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データベースからすべてのドメインを取得して表に表示するページを作成しました。ページネーションは、1 ページあたり 1002 ドメインを表示するように設定されており、テーブルは 3 列である必要があります。

何をすべきかわからない場合は、「Row Test1」と「Row Test1」が表示される最後の方です。これらはページに正しく表示されます。ただし、それらを表示する代わりに、データベースから実際にドメインを表示するにはどうすればよいですか。

誰かがコードの固定部分の例を投稿できれば、それは非常に高く評価されます。私は非常に多くのことを試してきたように感じ、少し混乱しています。

コード全体は次のとおりです。

<?php include("header.html"); ?>

<center>
<?php
    /*
        Place code to connect to your DB here.
    */
    include('database.php');    // include your code to connect to DB.

    $tbl_name="list";       //your table name
    // How many adjacent pages should be shown on each side?
    $adjacents = 3;

    /* 
       First get total number of rows in data table. 
       If you have a WHERE clause in your query, make sure you mirror it here.
    */
    $query = "SELECT COUNT(*) as num FROM $tbl_name";
    $total_pages = mysql_fetch_array(mysql_query($query));
    $total_pages = $total_pages[num];

    /* Setup vars for query. */
    $targetpage = "index.php";  //your file name  (the name of this file)
    $limit = 1002;                              //how many items to show per page
    $page = $_GET['page'];
    if($page) 
        $start = ($page - 1) * $limit;          //first item to display on this page
    else
        $start = 0;                             //if no page var is given, set start to 0

    /* Get data. */
    $sql = "SELECT website FROM $tbl_name LIMIT $start, $limit";
    $result = mysql_query($sql);

    /* Setup page vars for display. */
    if ($page == 0) $page = 1;                  //if no page var is given, default to 1.
    $prev = $page - 1;                          //previous page is page - 1
    $next = $page + 1;                          //next page is page + 1
    $lastpage = ceil($total_pages/$limit);      //lastpage is = total pages / items per page, rounded up.
    $lpm1 = $lastpage - 1;                      //last page minus 1

    /* 
        Now we apply our rules and draw the pagination object. 
        We're actually saving the code to a variable in case we want to draw it more than once.
    */
    $pagination = "";
    if($lastpage > 1)
    {   
        $pagination .= "<div class=\"pagination2\">";
        //previous button
        if ($page > 1) 
            $pagination.= "<a href=\"$targetpage?page=$prev\">&lt; previous</a>";
        else
            $pagination.= "<span class=\"disabled\">&lt; previous</span>";  

        //pages 
        if ($lastpage < 7 + ($adjacents * 2))   //not enough pages to bother breaking it up
        {   
            for ($counter = 1; $counter <= $lastpage; $counter++)
            {
                if ($counter == $page)
                    $pagination.= "<span class=\"current\">$counter</span>";
                else
                    $pagination.= "<a href=\"$targetpage?page=$counter\">$counter</a>";                 
            }
        }
        elseif($lastpage > 5 + ($adjacents * 2))    //enough pages to hide some
        {
            //close to beginning; only hide later pages
            if($page < 1 + ($adjacents * 2))        
            {
                for ($counter = 1; $counter < 4 + ($adjacents * 2); $counter++)
                {
                    if ($counter == $page)
                        $pagination.= "<span class=\"current\">$counter</span>";
                    else
                        $pagination.= "<a href=\"$targetpage?page=$counter\">$counter</a>";                 
                }
                $pagination.= "...";
                $pagination.= "<a href=\"$targetpage?page=$lpm1\">$lpm1</a>";
                $pagination.= "<a href=\"$targetpage?page=$lastpage\">$lastpage</a>";       
            }
            //in middle; hide some front and some back
            elseif($lastpage - ($adjacents * 2) > $page && $page > ($adjacents * 2))
            {
                $pagination.= "<a href=\"$targetpage?page=1\">1</a>";
                $pagination.= "<a href=\"$targetpage?page=2\">2</a>";
                $pagination.= "...";
                for ($counter = $page - $adjacents; $counter <= $page + $adjacents; $counter++)
                {
                    if ($counter == $page)
                        $pagination.= "<span class=\"current\">$counter</span>";
                    else
                        $pagination.= "<a href=\"$targetpage?page=$counter\">$counter</a>";                 
                }
                $pagination.= "...";
                $pagination.= "<a href=\"$targetpage?page=$lpm1\">$lpm1</a>";
                $pagination.= "<a href=\"$targetpage?page=$lastpage\">$lastpage</a>";       
            }
            //close to end; only hide early pages
            else
            {
                $pagination.= "<a href=\"$targetpage?page=1\">1</a>";
                $pagination.= "<a href=\"$targetpage?page=2\">2</a>";
                $pagination.= "...";
                for ($counter = $lastpage - (2 + ($adjacents * 2)); $counter <= $lastpage; $counter++)
                {
                    if ($counter == $page)
                        $pagination.= "<span class=\"current\">$counter</span>";
                    else
                        $pagination.= "<a href=\"$targetpage?page=$counter\">$counter</a>";                 
                }
            }
        }

        //next button
        if ($page < $counter - 1) 
            $pagination.= "<a href=\"$targetpage?page=$next\">next &gt;</a>";
        else
            $pagination.= "<span class=\"disabled\">next &gt;</span>";
        $pagination.= "</div>\n";       
    }
?>

    <?php
$i = 0;
echo '<table><tr>'; 
        while($row = mysql_fetch_array($result))
{
    $i ++;
    if ($i<=2)
    {
      echo '<td>
         <div>Row Test1</div>
       </td>'; 
    }

    else
    {       
      echo '</tr><tr>';
      echo '<td><div>Row Test2</div></td>'; 
      $i = 0;
   }
}  
echo '</tr></table>';
    ?>

<?=$pagination?>
</center>

<?php include("footer.html"); ?>
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1 に答える 1

0

while ステートメントで行の印刷を分割する必要がある理由が少しわかりません。while ステートメントは、ステートメントが true と評価される限り、1、20、またはなしのいずれであっても、すべての結果を出力します。

<?php
    $i = 0;
    echo '<table><tr>';
    while($row = mysql_fetch_array($result)) {
        $i ++;
        echo '<td><div>'.$row[databasecolumnnamethatcontainsurlgoeshere].'</div></td>';
    }  
    echo '</tr></table>';
?>
于 2012-09-29T21:21:56.647 に答える