3

私はこのデータの表を持っています：

+-----+-----------+------------------------------------+---------+
| ID  | post_type | name                               | term_id |
+-----+-----------+------------------------------------+---------+
| 278 | supplier  | Heating                            |      15 |
| 282 | supplier  | Central Heating                    |      16 |
| 278 | supplier  | Biomass                            |      17 |
| 278 | supplier  | Ground Source Heat Pumps           |      18 |
| 278 | supplier  | Passive Solar                      |      19 |
| 282 | supplier  | Air Source Heat Pumps              |      21 |
| 278 | supplier  | Air Conditioning                   |      22 |
| 278 | supplier  | Boilers                            |      23 |
| 277 | supplier  | Lighting                           |      25 |
| 277 | supplier  | LED's                              |      26 |
| 282 | supplier  | Halogen                            |      28 |
| 277 | supplier  | CFL                                |      29 |
| 282 | supplier  | Sustainable Construction Materials |      31 |
| 282 | supplier  | Plaster                            |      33 |
| 282 | supplier  | Floors                             |      37 |
| 282 | supplier  | Water                              |      38 |
| 282 | supplier  | Showers & Baths                |      43 |
| 278 | supplier  | Cooling                            |      44 |
| 278 | supplier  | Refrigeration                      |      46 |
| 282 | supplier  | Passive Design                     |      47 |
| 278 | supplier  | Chillers                           |      48 |
| 282 | supplier  | Renewable Energy                   |      49 |
| 282 | supplier  | Air Source Heat Pumps              |      53 |
| 282 | supplier  | Biomass Heating                    |      55 |
| 282 | supplier  | Biofuels                           |      57 |
| 282 | supplier  | Insulation                         |      61 |
| 282 | supplier  | Wall                               |      63 |
| 282 | supplier  | Floor                              |      64 |
| 282 | supplier  | Draught Proofing                   |      65 |
| 282 | supplier  | Energy Efficiency                  |      70 |
| 282 | supplier  | Gas Boiler Management Systems      |      71 |
| 282 | supplier  | Low Energy Lighting                |      72 |
| 282 | supplier  | Voltage Control                    |      73 |
| 282 | supplier  | Smart Meters                       |      74 |
| 282 | supplier  | Electric Heating                   |      75 |
+-----+-----------+------------------------------------+---------+

また、指定された（ワイルドカード文字列）と（整数）IDの両方に適用されるのリストを抽出する必要があります。したがって、たとえば、を返す必要があるaと...を持つsを検索します。nameterm_idIDname LIKE '%Lighting%'term_id = 26ID 277

次のクエリは機能しますが、きれいではありません。

SELECT a.ID, d.name, d.term_id
FROM cn_posts AS a
INNER JOIN cn_postmeta AS b ON a.ID = b.post_id
INNER JOIN cn_term_relationships AS c ON a.ID = c.object_id
INNER JOIN cn_terms AS d ON c.term_taxonomy_id = d.term_id
WHERE a.post_status = 'publish'
AND d.name LIKE '%Lighting%'
AND a.ID IN (
    SELECT a.ID
    FROM cn_posts AS a
    INNER JOIN cn_postmeta AS b ON a.ID = b.post_id
    INNER JOIN cn_term_relationships AS c ON a.ID = c.object_id
    INNER JOIN cn_terms AS d ON c.term_taxonomy_id = d.term_id
    WHERE d.term_id = '26'
)
GROUP BY a.ID

次のクエリを試しましたが、すべて結果が返されません。

SELECT DISTINCT a.ID, d.name, d.term_id
FROM cn_posts AS a
LEFT JOIN cn_postmeta AS b ON a.ID = b.post_id
LEFT JOIN cn_term_relationships AS c ON a.ID = c.object_id
LEFT JOIN cn_terms AS d ON c.term_taxonomy_id = d.term_id
WHERE a.post_status = 'publish'
AND d.name LIKE '%Lighting%'
AND d.term_id = '26'

SELECT a.ID, d.name, d.term_id, a.post_status
FROM cn_posts AS a
JOIN cn_postmeta AS b ON a.ID = b.post_id
JOIN cn_term_relationships AS c ON a.ID = c.object_id 
JOIN cn_terms AS d ON c.term_taxonomy_id = d.term_id
WHERE a.post_status = 'publish'
AND d.name LIKE '%Lighting%'
AND d.term_id = '26'
GROUP BY a.ID

これらは両方とも投稿を返します：

SELECT a.ID, d.name, d.term_id, a.post_status
FROM cn_posts AS a
JOIN cn_postmeta AS b ON a.ID = b.post_id
JOIN cn_term_relationships AS c ON a.ID = c.object_id 
JOIN cn_terms AS d ON c.term_taxonomy_id = d.term_id
WHERE a.post_status = 'publish'
AND d.name LIKE '%Lighting%'

SELECT a.ID, d.name, d.term_id, a.post_status
FROM cn_posts AS a
JOIN cn_postmeta AS b ON a.ID = b.post_id
JOIN cn_term_relationships AS c ON a.ID = c.object_id 
JOIN cn_terms AS d ON c.term_taxonomy_id = d.term_id
WHERE a.post_status = 'publish'
AND d.term_id = '26'

しかし、名前とterm_idの両方をクエリに含めると、何も返されませんか？

4

6 に答える 6

1

明らかに、テーブル（データサンプル）の単一の行がの条件に一致することはありませんd.name LIKE '%Lighting%' AND d.term_id = '26'。最初の部分に一致する行と2番目の部分に一致する行がありますが、両方に一致する行はありません。ただし、行のグループID = 277として取得した場合、は条件に一致します。したがって、グループ化を導入し、HAVING句で、わずかに変更されていますが、次のように条件を適用する必要があります。

SELECT a.ID
FROM cn_posts AS a
INNER JOIN cn_postmeta AS b ON a.ID = b.post_id
INNER JOIN cn_term_relationships AS c ON a.ID = c.object_id
INNER JOIN cn_terms AS d ON c.term_taxonomy_id = d.term_id
WHERE a.post_status = 'publish'
GROUP BY a.ID
HAVING COUNT(d.name LIKE '%Lighting%' OR NULL) > 0
   AND COUNT(d.term_id = '26'         OR NULL) > 0
;

ただし、これは、同じクエリでIDのようなd.name、またはd.termIDと一緒に詳細を取得できないことを意味することに注意してください（ただし、この場合、他の列をプルすることは問題ありませんa）。問題を解決するために同じクエリで列を返すことが必須である場合は、必要なすべてのデータを取得dするほぼ同じクエリで、上記を派生テーブルとして使用する必要があります。その場合、派生テーブルは、IDのセットを両方の条件に一致するIDだけにフィルターする手段として使用されます。そして、そのメインクエリでは、次のように、2つの条件をではなく接続する必要があります。ORAND

SELECT a.ID, d.name, d.term_id
FROM cn_posts AS a
INNER JOIN cn_postmeta AS b ON a.ID = b.post_id
INNER JOIN cn_term_relationships AS c ON a.ID = c.object_id
INNER JOIN cn_terms AS d ON c.term_taxonomy_id = d.term_id
WHERE a.post_status = 'publish'
AND (d.name LIKE '%Lighting%' OR d.term_id = '26')
AND a.ID IN (
    /* the above query, now used just as a filter */
    SELECT a.ID
    FROM cn_posts AS a
    INNER JOIN cn_postmeta AS b ON a.ID = b.post_id
    INNER JOIN cn_term_relationships AS c ON a.ID = c.object_id
    INNER JOIN cn_terms AS d ON c.term_taxonomy_id = d.term_id
    WHERE a.post_status = 'publish'
    GROUP BY a.ID
    HAVING COUNT(d.name LIKE '%Lighting%' OR NULL) > 0
       AND COUNT(d.term_id = '26'         OR NULL) > 0
)
;

どうやら、これはあなたが最終的に作ったクエリよりも良いことはほとんどないでしょう。

于 2012-09-24T15:14:25.217 に答える
0

これを試しましたか？

SELECT a.ID, d.name, d.term_id
FROM cn_posts AS a
INNER JOIN cn_postmeta AS b ON a.ID = b.post_id
INNER JOIN cn_term_relationships AS c ON a.ID = c.object_id 
INNER JOIN cn_terms AS d ON c.term_taxonomy_id = d.term_id
WHERE a.post_status = 'publish'
AND d.name LIKE '%Lighting%'
AND d.term_id = '28'
GROUP BY a.ID
于 2012-09-24T11:26:10.920 に答える
0 
SELECT a.ID, d.name, d.term_id, a.post_status
FROM wp_posts AS a
JOIN wp_postmeta AS b ON a.ID = b.post_id
JOIN wp_term_relationships AS c ON a.ID = c.object_id 
JOIN wp_terms AS d ON c.term_taxonomy_id = d.term_id
WHERE a.post_status = 'publish'
AND d.name LIKE '%Halogen%'
AND d.term_id = '25'
GROUP BY a.ID
于 2012-09-24T11:29:33.257 に答える
0

この単純な選択はあなたが必要とするものをしません。

select ID, name, term_id from yourtable where name LIKE '%Lighting%' and a term_id = 26
于 2012-09-24T13:27:53.200 に答える
0

結局のところ、みんなの助けを借りて（ありがとうございました!!）私はこのクエリを使用することになりました。これは最もクリーンではありませんでしたが、私が求めていた結果を得た唯一のクエリであり、仕事を動かす必要がありました。

また、投稿のタイトルと説明、およびサービス名のキーワードと一致します。

SELECT a.ID, a.post_title, a.post_status, d.name, d.term_id
FROM cn_posts AS a
JOIN cn_postmeta AS b ON a.ID = b.post_id
JOIN cn_term_relationships AS c ON a.ID = c.object_id
JOIN cn_terms AS d ON c.term_taxonomy_id = d.term_id
WHERE a.post_status = 'publish'
AND ( a.post_title LIKE '%Lighting%' OR a.post_content LIKE '%Lighting%' OR d.name LIKE '%Lighting%' )
AND a.ID IN (
    SELECT a.ID FROM cn_posts AS a
    INNER JOIN cn_postmeta AS b ON a.ID = b.post_id
    INNER JOIN cn_term_relationships AS c ON a.ID = c.object_id
    INNER JOIN cn_terms AS d ON c.term_taxonomy_id = d.term_id
    WHERE d.term_id = '26' )
GROUP BY a.ID

どうもありがとうございました。明らかに、他のクエリが機能しなかった理由を理解できる場合、またはこのクエリをクリーンアップできる場合は、遠慮なく返信してください。

デイブ

于 2012-09-24T14:24:34.960 に答える
0 
SELECT a.ID, d.name, d.term_id 
FROM cn_posts AS a 
INNER JOIN cn_postmeta AS b ON a.ID = b.post_id 
INNER JOIN cn_term_relationships AS c ON a.ID = c.object_id 
INNER JOIN cn_terms AS d ON c.term_taxonomy_id = d.term_id 
INNER JOIN cn_terms AS d2 ON c.term_taxonomy_id = d2.term_id 
WHERE a.post_status = 'publish' 
AND d.name LIKE '%Lighting%' 
AND d2.term_id = '26'

条件が異なる行にあるため、cn_termsに2回参加する必要があります。

于 2012-09-24T14:31:00.800 に答える