5

IDが2のオブジェクトを（次の配列で）見つけて、それを配列の先頭に移動するある種の関数を実行しようとしています。元の配列は次のとおりです。

Array
(
    [0] => stdClass Object
        (
            [id] => 177
            [startdate] => 2014-08-02
        )

    [1] => stdClass Object
        (
            [id] => 178
            [startdate] => 2014-08-02
        )

    [2] => stdClass Object
        (
            [id] => 2
            [startdate] => 2014-07-28
        )

    [3] => stdClass Object
        (
            [id] => 82
            [startdate] => 2014-07-28

        )

    [4] => stdClass Object
        (
            [id] => 199
            [startdate] => 2013-10-10
        )
)

そして、ここに出力したいものがあります（移動した配列アイテムを使用）：

Array
(

    [0] => stdClass Object
        (
            [id] => 2
            [startdate] => 2014-07-28
        )
    [1] => stdClass Object
        (
            [id] => 177
            [startdate] => 2014-08-02
        )

    [2] => stdClass Object
        (
            [id] => 178
            [startdate] => 2014-08-02
        )

    [3] => stdClass Object
        (
            [id] => 82
            [startdate] => 2014-07-28

        )

    [4] => stdClass Object
        (
            [id] => 199
            [startdate] => 2013-10-10
        )
)

どんな助けでも大歓迎です。

4

1 に答える 1

12 
function customShift($array, $id){
    foreach($array as $key => $val){     // loop all elements
        if($val->id == $id){             // check for id $id
            unset($array[$key]);         // unset the $array with id $id
            array_unshift($array, $val); // unshift the array with $val to push in the beginning of array
            return $array;               // return new $array
        }
    }
}

print_r(customShift($data, 2));
于 2012-09-24T06:34:01.040 に答える