SELECT MAX( t.valuesum ) AS total, t.codebook
FROM (
SELECT SUM( value ) AS valuesum, codebook
FROM stock
GROUP BY codebook
) t
GROUP BY t.codebook
サブクエリでは、出力は次のとおりです。
b001 35,
b002 20,
b0003 11
見たいのは: b001 35. 助けてください。
条件を使用した最初のソリューションwhere
:
SELECT t1.valuesum, t1.codebook
FROM (
SELECT SUM( s.value ) AS valuesum, s.codebook
FROM stock s
GROUP BY s.codebook
) t1
WHERE t1.valuesum in (SELECT MAX( t2.valuesum ) AS total
FROM (
SELECT SUM( s2.value ) AS valuesum, s2.codebook
FROM stock s2
GROUP BY s2.codebook
)t2
)
条件を使用した2番目のソリューションhaving
:
SELECT max(t1.valuesum), t1.codebook
FROM (
SELECT SUM( s.value ) AS valuesum, s.codebook
FROM stock s
GROUP BY s.codebook
) t1
GROUP BY t1.codebook
HAVING max(t1.valuesum) = (SELECT MAX( t2.valuesum ) AS total
FROM (
SELECT SUM( s2.value ) AS valuesum, s2.codebook
FROM stock s2
GROUP BY s2.codebook
)t2
)
これを試して
SELECT SUM( value ) AS valuesum, codebook
FROM stock
GROUP BY codebook
ORDER BY valuesum DESC
LIMIT 1
(コメントとエラー メッセージから) MySQL を使用していると仮定すると、次のようになります。
SELECT SUM( value ) AS valuesum, codebook
FROM stock
GROUP BY codebook
ORDER BY valuesum DESC
LIMIT 1 ;
これを試して
SELECT TOP 1 * FROM
(
SELECT SUM([value]) AS valuesum, codebook
FROM stock
GROUP BY codebook
)
ORDER BY valuesum DESC