2

私はEclipselink v2.3.3を使用しています

このエラーが発生しています

Error compiling the query [Credential.updateExistingCredentialNoPW: UPDATE Credential c SET c.active = :active, c.employee.address.streetAddress = :stadd, c.employee.address.city = :city, c.employee.address.province = :prov, c.employee.address.zip = :zip WHERE c.id = :id], line 1, column 46: invalid navigation expression [c.employee], cannot navigate association field [employee] in the SET clause target.

コードを実行しようとすると。

コードの実行を妨げる影響を受ける名前付きクエリは次のとおりです

@NamedQuery(name = "Credential.updateExistingCredentialNoPW",
query = "UPDATE Credential c "
+ "SET c.active = :active, "
+ "c.employee.address.streetAddress = :stadd, "
+ "c.employee.address.city = :city, "
+ "c.employee.address.province = :prov, "
+ "c.employee.address.zip = :zip "
+ "WHERE c.id = :id"),

@NamedQuery(name = "Credential.updateExistingCredential",
query = "UPDATE Credential c "
+ "SET c.password = :pw, "
+ "c.active = :active, "
+ "c.employee.address.streetAddress = :stadd, "
+ "c.employee.address.city = :city, "
+ "c.employee.address.province = :prov, "
+ "c.employee.address.zip = :zip "
+ "WHERE c.id = :id"),

@NamedQuery(name = "Credential.updateSalary",
query = "UPDATE Credential c "
+ "SET c.employee.salary.value = :val WHERE c.id = :id")

上記で指定したすべての名前付きクエリを配置するクラスは次のとおりです

public class Credential implements Serializable {

private static final long serialVersionUID = 1L;
@Id
@GeneratedValue(generator = "CRED_GEN", strategy = GenerationType.IDENTITY)
@Column(name = "CREDENTIAL_ID")
private long id;
// unique & not nullabe username
@Column(nullable = false, unique = true)
private String username;
@Column(nullable = false, name = "USER_KEY")
private String password;
@Column(nullable = false)
private boolean active;
@Column(nullable = false)
private int userLevel;
@OneToOne(cascade = CascadeType.PERSIST, fetch = FetchType.EAGER)
private Employee employee;

public Credential() {
}

public Credential(String username, String password, boolean active,
        int userLevel, Employee employee) throws NoSuchAlgorithmException {
    this.username = username;
    this.setPassword(password);
    this.active = active;
    this.userLevel = userLevel;
    this.employee = employee;
}

public long getId() {
    return id;
}

public void setId(long id) {
    this.id = id;
}

public int getUserLevel() {
    return userLevel;
}

public void setUserLevel(int userLevel) {
    this.userLevel = userLevel;
}

public boolean isActive() {
    return active;
}

public void setActive(boolean active) {
    this.active = active;
}

public Employee getEmployee() {
    return employee;
}

public void setEmployee(Employee employee) {
    this.employee = employee;
}

public String getPassword() {
    return password;
}

public void setPassword(String password) throws NoSuchAlgorithmException {
    this.password = Cryptography.getHash(password);
}

public String getUsername() {
    return username;
}

public void setUsername(String username) {
    this.username = username;
}

私はそれを間違っていますか？

4

2 に答える 2

0

単一の SQL クエリで複数のテーブルを更新することはできません。

https://forums.oracle.com/forums/thread.jspa?threadID=2223393を参照してください。

したがって、Eclipselinkでも不可能です。

これを 2 つのクエリに分割するか、セッターを使用することをお勧めします。

于 2012-09-26T05:58:22.293 に答える
0

できません。SQL クエリを使用するか、Java コードを使用します。

Credential c = em.find(Credential.class, credentialId);
c.setActive(active);
c.getEmployee().getAddress().setStreet(street);
...
于 2012-09-26T05:58:53.743 に答える